---------- Forwarded message ---------
From: Michael Ossipoff email9648742@gmail.com
Date: Sat, Nov 4, 2023 at 10:33
Subject: Re: Some thoughts on Condorcet and Burial
To: Forest Simmons forest.simmons21@gmail.com
Sorry—I meant that CW wins that 1st comparison, against BF, & so CW then
goes against Bus. Bus wins.
SP is autodeterrent.
On Sat, Nov 4, 2023 at 10:29 Michael Ossipoff email9648742@gmail.com
wrote:
So that suggests that, for SP, agenda-ordered by Borda or implicit
approval, would, in the strategic top-cycle, start by comparing CW & BF.
BF wins that comparison, & goes against Bus.
Bus wins.
The burial is penalized.
The familiar, widely used & precedented SP is autodeterrent.
On Sat, Nov 4, 2023 at 10:20 Michael Ossipoff email9648742@gmail.com
wrote:
Referring to what I was saying about the order of the 3 too-cycle
candidates’ Borda or implicit approval:
I told why I claim that BF is the most likely one to be middle.
So what’s the most likely order for the top & bottom of that ordering?
Well, top & bottom are the most extreme difference in the ordering “. So,
isn’t that difference more likely to not contradict a pairwise defeat?
Together, those two facts suggest that the most likely order for the 3
candidates’ Borda or implicit approval is:
Bus>BF>CW.
On Fri, Nov 3, 2023 at 06:35 Forest Simmons forest.simmons21@gmail.com
wrote:
On Mon, Oct 30, 2023, 6:21 PM C.Benham cbenham@adam.com.au wrote:
Why do we support the Condorcet criterion? For me there are three
reasons:
(1) Failure to elect a voted CW can give the voters who voted the CW
over the actual winner
a potentially very strong, difficult (if not impossible ) to answer
complaint.
And those voters could be more than half the total.
(2) Always electing a voted CW is (among methods that fail Favorite
Betrayal) is the best way to minimise
Compromise incentive.
(3) Limited to the information we can glean for pure ranked ballots
(especially if we decide to only refer
to the pairwise matrix), the voted CW is the most likely utility
maximiser.
If there is no voted CW , then the winner should come from the Smith
set. Condorcet is just the logical
consequence of Smith and Clone Independence (specifically Clone-Winner).
Some methods are able to meet Condorcet but not Smith, but hopefully
they get something in return.
(For example I think Min Max Margins gets Mono-add-Top and maybe
something else).
So coming to the question of which individual member of the Smith set
should we elect, I don't see that a
supposed, guessed-at "sincere CW" has an especially strong claim,
certainly nothing compared to an actual
voted CW.
Suppose sincere looks like:
49 A>>>C>B
48 B>>>C>A
03 C>A>>>B
My favorite burial proof method is to elect the nemesis of the nemesis
of the (repeated) Submidway Approval Elimination winner.
Max Approval is 52
Min Approval is 3
Midway is 27.5
So we eliminate C.
Updating approvals we have 52 for A and 48 for B. Midway is 50. B is the
only Sub Midway candidate so A is the SubMidway Approval winner.
The nemesis of A is C, and C has no nemesis because it not pairbeaten.
We respect the Condorcet Criterion and elect C, a very weak CW.
There is no way out of it if we want a Condorcet Criterion Compliant
method.
Suppose that all voters get about the same utility from electing their
favourites. In that case A is the big utility
maximiser.
Now suppose that this is say the first post-FPP election, and the
voters are all exhorted to express their full
rankings, no matter how weak or uncertain some of their preferences may
be, because we don't want anything
that looks like the (shudder) "minority rule" we had under FPP.
This reminds me of the practice omanipulative judges in the US warning
jurors to ignore their sacred right of "Jury Nullification" (inherited from
English Common Law).
Those lying (by intimidation) judges are a disgrace to their office ...
and should be stripped of their holy robes ... imho.
So they vote:
49 A>C
48 B>C
03 C>A
C is the voted CW. For some pro-Condorcet zealots, this is ideal. No
sincere preferences were reversed or
"concealed", resulting in the election of the "sincere CW".
(In passing I note that in most places if the non-Condorcet method
IRV/RCV were used, A would be uncontroversially
elected probably without anyone even noticing that C is the CW.)
Backing up a bit, suppose that instead of the voters being exhorted to
fully rank no-matter-what, they are given the
message "this election is for a serious powerful office, so we don't
want anything like GIGO ("garbage in, garbage out")
so if some of your preferences are weak or uncertain it is quite ok to
keep them to yourself via truncation or equal-ranking."
