DK
Daniel Kirslis
Thu, May 15, 2025 11:24 PM
Hello!
I am a newcomer to this mailing list, so please forgive me if this message
violates any norms or protocols that the members of this list adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and Condorcet. I
believe that it maintains the simplicity and mathematical elegance of the
Borda count while incorporating Condorcet's concern with pairwise
dominance. Intuitively, it can be understood as ordering candidates by how
close they come to being unanimously selected when plotted in Cartesian
coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you all
will take a look at the paper and share your comments, questions, and
critiques. Ultimately, it is my hope that ranked-choice voting advocates
can arrive at a consensus about the best method for RCV and thus strengthen
efforts to adopt it and deliver much needed democratic improvements. But
even if you don't find the system itself compelling, you may find the
method of plotting electoral outcomes elucidated in the paper to be useful
for the analysis of other electoral systems.
Thank you!
-Dan
Hello!
I am a newcomer to this mailing list, so please forgive me if this message
violates any norms or protocols that the members of this list adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and Condorcet. I
believe that it maintains the simplicity and mathematical elegance of the
Borda count while incorporating Condorcet's concern with pairwise
dominance. Intuitively, it can be understood as ordering candidates by how
close they come to being unanimously selected when plotted in Cartesian
coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you all
will take a look at the paper and share your comments, questions, and
critiques. Ultimately, it is my hope that ranked-choice voting advocates
can arrive at a consensus about the best method for RCV and thus strengthen
efforts to adopt it and deliver much needed democratic improvements. But
even if you don't find the system itself compelling, you may find the
method of plotting electoral outcomes elucidated in the paper to be useful
for the analysis of other electoral systems.
Thank you!
-Dan
CB
Chris Benham
Sat, May 17, 2025 12:00 PM
Dan,
I had a look at your paper and (probably partly due to my lack of
academic maths background) I found it almost completely opaque.
And the bits I do understand sound very unpromising. Why should we be
interested in the "concerns" of Borda (whatever they are)? And so much
that we should embrace a method that fails the Condorcet criterion?
Do you propose allowing above-bottom equal ranking or truncation?
Importantly, the K-count satisfies the ‘sincere favorite’ criterion: a
voter is
never incentivized to place their favorite candidate in any position
other than
1st. This is a particularly perverse form of strategic voting that the
K-count
avoids. Notably, it is not avoided by one of the most popular ranked
choice
methods, instant runoff.
That somewhat increases my interest in finding out how this method
works. Meeting that criterion is difficult for methods trying to be
better than simple Approval.
Who does your method elect in this example?
46 A
44 B>C
10 C
Chris Benham
On 16/05/2025 8:54 am, Daniel Kirslis via Election-Methods wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this
message violates any norms or protocols that the members of this list
adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and
Condorcet. I believe that it maintains the simplicity and mathematical
elegance of the Borda count while incorporating Condorcet's concern
with pairwise dominance. Intuitively, it can be understood as ordering
candidates by how close they come to being unanimously selected when
plotted in Cartesian coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you
all will take a look at the paper and share your comments, questions,
and critiques. Ultimately, it is my hope that ranked-choice voting
advocates can arrive at a consensus about the best method for RCV and
thus strengthen efforts to adopt it and deliver much needed democratic
improvements. But even if you don't find the system itself compelling,
you may find the method of plotting electoral outcomes elucidated in
the paper to be useful for the analysis of other electoral systems.
Thank you!
-Dan
Election-Methods mailing list - see https://electorama.com/em for list info
Dan,
I had a look at your paper and (probably partly due to my lack of
academic maths background) I found it almost completely opaque.
And the bits I do understand sound very unpromising. Why should we be
interested in the "concerns" of Borda (whatever they are)? And so much
that we should embrace a method that fails the Condorcet criterion?
Do you propose allowing above-bottom equal ranking or truncation?
> Importantly, the K-count satisfies the ‘sincere favorite’ criterion: a
> voter is
> never incentivized to place their favorite candidate in any position
> other than
> 1st. This is a particularly perverse form of strategic voting that the
> K-count
> avoids. Notably, it is not avoided by one of the most popular ranked
> choice
> methods, instant runoff.
That somewhat increases my interest in finding out how this method
works. Meeting that criterion is difficult for methods trying to be
better than simple Approval.
Who does your method elect in this example?
46 A
44 B>C
10 C
Chris Benham
On 16/05/2025 8:54 am, Daniel Kirslis via Election-Methods wrote:
> Hello!
>
> I am a newcomer to this mailing list, so please forgive me if this
> message violates any norms or protocols that the members of this list
> adhere to.
>
> I have recently developed a novel method for tabulating ranked-choice
> elections that attempts to reconcile the concerns of Borda and
> Condorcet. I believe that it maintains the simplicity and mathematical
> elegance of the Borda count while incorporating Condorcet's concern
> with pairwise dominance. Intuitively, it can be understood as ordering
> candidates by how close they come to being unanimously selected when
> plotted in Cartesian coordinate space. Here is a link to the paper:
> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>
> Given its simplicity, I have been very surprised to discover that this
> method has never been proposed before. I am hoping that some of you
> all will take a look at the paper and share your comments, questions,
> and critiques. Ultimately, it is my hope that ranked-choice voting
> advocates can arrive at a consensus about the best method for RCV and
> thus strengthen efforts to adopt it and deliver much needed democratic
> improvements. But even if you don't find the system itself compelling,
> you may find the method of plotting electoral outcomes elucidated in
> the paper to be useful for the analysis of other electoral systems.
>
> Thank you!
>
> -Dan
>
> ----
> Election-Methods mailing list - see https://electorama.com/em for list info
TP
Toby Pereira
Sat, May 17, 2025 2:00 PM
I think a basic summary in this list of how the method actually works would be good. Then we can read the paper with the background and arguments for it at our leisure.
Toby
On Saturday 17 May 2025 at 13:00:49 BST, Chris Benham via Election-Methods election-methods@lists.electorama.com wrote:
Dan,
I had a look at your paper and (probably partly due to my lack of
academic maths background) I found it almost completely opaque.
And the bits I do understand sound very unpromising. Why should we be
interested in the "concerns" of Borda (whatever they are)? And so much
that we should embrace a method that fails the Condorcet criterion?
Do you propose allowing above-bottom equal ranking or truncation?
Importantly, the K-count satisfies the ‘sincere favorite’ criterion: a
voter is
never incentivized to place their favorite candidate in any position
other than
1st. This is a particularly perverse form of strategic voting that the
K-count
avoids. Notably, it is not avoided by one of the most popular ranked
choice
methods, instant runoff.
That somewhat increases my interest in finding out how this method
works. Meeting that criterion is difficult for methods trying to be
better than simple Approval.
Who does your method elect in this example?
46 A
44 B>C
10 C
Chris Benham
On 16/05/2025 8:54 am, Daniel Kirslis via Election-Methods wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this
message violates any norms or protocols that the members of this list
adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and
Condorcet. I believe that it maintains the simplicity and mathematical
elegance of the Borda count while incorporating Condorcet's concern
with pairwise dominance. Intuitively, it can be understood as ordering
candidates by how close they come to being unanimously selected when
plotted in Cartesian coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you
all will take a look at the paper and share your comments, questions,
and critiques. Ultimately, it is my hope that ranked-choice voting
advocates can arrive at a consensus about the best method for RCV and
thus strengthen efforts to adopt it and deliver much needed democratic
improvements. But even if you don't find the system itself compelling,
you may find the method of plotting electoral outcomes elucidated in
the paper to be useful for the analysis of other electoral systems.
Thank you!
-Dan
Election-Methods mailing list - see https://electorama.com/em for list info
I think a basic summary in this list of how the method actually works would be good. Then we can read the paper with the background and arguments for it at our leisure.
Toby
On Saturday 17 May 2025 at 13:00:49 BST, Chris Benham via Election-Methods <election-methods@lists.electorama.com> wrote:
Dan,
I had a look at your paper and (probably partly due to my lack of
academic maths background) I found it almost completely opaque.
And the bits I do understand sound very unpromising. Why should we be
interested in the "concerns" of Borda (whatever they are)? And so much
that we should embrace a method that fails the Condorcet criterion?
Do you propose allowing above-bottom equal ranking or truncation?
> Importantly, the K-count satisfies the ‘sincere favorite’ criterion: a
> voter is
> never incentivized to place their favorite candidate in any position
> other than
> 1st. This is a particularly perverse form of strategic voting that the
> K-count
> avoids. Notably, it is not avoided by one of the most popular ranked
> choice
> methods, instant runoff.
That somewhat increases my interest in finding out how this method
works. Meeting that criterion is difficult for methods trying to be
better than simple Approval.
Who does your method elect in this example?
46 A
44 B>C
10 C
Chris Benham
On 16/05/2025 8:54 am, Daniel Kirslis via Election-Methods wrote:
> Hello!
>
> I am a newcomer to this mailing list, so please forgive me if this
> message violates any norms or protocols that the members of this list
> adhere to.
>
> I have recently developed a novel method for tabulating ranked-choice
> elections that attempts to reconcile the concerns of Borda and
> Condorcet. I believe that it maintains the simplicity and mathematical
> elegance of the Borda count while incorporating Condorcet's concern
> with pairwise dominance. Intuitively, it can be understood as ordering
> candidates by how close they come to being unanimously selected when
> plotted in Cartesian coordinate space. Here is a link to the paper:
> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>
> Given its simplicity, I have been very surprised to discover that this
> method has never been proposed before. I am hoping that some of you
> all will take a look at the paper and share your comments, questions,
> and critiques. Ultimately, it is my hope that ranked-choice voting
> advocates can arrive at a consensus about the best method for RCV and
> thus strengthen efforts to adopt it and deliver much needed democratic
> improvements. But even if you don't find the system itself compelling,
> you may find the method of plotting electoral outcomes elucidated in
> the paper to be useful for the analysis of other electoral systems.
>
> Thank you!
>
> -Dan
>
> ----
> Election-Methods mailing list - see https://electorama.com/em for list info
----
Election-Methods mailing list - see https://electorama.com/em for list info
AB
Andrew B Jennings (elections)
Sun, May 18, 2025 4:10 PM
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate with the smallest sum of SQUARES of non-victories (defeats plus ties) against their opponents.
Taking the square root and dividing can make it meaningful by scaling it to [0,1] or [0,s] (where s is the number of voters), but doesn't change the finish order.
It does seem like an interesting attempt to "square the circle" (great pun) and compromise between Borda and Condorcet. I hadn't realized that Borda and Minimax are minimizing the one-norm and infinity-norm in the same geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via Election-Methods election-methods@lists.electorama.com wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this message violates any norms or protocols that the members of this list adhere to.
I have recently developed a novel method for tabulating ranked-choice elections that attempts to reconcile the concerns of Borda and Condorcet. I believe that it maintains the simplicity and mathematical elegance of the Borda count while incorporating Condorcet's concern with pairwise dominance. Intuitively, it can be understood as ordering candidates by how close they come to being unanimously selected when plotted in Cartesian coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this method has never been proposed before. I am hoping that some of you all will take a look at the paper and share your comments, questions, and critiques. Ultimately, it is my hope that ranked-choice voting advocates can arrive at a consensus about the best method for RCV and thus strengthen efforts to adopt it and deliver much needed democratic improvements. But even if you don't find the system itself compelling, you may find the method of plotting electoral outcomes elucidated in the paper to be useful for the analysis of other electoral systems.
Thank you!
-Dan
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate with the smallest sum of SQUARES of non-victories (defeats plus ties) against their opponents.
Taking the square root and dividing can make it meaningful by scaling it to [0,1] or [0,s] (where s is the number of voters), but doesn't change the finish order.