That warning should be mandatory ... as should an honest effort to
"fully inform" a jury of their most sacred rights predatimg even the Magna
Carta.
So they vote:
49 A
48 B
03 C>A
Now the voted CW is A. Should anyone be seriously concerned that,
due to so many voters truncating, that some other
candidate might actually be the "sincere CW"?
Your example shows the wisdom of electing the ballot CW when there is
one.
In fact, all of our burial resistant methods elect the voted CW when one
exists. But when one does not exist we suspiciously suspect that its
absence was most likely caused by subversion of a CW, since that is by far
the easiest way to create a beat cycle ... whether innocently or with
"malice aforethought."
For me, if voters have the freedom to fully rank but for whatever
reason choose to truncate (and/or equal-rank, assuming that
is allowed) a lot of that is fine and the voting method should prefer
not to know about weak and uncertain preferences.
The type of insincere voting that most concerns me is that which
produces outrageous failure of Later-no-Help, achieving by order-reversal
Burial what could not have been done by simple truncation.
46 A
44 B>C (sincere is B or B>A)
10 C
Let's see what our Sub Midway Approval Elimination burial resistant
method does here:
The respective max and min implicit approval scores are 54 for C and 44
for B. So Midway is 49. Both A and B have Sub Midway Approval leaving C as
the candidate whose nemesis's nemesis we should elect.
C's nemesis is B, and B's nemesis is A.
So A is the winner of our burial resistant method.
How does this work?
Well, Nanson is very good at fingering the Burial Faction Favorite, but
Poor man's Nanson aka SubMidApproval Elimination is even better at electing
the BFF than ordinary Nanson or RP wv, although they are both pretty good
at it as this example shows.
Once you have the likely BFF you can follow the cycle forward one or
backward two candidates to the "bus" under which the buried candidate was
buried.
[Electing this "bus" is what makes the method backfire on the burying
faction ... so electing the strongest bus (their could be a clone set of
them) is the proper aim of a good burial proof method designer ... to
completely deter potential subverters from even flirting with the idea.]
Like I said you can go in either direction around the cycle to get to a
"bus" from the BFF candidate .... but it's better psychologically to elect
the syrongest wv defeater of the strongest wv defeater of the Nanson winner
.... as opposed to saying "Elect the candidate with the most losing votes
against the Nanson winner" .. they are almost always the same candidate
even when Smith has more than three members.
Like I say, SubMidAolroval Elimination is more reliable than even
ordinary Nanson or RP wv at finding the BFF candidate. But for the
curjous, you can always do a sincere runoff between the likely strongest
Bus (the nemesis of the nemesis of the likely BFF), and the Smith candidate
with the fewest losing votes against it (i.e.against the bus) the same as
the weakest Smith weakest Smith candidate to defeat the BFF.
[It is easy to show that a subverted CW always defeats the BFF, which
beats the bus that beat the buried candidate that precipitated the
insincere cycle resulting from the burial.]
In this example the sincere runoff (were that option to be taken) would
be between the Bus A and the Smith candidate B with the fewest losing votes
to it A.
For the sincere winner of this runoff we have to go clear back to the
original scenario. And it turns out that A is the sincere winner of the
runoff, because C, the sincere CW was acting more like a BFF ... so not a
finalist in the runoff!
Electing B here is completely unacceptable.
Right, and now we have a method designed to automatically avoid that
kind of mistake.
Regardless of whether or not the B>C voters are sincere, there isn't
any case that B has a stronger
claim than A.
I don't like (but it can sometimes be justified) a larger faction being
stung by a successful truncation Defection strategy of a smaller one, but
apart
from that I consider a lot of truncation to be normal, natural and
mostly desirable.
More later.
Chris Benham
Are the beatcycles that sometimes arise from expressed ballot preferences
... are these cycles more likely to arise from occasional inevitable
inconsistencies inherent in sincerely voted ballots? ... or from ballots
that reflect exaggerated preferences from attempts to improve the election
outcome over the one likely to result from honest, unexagerated ballots (?)
Should Condorcet methods be designed on the assumption that most ballot
cycles are sincere? .... or on the assumption that most are the result of
insincere ballots (?)
Some people think that the question is irrelevant ... that no matter the
answer, the best result will be obtained by assuming the sincerity of the
voted ballots. Others think healthy skepticism is necessary for optimal
results. What do you think?
In SP, if there are many candidates instead of only 3, causing Bus to
pairbeat CW, just replaces a possible CW win with a Bus win.
So, with only 3 candidates, or with many, SP is autodeterrent.