It does seem like an interesting attempt to "square the circle" (great pun) and compromise between Borda and Condorcet. I hadn't realized that Borda and Minimax are minimizing the one-norm and infinity-norm in the same geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via Election-Methods <election-methods@lists.electorama.com> wrote:
> Hello!
>
> I am a newcomer to this mailing list, so please forgive me if this message violates any norms or protocols that the members of this list adhere to.
>
> I have recently developed a novel method for tabulating ranked-choice elections that attempts to reconcile the concerns of Borda and Condorcet. I believe that it maintains the simplicity and mathematical elegance of the Borda count while incorporating Condorcet's concern with pairwise dominance. Intuitively, it can be understood as ordering candidates by how close they come to being unanimously selected when plotted in Cartesian coordinate space. Here is a link to the paper:
> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>
> Given its simplicity, I have been very surprised to discover that this method has never been proposed before. I am hoping that some of you all will take a look at the paper and share your comments, questions, and critiques. Ultimately, it is my hope that ranked-choice voting advocates can arrive at a consensus about the best method for RCV and thus strengthen efforts to adopt it and deliver much needed democratic improvements. But even if you don't find the system itself compelling, you may find the method of plotting electoral outcomes elucidated in the paper to be useful for the analysis of other electoral systems.
>
> Thank you!
>
> -Dan
DK
Daniel Kirslis
Sun, May 18, 2025 5:51 PM
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
Andy - I really appreciate your feedback. Your summary is correct, and
your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
thinking about it that I had not considered. It seems like a potentially
fruitful lens for understanding it. And, as perhaps you have surmised, I
may have been mistaken in the statement about the sincere favorite
criteria, but I am working on an analysis of the issue that I will share.
Toby, making a short summary is a great suggestion. The argument in the
paper is admittedly a bit convoluted before it presents the actual method.
Here is the simplified way that I would explain it:
Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each candidate, you
make a plot, where each axis is the total number of times that they were
preferred to each of their opponents. So, if the candidates are A, B, and
C, candidate A’s plot would have “number of times preferred to B” on one
axis and “number of times preferred to C” on the other axis. Candidate B &
C could be plotted similarly in terms of their opponents. The winner is
simply the candidate who is plotted the farthest up and to the right, or
closest to topmost and rightmost point, which is where a candidate who is
the unanimous first-place choice would be plotted. The distance from that
point is calculated using the Pythagorean theorem, which is where
minimizing the sum of squares that Andy referenced comes in.
The figures in the paper tell the story better than the words, as it is
essentially a geometric idea. And, sections 4, 5, and 6 can really be
skipped - they are more about justifying the approach than explaining it.
Chris, you asked “Why should we be interested in the "concerns" of Borda
(whatever they are)? And so much that we should embrace a method that fails
the Condorcet criterion?” Great question. If you look at the Stanford
Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
Condorcet and Borda as the original pioneers of this thinking (
https://plato.stanford.edu/entries/social-choice/). Borda thinks about
majoritarianism in terms of votes, while Condorcet thinks about it in terms
of voters. Obviously, in FPP elections, these are the same, but the heart
of the interest in these questions comes from the tension that arises
between them in a ranked-choice setting, where each voter has multiple
votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
thinker who studies these issues and has argued most persuasively for
Borda’s approach over Condorcet methods. In section 9 of my paper, I
explain some of my philosophical objections to the Condorcet winner
criterion.
You also asked “Do you propose allowing above-bottom equal ranking or
truncation?” Equal ranking is allowed, and unranked candidates are treated
as last place.
And, I am afraid I may have actually been mistaken about the sincere
favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this example.
The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or
last-place preference, their K-count is simply equal to the number of
voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
elections@jenningsstory.com> wrote:
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate with
the smallest sum of SQUARES of non-victories (defeats plus ties) against
their opponents.
Taking the square root and dividing can make it meaningful by scaling it
to [0,1] or [0,s] (where s is the number of voters), but doesn't change the
finish order.
It does seem like an interesting attempt to "square the circle" (great
pun) and compromise between Borda and Condorcet. I hadn't realized that
Borda and Minimax are minimizing the one-norm and infinity-norm in the same
geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
Election-Methods election-methods@lists.electorama.com wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this message
violates any norms or protocols that the members of this list adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and Condorcet. I
believe that it maintains the simplicity and mathematical elegance of the
Borda count while incorporating Condorcet's concern with pairwise
dominance. Intuitively, it can be understood as ordering candidates by how
close they come to being unanimously selected when plotted in Cartesian
coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you all
will take a look at the paper and share your comments, questions, and
critiques. Ultimately, it is my hope that ranked-choice voting advocates
can arrive at a consensus about the best method for RCV and thus strengthen
efforts to adopt it and deliver much needed democratic improvements. But
even if you don't find the system itself compelling, you may find the
method of plotting electoral outcomes elucidated in the paper to be useful
for the analysis of other electoral systems.
Thank you!
-Dan
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
*Andy* - I really appreciate your feedback. Your summary is correct, and
your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
thinking about it that I had not considered. It seems like a potentially
fruitful lens for understanding it. And, as perhaps you have surmised, I
may have been mistaken in the statement about the sincere favorite
criteria, but I am working on an analysis of the issue that I will share.
*Toby*, making a short summary is a great suggestion. The argument in the
paper is admittedly a bit convoluted before it presents the actual method.
Here is the simplified way that I would explain it:
*Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each candidate, you
make a plot, where each axis is the total number of times that they were
preferred to each of their opponents. So, if the candidates are A, B, and
C, candidate A’s plot would have “number of times preferred to B” on one
axis and “number of times preferred to C” on the other axis. Candidate B &
C could be plotted similarly in terms of their opponents. The winner is
simply the candidate who is plotted the farthest up and to the right, or
closest to topmost and rightmost point, which is where a candidate who is
the unanimous first-place choice would be plotted. The distance from that
point is calculated using the Pythagorean theorem, which is where
minimizing the sum of squares that Andy referenced comes in.*
The figures in the paper tell the story better than the words, as it is
essentially a geometric idea. And, sections 4, 5, and 6 can really be
skipped - they are more about justifying the approach than explaining it.
*Chris*, you asked “Why should we be interested in the "concerns" of Borda
(whatever they are)? And so much that we should embrace a method that fails
the Condorcet criterion?” Great question. If you look at the Stanford
Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
Condorcet and Borda as the original pioneers of this thinking (
https://plato.stanford.edu/entries/social-choice/). Borda thinks about
majoritarianism in terms of votes, while Condorcet thinks about it in terms
of voters. Obviously, in FPP elections, these are the same, but the heart
of the interest in these questions comes from the tension that arises
between them in a ranked-choice setting, where each voter has multiple
votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
thinker who studies these issues and has argued most persuasively for
Borda’s approach over Condorcet methods. In section 9 of my paper, I
explain some of my philosophical objections to the Condorcet winner
criterion.
You also asked “Do you propose allowing above-bottom equal ranking or
truncation?” Equal ranking is allowed, and unranked candidates are treated
as last place.
And, I am afraid I may have actually been mistaken about the sincere
favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this example.
The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or
last-place preference, their K-count is simply equal to the number of
voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
elections@jenningsstory.com> wrote:
> Hi Dan,
>
> Great paper. Thank you for posting!
>
> It seems like the short version is that the winner is the candidate with
> the smallest sum of SQUARES of non-victories (defeats plus ties) against
> their opponents.
>
> Taking the square root and dividing can make it meaningful by scaling it
> to [0,1] or [0,s] (where s is the number of voters), but doesn't change the
> finish order.
>
> It does seem like an interesting attempt to "square the circle" (great
> pun) and compromise between Borda and Condorcet. I hadn't realized that
> Borda and Minimax are minimizing the one-norm and infinity-norm in the same
> geometric space. The two-norm certainly seems like it should be explored.
>
> I would love to see the proof of non-favorite-betrayal.
>
> Best,
>
> ~ Andy
> On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
> Election-Methods <election-methods@lists.electorama.com> wrote:
>
> Hello!
>
> I am a newcomer to this mailing list, so please forgive me if this message
> violates any norms or protocols that the members of this list adhere to.
>
> I have recently developed a novel method for tabulating ranked-choice
> elections that attempts to reconcile the concerns of Borda and Condorcet. I
> believe that it maintains the simplicity and mathematical elegance of the
> Borda count while incorporating Condorcet's concern with pairwise
> dominance. Intuitively, it can be understood as ordering candidates by how
> close they come to being unanimously selected when plotted in Cartesian
> coordinate space. Here is a link to the paper:
>
> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>
> Given its simplicity, I have been very surprised to discover that this
> method has never been proposed before. I am hoping that some of you all
> will take a look at the paper and share your comments, questions, and
> critiques. Ultimately, it is my hope that ranked-choice voting advocates
> can arrive at a consensus about the best method for RCV and thus strengthen
> efforts to adopt it and deliver much needed democratic improvements. But
> even if you don't find the system itself compelling, you may find the
> method of plotting electoral outcomes elucidated in the paper to be useful
> for the analysis of other electoral systems.
>
> Thank you!
>
> -Dan
>
>
>
AS
Abel Stan
Sun, May 18, 2025 6:41 PM
Hi Dan,
Thank you for this contribution, I have not yet encountered such a system,
nor this sort of visualisation, conceptualization between Borda and
Condorcet.
The usual link between these two approaches is the fact that Borda is the
neutral positional system, giving equally spaced points. I give +1 point to
every candidate I rank one above another. I give +2 points to anyone I rank
two points above. That's why the Borda score is the sum of the number of
all won pairwise duels. This gives the duality of Borda so that it can be
described as both a positional and a pairwise count. Condorcet/Smith are
the "unanimity" of pairwise aggretations (Copeland is the plurality of
pairwise aggregations), while Borda is the plurality of non aggregated
pairwise votes (I guess Pareto is the unanimity of non-aggregated pairwise
votes). So in some sense, Condorcet is aggregation of pairwise pluralities,
while Borda is plurality of pairwise aggregations. To me, the Condorcet
principle seems to make much more sense, since by these definitions, Borda
is far less independent of irrelevant alternatives (granted, Condorcet on
its own is defined with 'unanimity' which also means it needs an extension
to be more decisive). I wonder how exactly your approach can be integrated
into this framework and to which is it closer (if it's not THE "middle",
what is, and what other means can we define - arithmetic, geometric,
harmonic, etc. - and is this the quadratic mean?).
I struggle with section 9. I understand the point that the Condorcet
principle might have a tautology (like in me saying because of the above is
Condorcet is more "majoritarian", and Borda more "pluralitarian" because I
define "majority" and "majoritarianism" as aggregating pairwise first,
while aggregating non-pairwise I will consider by definition
"pluralitarian" because of the possibility of aggregating more that 2
candidates at once) in saying the pairwise preference is what matters,
because it's what should matter. But why would the "paradox" break this? If
there is no paradox, that is like when there is unanimity, it's good, but
the rule should still say what happens if there is no unanimity. The same
way we can say in a race of 2 (where Borda and Condorcet are equivalent) if
there is no unanimity simple majority should suffice, we can define what
should suffice in case there is no Condorcet winner. Or if FPP (with ranked
ballots) leads to a tie, we can define a tiebreaker with the next
preferences. We can say we want methods that satisfy unanimity or that have
tiebreakers without expecting that all social preferences can be aggregated
with unanimity alone or without ties. Same goes for Condorcet, the
unanimity of simple majorities. Of course, you could also establish a
'Borda criterion', the plurality of pairwise points, but that would
essentially just say you have to choose the one Borda winner if there
exists one, and one of the Borda winners, if there is a tie. The analogies
in the paper seem unconvincing to me, I doubt that the unanimity criterion
is any less tautological. That's not to say that non-Condorcet paradigms
are not valid, but they are paradigms - similarly to non-Euclidean geometry
Abel
Daniel Kirslis via Election-Methods election-methods@lists.electorama.com
ezt írta (időpont: 2025. máj. 18., V, 19:52):
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
Andy - I really appreciate your feedback. Your summary is correct, and
your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
thinking about it that I had not considered. It seems like a potentially
fruitful lens for understanding it. And, as perhaps you have surmised, I
may have been mistaken in the statement about the sincere favorite
criteria, but I am working on an analysis of the issue that I will share.