SP could be used as the Condorcet completion method, applied to the
top-cycle, for autodeterrence.
But plain SP, by itself, is autodeterrent too.
On Sat, Nov 4, 2023 at 10:40 Michael Ossipoff email9648742@gmail.com
wrote:
---------- Forwarded message ---------
From: Michael Ossipoff email9648742@gmail.com
Date: Sat, Nov 4, 2023 at 10:33
Subject: Re: Some thoughts on Condorcet and Burial
To: Forest Simmons forest.simmons21@gmail.com
Sorry—I meant that CW wins that 1st comparison, against BF, & so CW then
goes against Bus. Bus wins.
SP is autodeterrent.
On Sat, Nov 4, 2023 at 10:29 Michael Ossipoff email9648742@gmail.com
wrote:
So that suggests that, for SP, agenda-ordered by Borda or implicit
approval, would, in the strategic top-cycle, start by comparing CW & BF.
BF wins that comparison, & goes against Bus.
Bus wins.
The burial is penalized.
The familiar, widely used & precedented SP is autodeterrent.
On Sat, Nov 4, 2023 at 10:20 Michael Ossipoff email9648742@gmail.com
wrote:
Referring to what I was saying about the order of the 3 too-cycle
candidates’ Borda or implicit approval:
I told why I claim that BF is the most likely one to be middle.
So what’s the most likely order for the top & bottom of that ordering?
Well, top & bottom are the most extreme difference in the ordering “.
So, isn’t that difference more likely to not contradict a pairwise defeat?
Together, those two facts suggest that the most likely order for the 3
candidates’ Borda or implicit approval is:
Bus>BF>CW.
On Fri, Nov 3, 2023 at 06:35 Forest Simmons forest.simmons21@gmail.com
wrote:
On Mon, Oct 30, 2023, 6:21 PM C.Benham cbenham@adam.com.au wrote:
Why do we support the Condorcet criterion? For me there are three
reasons:
(1) Failure to elect a voted CW can give the voters who voted the CW
over the actual winner
a potentially very strong, difficult (if not impossible ) to answer
complaint.
And those voters could be more than half the total.
(2) Always electing a voted CW is (among methods that fail Favorite
Betrayal) is the best way to minimise
Compromise incentive.
(3) Limited to the information we can glean for pure ranked ballots
(especially if we decide to only refer
to the pairwise matrix), the voted CW is the most likely utility
maximiser.
If there is no voted CW , then the winner should come from the Smith
set. Condorcet is just the logical
consequence of Smith and Clone Independence (specifically
Clone-Winner).
Some methods are able to meet Condorcet but not Smith, but hopefully
they get something in return.
(For example I think Min Max Margins gets Mono-add-Top and maybe
something else).
So coming to the question of which individual member of the Smith set
should we elect, I don't see that a
supposed, guessed-at "sincere CW" has an especially strong claim,
certainly nothing compared to an actual
voted CW.
Suppose sincere looks like:
49 A>>>C>B
48 B>>>C>A
03 C>A>>>B
My favorite burial proof method is to elect the nemesis of the nemesis
of the (repeated) Submidway Approval Elimination winner.
Max Approval is 52
Min Approval is 3
Midway is 27.5
So we eliminate C.
Updating approvals we have 52 for A and 48 for B. Midway is 50. B is
the only Sub Midway candidate so A is the SubMidway Approval winner.
The nemesis of A is C, and C has no nemesis because it not pairbeaten.
We respect the Condorcet Criterion and elect C, a very weak CW.
There is no way out of it if we want a Condorcet Criterion Compliant
method.
Suppose that all voters get about the same utility from electing their
favourites. In that case A is the big utility
maximiser.
Now suppose that this is say the first post-FPP election, and the
voters are all exhorted to express their full
rankings, no matter how weak or uncertain some of their preferences
may be, because we don't want anything
that looks like the (shudder) "minority rule" we had under FPP.
This reminds me of the practice omanipulative judges in the US warning
jurors to ignore their sacred right of "Jury Nullification" (inherited from
English Common Law).
Those lying (by intimidation) judges are a disgrace to their office ...
and should be stripped of their holy robes ... imho.
So they vote:
49 A>C
48 B>C
03 C>A
C is the voted CW. For some pro-Condorcet zealots, this is ideal. No
sincere preferences were reversed or
"concealed", resulting in the election of the "sincere CW".
(In passing I note that in most places if the non-Condorcet method
IRV/RCV were used, A would be uncontroversially
elected probably without anyone even noticing that C is the CW.)