Toby, making a short summary is a great suggestion. The argument in the
paper is admittedly a bit convoluted before it presents the actual method.
Here is the simplified way that I would explain it:
Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each candidate, you
make a plot, where each axis is the total number of times that they were
preferred to each of their opponents. So, if the candidates are A, B, and
C, candidate A’s plot would have “number of times preferred to B” on one
axis and “number of times preferred to C” on the other axis. Candidate B &
C could be plotted similarly in terms of their opponents. The winner is
simply the candidate who is plotted the farthest up and to the right, or
closest to topmost and rightmost point, which is where a candidate who is
the unanimous first-place choice would be plotted. The distance from that
point is calculated using the Pythagorean theorem, which is where
minimizing the sum of squares that Andy referenced comes in.
The figures in the paper tell the story better than the words, as it is
essentially a geometric idea. And, sections 4, 5, and 6 can really be
skipped - they are more about justifying the approach than explaining it.
Chris, you asked “Why should we be interested in the "concerns" of
Borda (whatever they are)? And so much that we should embrace a method that
fails the Condorcet criterion?” Great question. If you look at the Stanford
Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
Condorcet and Borda as the original pioneers of this thinking (
https://plato.stanford.edu/entries/social-choice/). Borda thinks about
majoritarianism in terms of votes, while Condorcet thinks about it in terms
of voters. Obviously, in FPP elections, these are the same, but the heart
of the interest in these questions comes from the tension that arises
between them in a ranked-choice setting, where each voter has multiple
votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
thinker who studies these issues and has argued most persuasively for
Borda’s approach over Condorcet methods. In section 9 of my paper, I
explain some of my philosophical objections to the Condorcet winner
criterion.
You also asked “Do you propose allowing above-bottom equal ranking or
truncation?” Equal ranking is allowed, and unranked candidates are treated
as last place.
And, I am afraid I may have actually been mistaken about the sincere
favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this
example. The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or
last-place preference, their K-count is simply equal to the number of
voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
elections@jenningsstory.com> wrote:
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate with
the smallest sum of SQUARES of non-victories (defeats plus ties) against
their opponents.
Taking the square root and dividing can make it meaningful by scaling it
to [0,1] or [0,s] (where s is the number of voters), but doesn't change the
finish order.
It does seem like an interesting attempt to "square the circle" (great
pun) and compromise between Borda and Condorcet. I hadn't realized that
Borda and Minimax are minimizing the one-norm and infinity-norm in the same
geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
Election-Methods election-methods@lists.electorama.com wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this
message violates any norms or protocols that the members of this list
adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and Condorcet. I
believe that it maintains the simplicity and mathematical elegance of the
Borda count while incorporating Condorcet's concern with pairwise
dominance. Intuitively, it can be understood as ordering candidates by how
close they come to being unanimously selected when plotted in Cartesian
coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you all
will take a look at the paper and share your comments, questions, and
critiques. Ultimately, it is my hope that ranked-choice voting advocates
can arrive at a consensus about the best method for RCV and thus strengthen
efforts to adopt it and deliver much needed democratic improvements. But
even if you don't find the system itself compelling, you may find the
method of plotting electoral outcomes elucidated in the paper to be useful
for the analysis of other electoral systems.
Thank you!
-Dan
Hi Dan,
Thank you for this contribution, I have not yet encountered such a system,
nor this sort of visualisation, conceptualization between Borda and
Condorcet.
The usual link between these two approaches is the fact that Borda is the
neutral positional system, giving equally spaced points. I give +1 point to
every candidate I rank one above another. I give +2 points to anyone I rank
two points above. That's why the Borda score is the sum of the number of
all won pairwise duels. This gives the duality of Borda so that it can be
described as both a positional and a pairwise count. Condorcet/Smith are
the "unanimity" of pairwise aggretations (Copeland is the plurality of
pairwise aggregations), while Borda is the plurality of non aggregated
pairwise votes (I guess Pareto is the unanimity of non-aggregated pairwise
votes). So in some sense, Condorcet is aggregation of pairwise pluralities,
while Borda is plurality of pairwise aggregations. To me, the Condorcet
principle seems to make much more sense, since by these definitions, Borda
is far less independent of irrelevant alternatives (granted, Condorcet on
its own is defined with 'unanimity' which also means it needs an extension
to be more decisive). I wonder how exactly your approach can be integrated
into this framework and to which is it closer (if it's not THE "middle",
what is, and what other means can we define - arithmetic, geometric,
harmonic, etc. - and is this the quadratic mean?).
I struggle with section 9. I understand the point that the Condorcet
principle might have a tautology (like in me saying because of the above is
Condorcet is more "majoritarian", and Borda more "pluralitarian" because I
define "majority" and "majoritarianism" as aggregating pairwise first,
while aggregating non-pairwise I will consider by definition
"pluralitarian" because of the possibility of aggregating more that 2
candidates at once) in saying the pairwise preference is what matters,
because it's what should matter. But why would the "paradox" break this? If
there is no paradox, that is like when there is unanimity, it's good, but
the rule should still say what happens if there is no unanimity. The same
way we can say in a race of 2 (where Borda and Condorcet are equivalent) if
there is no unanimity simple majority should suffice, we can define what
should suffice in case there is no Condorcet winner. Or if FPP (with ranked
ballots) leads to a tie, we can define a tiebreaker with the next
preferences. We can say we want methods that satisfy unanimity or that have
tiebreakers without expecting that all social preferences can be aggregated
with unanimity alone or without ties. Same goes for Condorcet, the
unanimity of simple majorities. Of course, you could also establish a
'Borda criterion', the plurality of pairwise points, but that would
essentially just say you have to choose the one Borda winner if there
exists one, and one of the Borda winners, if there is a tie. The analogies
in the paper seem unconvincing to me, I doubt that the unanimity criterion
is any less tautological. That's not to say that non-Condorcet paradigms
are not valid, but they are paradigms - similarly to non-Euclidean geometry
- as far as I know.
Abel
Daniel Kirslis via Election-Methods <election-methods@lists.electorama.com>
ezt írta (időpont: 2025. máj. 18., V, 19:52):
> Hi all,
>
> Thanks so much for the replies. I’ll respond to everyone in this thread.
>
> *Andy* - I really appreciate your feedback. Your summary is correct, and
> your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
> thinking about it that I had not considered. It seems like a potentially
> fruitful lens for understanding it. And, as perhaps you have surmised, I
> may have been mistaken in the statement about the sincere favorite
> criteria, but I am working on an analysis of the issue that I will share.
>
> *Toby*, making a short summary is a great suggestion. The argument in the
> paper is admittedly a bit convoluted before it presents the actual method.
> Here is the simplified way that I would explain it:
>
> *Each voter ranks their preferences, with ties allowed and unranked
> candidates treated as last-place preferences. Then, for each candidate, you
> make a plot, where each axis is the total number of times that they were
> preferred to each of their opponents. So, if the candidates are A, B, and
> C, candidate A’s plot would have “number of times preferred to B” on one
> axis and “number of times preferred to C” on the other axis. Candidate B &
> C could be plotted similarly in terms of their opponents. The winner is
> simply the candidate who is plotted the farthest up and to the right, or
> closest to topmost and rightmost point, which is where a candidate who is
> the unanimous first-place choice would be plotted. The distance from that
> point is calculated using the Pythagorean theorem, which is where
> minimizing the sum of squares that Andy referenced comes in.*
>
> The figures in the paper tell the story better than the words, as it is
> essentially a geometric idea. And, sections 4, 5, and 6 can really be
> skipped - they are more about justifying the approach than explaining it.
>
> *Chris*, you asked “Why should we be interested in the "concerns" of
> Borda (whatever they are)? And so much that we should embrace a method that
> fails the Condorcet criterion?” Great question. If you look at the Stanford
> Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
> Condorcet and Borda as the original pioneers of this thinking (
> https://plato.stanford.edu/entries/social-choice/). Borda thinks about
> majoritarianism in terms of votes, while Condorcet thinks about it in terms
> of voters. Obviously, in FPP elections, these are the same, but the heart
> of the interest in these questions comes from the tension that arises
> between them in a ranked-choice setting, where each voter has multiple
> votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
> thinker who studies these issues and has argued most persuasively for
> Borda’s approach over Condorcet methods. In section 9 of my paper, I
> explain some of my philosophical objections to the Condorcet winner
> criterion.
>
> You also asked “Do you propose allowing above-bottom equal ranking or
> truncation?” Equal ranking is allowed, and unranked candidates are treated
> as last place.
>
> And, I am afraid I may have actually been mistaken about the sincere
> favorite property, so will have to disappoint you there.
>
> You asked “Who does your method elect in this example?
>
> 46 A
> 44 B>C
> 10 C”
>
> If I am understanding your notation correctly, A would win in this
> example. The full ranking would be:
> A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
> B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
> C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
>
> As you can see, when a candidate only appears as a first-place or
> last-place preference, their K-count is simply equal to the number of
> voters ranking them first.
>
> Thanks all!
>
> On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
> elections@jenningsstory.com> wrote:
>
>> Hi Dan,
>>
>> Great paper. Thank you for posting!
>>
>> It seems like the short version is that the winner is the candidate with
>> the smallest sum of SQUARES of non-victories (defeats plus ties) against
>> their opponents.
>>
>> Taking the square root and dividing can make it meaningful by scaling it
>> to [0,1] or [0,s] (where s is the number of voters), but doesn't change the
>> finish order.
>>
>> It does seem like an interesting attempt to "square the circle" (great
>> pun) and compromise between Borda and Condorcet. I hadn't realized that
>> Borda and Minimax are minimizing the one-norm and infinity-norm in the same
>> geometric space. The two-norm certainly seems like it should be explored.
>>
>> I would love to see the proof of non-favorite-betrayal.
>>
>> Best,
>>
>> ~ Andy
>> On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
>> Election-Methods <election-methods@lists.electorama.com> wrote:
>>
>> Hello!
>>
>> I am a newcomer to this mailing list, so please forgive me if this
>> message violates any norms or protocols that the members of this list
>> adhere to.
>>
>> I have recently developed a novel method for tabulating ranked-choice
>> elections that attempts to reconcile the concerns of Borda and Condorcet. I
>> believe that it maintains the simplicity and mathematical elegance of the
>> Borda count while incorporating Condorcet's concern with pairwise
>> dominance. Intuitively, it can be understood as ordering candidates by how
>> close they come to being unanimously selected when plotted in Cartesian
>> coordinate space. Here is a link to the paper:
>>
>> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>>
>> Given its simplicity, I have been very surprised to discover that this
>> method has never been proposed before. I am hoping that some of you all
>> will take a look at the paper and share your comments, questions, and
>> critiques. Ultimately, it is my hope that ranked-choice voting advocates
>> can arrive at a consensus about the best method for RCV and thus strengthen
>> efforts to adopt it and deliver much needed democratic improvements. But
>> even if you don't find the system itself compelling, you may find the
>> method of plotting electoral outcomes elucidated in the paper to be useful
>> for the analysis of other electoral systems.