Backing up a bit, suppose that instead of the voters being exhorted to
fully rank no-matter-what, they are given the
message "this election is for a serious powerful office, so we don't
want anything like GIGO ("garbage in, garbage out")
so if some of your preferences are weak or uncertain it is quite ok to
keep them to yourself via truncation or equal-ranking."
That warning should be mandatory ... as should an honest effort to
"fully inform" a jury of their most sacred rights predatimg even the Magna
Carta.
So they vote:
49 A
48 B
03 C>A
Now the voted CW is A. Should anyone be seriously concerned that,
due to so many voters truncating, that some other
candidate might actually be the "sincere CW"?
Your example shows the wisdom of electing the ballot CW when there is
one.
In fact, all of our burial resistant methods elect the voted CW when
one exists. But when one does not exist we suspiciously suspect that its
absence was most likely caused by subversion of a CW, since that is by far
the easiest way to create a beat cycle ... whether innocently or with
"malice aforethought."
For me, if voters have the freedom to fully rank but for whatever
reason choose to truncate (and/or equal-rank, assuming that
is allowed) a lot of that is fine and the voting method should prefer
not to know about weak and uncertain preferences.
The type of insincere voting that most concerns me is that which
produces outrageous failure of Later-no-Help, achieving by order-reversal
Burial what could not have been done by simple truncation.
46 A
44 B>C (sincere is B or B>A)
10 C
Let's see what our Sub Midway Approval Elimination burial resistant
method does here:
The respective max and min implicit approval scores are 54 for C and 44
for B. So Midway is 49. Both A and B have Sub Midway Approval leaving C as
the candidate whose nemesis's nemesis we should elect.
C's nemesis is B, and B's nemesis is A.
So A is the winner of our burial resistant method.
How does this work?
Well, Nanson is very good at fingering the Burial Faction Favorite, but
Poor man's Nanson aka SubMidApproval Elimination is even better at electing
the BFF than ordinary Nanson or RP wv, although they are both pretty good
at it as this example shows.
Once you have the likely BFF you can follow the cycle forward one or
backward two candidates to the "bus" under which the buried candidate was
buried.
[Electing this "bus" is what makes the method backfire on the burying
faction ... so electing the strongest bus (their could be a clone set of
them) is the proper aim of a good burial proof method designer ... to
completely deter potential subverters from even flirting with the idea.]
Like I said you can go in either direction around the cycle to get to
a "bus" from the BFF candidate .... but it's better psychologically to
elect the syrongest wv defeater of the strongest wv defeater of the Nanson
winner .... as opposed to saying "Elect the candidate with the most losing
votes against the Nanson winner" .. they are almost always the same
candidate even when Smith has more than three members.
Like I say, SubMidAolroval Elimination is more reliable than even
ordinary Nanson or RP wv at finding the BFF candidate. But for the
curjous, you can always do a sincere runoff between the likely strongest
Bus (the nemesis of the nemesis of the likely BFF), and the Smith candidate
with the fewest losing votes against it (i.e.against the bus) the same as
the weakest Smith weakest Smith candidate to defeat the BFF.
[It is easy to show that a subverted CW always defeats the BFF, which
beats the bus that beat the buried candidate that precipitated the
insincere cycle resulting from the burial.]
In this example the sincere runoff (were that option to be taken) would
be between the Bus A and the Smith candidate B with the fewest losing votes
to it A.
For the sincere winner of this runoff we have to go clear back to the
original scenario. And it turns out that A is the sincere winner of the
runoff, because C, the sincere CW was acting more like a BFF ... so not a
finalist in the runoff!
Electing B here is completely unacceptable.
Right, and now we have a method designed to automatically avoid that
kind of mistake.
Regardless of whether or not the B>C voters are sincere, there isn't
any case that B has a stronger
claim than A.
I don't like (but it can sometimes be justified) a larger faction
being stung by a successful truncation Defection strategy of a smaller
one, but apart
from that I consider a lot of truncation to be normal, natural and
mostly desirable.
More later.
Chris Benham
Are the beatcycles that sometimes arise from expressed ballot preferences
... are these cycles more likely to arise from occasional inevitable
inconsistencies inherent in sincerely voted ballots? ... or from ballots
that reflect exaggerated preferences from attempts to improve the election
outcome over the one likely to result from honest, unexagerated ballots (?)
Should Condorcet methods be designed on the assumption that most ballot
cycles are sincere? .... or on the assumption that most are the result of
insincere ballots (?)
Some people think that the question is irrelevant ... that no matter the
answer, the best result will be obtained by assuming the sincerity of the
voted ballots. Others think healthy skepticism is necessary for optimal
results. What do you think?