>>
>> Thank you!
>>
>> -Dan
>>
>>
>> ----
> Election-Methods mailing list - see https://electorama.com/em for list
> info
>
RB
robert bristow-johnson
Sun, May 18, 2025 7:29 PM
Hi Dan,
I made one pass through your paper, but the interaction with Chris and Andy was helpful. I understand the definition of your K-count measure, but still don't understand the motivation of it, solely from the POV of democratic principles, which is where I draw my Condorcetist perspective. Admittedly, I am a hard-core Condorcet advocate, but I am so because of some basic principles.
I read your section 9 and re-read it, and I still cannot get past how it justifies any non-Condorcet method (including your K-count) over Condorcet. The principles of free and fair elections in a democratic context require, among other things, that our votes are valued equally:
1. "One person, one vote": Every enfranchised voter has an equal influence on
government in elections because of our inherent equality as citizens and this is
independent of any utilitarian notion of personal investment in the outcome. If I
enthusiastically prefer Candidate A and you prefer Candidate B only tepidly, your
vote for Candidate B counts no less (nor more) than my vote for A. The
effectiveness of one's vote – how much their vote counts – is not proportional to
their degree of preference but is determined only by their franchise. A citizen with
franchise has a vote that counts equally as much as any other citizen with
franchise. For any ranked ballot, this means that if Candidate A is ranked higher
than Candidate B then that is a vote for A, if only candidates A and B are
contending (such as in the IRV final round). It doesn't matter how many levels A
is ranked higher than B, it counts as exactly one vote for A.
If our votes are not valued equally, then I want my vote to count more than yours. If that is unacceptable (understandably) then we must agree to count our votes equally. In the U.S., too many people have died over that inequality. So then, in order for our votes to be valued equally, we must have Majority Rule in single-winner elections:
2. Majority rule: If more voters mark their ballots preferring Candidate A over
Candidate B than the number of voters marking their ballots to the contrary,
then Candidate B is not elected. If Candidate B were to be elected, that would
mean that the fewer voters preferring Candidate B had cast votes that had greater
value and counted more than those votes from voters of the larger set preferring
Candidate A.
Those are two ways of, essentially, expressing the same principle in single-winner elections. For multi-winner elections, the way to value our votes equally would be Proportional Representation, but I don't wanna go there in this discussion. I would like to stay with single-winner elections.
Now, of course this doesn't deal with the problem of cycles and we can discuss what the best and most democratic way to deal with cycles is, but I cannot understand why, if a Condorcet winner exists, how any other method; Hare, Borda, Bucklin, or Kirslis is more democratic than Condorcet.
If a CW exists and we know (from the Cast Vote Record having ranked ballot data) that the CW exists and who that CW is, how is electing the K-count winner, assuming they're different from the CW, more democratic? Just like with the IRV failures, we will know that a smaller set of voters have left that election satisfied than that of a larger set of voters leaving the election dissatisfied. We will know that the votes coming from that smaller set of voters were more effective in electing their preferred candidate than the votes coming from the larger set of voters that not only preferred someone else, but they preferred a specific candidate over the one who Kirslis elected and marked their ballots saying so. For the very same reason that IRV failed in Burlington Vermont in 2009 or in Alaska in August 2022, the elected candidate will suffer a sense of loss of legitimacy in the election.
In Burlington in 2009, 4064 voters marked their ballots that Candidate A was a better choice than Candidate B and 3476 voters marked their ballots to the contrary. (There were 1436 voters that didn't like either A or B and didn't rank either.) How possibly can Candidate B be elected without counting those 3476 voters' individual votes a little more (like 17% more) than how much the votes were counted from the 4064 voters preferring Candidate A?
Now this is a failure of Hare (IRV) but I can construct the very same question for an election decided with Kirslis rules that failed to elect the CW when such exists. How would you answer that question? How do you justify satisfying a smaller set of voters at the expense of a larger set of voters that preferred, not just anyone else, but a specific candidate over the Kirslis winner? I couldn't glean an answer to that from section 9 (or anywhere else) in your paper.
bestest,
--
r b-j . _ . _ . _ . _ rbj@audioimagination.com
"Imagination is more important than knowledge."
.
.
.
On 05/18/2025 1:51 PM EDT Daniel Kirslis via Election-Methods election-methods@lists.electorama.com wrote:
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
Andy - I really appreciate your feedback. Your summary is correct, and your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of thinking about it that I had not considered. It seems like a potentially fruitful lens for understanding it. And, as perhaps you have surmised, I may have been mistaken in the statement about the sincere favorite criteria, but I am working on an analysis of the issue that I will share.
Toby, making a short summary is a great suggestion. The argument in the paper is admittedly a bit convoluted before it presents the actual method. Here is the simplified way that I would explain it:
Each voter ranks their preferences, with ties allowed and unranked candidates treated as last-place preferences. Then, for each candidate, you make a plot, where each axis is the total number of times that they were preferred to each of their opponents. So, if the candidates are A, B, and C, candidate A’s plot would have “number of times preferred to B” on one axis and “number of times preferred to C” on the other axis. Candidate B & C could be plotted similarly in terms of their opponents. The winner is simply the candidate who is plotted the farthest up and to the right, or closest to topmost and rightmost point, which is where a candidate who is the unanimous first-place choice would be plotted. The distance from that point is calculated using the Pythagorean theorem, which is where minimizing the sum of squares that Andy referenced comes in.
The figures in the paper tell the story better than the words, as it is essentially a geometric idea. And, sections 4, 5, and 6 can really be skipped - they are more about justifying the approach than explaining it.
Chris, you asked “Why should we be interested in the "concerns" of Borda (whatever they are)? And so much that we should embrace a method that fails the Condorcet criterion?” Great question. If you look at the Stanford Encyclopedia of Philosophy’s entry on Social Choice Theory, they list Condorcet and Borda as the original pioneers of this thinking (https://plato.stanford.edu/entries/social-choice/). Borda thinks about majoritarianism in terms of votes, while Condorcet thinks about it in terms of voters. Obviously, in FPP elections, these are the same, but the heart of the interest in these questions comes from the tension that arises between them in a ranked-choice setting, where each voter has multiple votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a thinker who studies these issues and has argued most persuasively for Borda’s approach over Condorcet methods. In section 9 of my paper, I explain some of my philosophical objections to the Condorcet winner criterion.
You also asked “Do you propose allowing above-bottom equal ranking or truncation?” Equal ranking is allowed, and unranked candidates are treated as last place.
And, I am afraid I may have actually been mistaken about the sincere favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this example. The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or last-place preference, their K-count is simply equal to the number of voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) elections@jenningsstory.com wrote:
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate with the smallest sum of SQUARES of non-victories (defeats plus ties) against their opponents.
Taking the square root and dividing can make it meaningful by scaling it to [0,1] or [0,s] (where s is the number of voters), but doesn't change the finish order.
It does seem like an interesting attempt to "square the circle" (great pun) and compromise between Borda and Condorcet. I hadn't realized that Borda and Minimax are minimizing the one-norm and infinity-norm in the same geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via Election-Methods election-methods@lists.electorama.com wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this message violates any norms or protocols that the members of this list adhere to.
I have recently developed a novel method for tabulating ranked-choice elections that attempts to reconcile the concerns of Borda and Condorcet. I believe that it maintains the simplicity and mathematical elegance of the Borda count while incorporating Condorcet's concern with pairwise dominance. Intuitively, it can be understood as ordering candidates by how close they come to being unanimously selected when plotted in Cartesian coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this method has never been proposed before. I am hoping that some of you all will take a look at the paper and share your comments, questions, and critiques. Ultimately, it is my hope that ranked-choice voting advocates can arrive at a consensus about the best method for RCV and thus strengthen efforts to adopt it and deliver much needed democratic improvements. But even if you don't find the system itself compelling, you may find the method of plotting electoral outcomes elucidated in the paper to be useful for the analysis of other electoral systems.
Thank you!
-Dan
Hi Dan,
I made one pass through your paper, but the interaction with Chris and Andy was helpful. I understand the definition of your K-count measure, but still don't understand the motivation of it, solely from the POV of democratic principles, which is where I draw my Condorcetist perspective. Admittedly, I am a hard-core Condorcet advocate, but I am so because of some basic principles.
I read your section 9 and re-read it, and I still cannot get past how it justifies *any* non-Condorcet method (including your K-count) over Condorcet. The principles of free and fair elections in a democratic context require, among other things, that our votes are valued equally:
1. "One person, one vote": Every enfranchised voter has an equal influence on
government in elections because of our inherent equality as citizens and this is
independent of any utilitarian notion of personal investment in the outcome. If I
enthusiastically prefer Candidate A and you prefer Candidate B only tepidly, your
vote for Candidate B counts no less (nor more) than my vote for A. The
effectiveness of one's vote – how much their vote counts – is not proportional to
their degree of preference but is determined only by their franchise. A citizen with
franchise has a vote that counts equally as much as any other citizen with
franchise. For any ranked ballot, this means that if Candidate A is ranked higher
than Candidate B then that is a vote for A, if only candidates A and B are
contending (such as in the IRV final round). It doesn't matter how many levels A
is ranked higher than B, it counts as exactly one vote for A.
If our votes are not valued equally, then I want my vote to count more than yours. If that is unacceptable (understandably) then we must agree to count our votes equally. In the U.S., too many people have died over that inequality. So then, in order for our votes to be valued equally, we must have Majority Rule in single-winner elections:
2. Majority rule: If more voters mark their ballots preferring Candidate A over
Candidate B than the number of voters marking their ballots to the contrary,
then Candidate B is not elected. If Candidate B were to be elected, that would
mean that the fewer voters preferring Candidate B had cast votes that had greater
value and counted more than those votes from voters of the larger set preferring
Candidate A.
Those are two ways of, essentially, expressing the same principle in single-winner elections. For multi-winner elections, the way to value our votes equally would be Proportional Representation, but I don't wanna go there in this discussion. I would like to stay with single-winner elections.
Now, of course this doesn't deal with the problem of cycles and we can discuss what the best and most democratic way to deal with cycles is, but I cannot understand why, *if* a Condorcet winner exists, how *any* other method; Hare, Borda, Bucklin, or Kirslis is more democratic than Condorcet.
If a CW exists and we *know* (from the Cast Vote Record having ranked ballot data) that the CW exists and who that CW is, how is electing the K-count winner, assuming they're different from the CW, more democratic? Just like with the IRV failures, we will *know* that a smaller set of voters have left that election satisfied than that of a larger set of voters leaving the election dissatisfied. We will know that the votes coming from that smaller set of voters were more effective in electing their preferred candidate than the votes coming from the larger set of voters that not only preferred someone else, but they preferred a *specific* candidate over the one who Kirslis elected and marked their ballots saying so. For the very same reason that IRV failed in Burlington Vermont in 2009 or in Alaska in August 2022, the elected candidate will suffer a sense of loss of legitimacy in the election.
In Burlington in 2009, 4064 voters marked their ballots that Candidate A was a better choice than Candidate B and 3476 voters marked their ballots to the contrary. (There were 1436 voters that didn't like either A or B and didn't rank either.) How *possibly* can Candidate B be elected without counting those 3476 voters' individual votes a little more (like 17% more) than how much the votes were counted from the 4064 voters preferring Candidate A?
Now this is a failure of Hare (IRV) but I can construct the very same question for an election decided with Kirslis rules that failed to elect the CW when such exists. How would you answer that question? How do you justify satisfying a smaller set of voters at the expense of a larger set of voters that preferred, not just anyone else, but a specific candidate over the Kirslis winner? I couldn't glean an answer to that from section 9 (or anywhere else) in your paper.
bestest,
--
r b-j . _ . _ . _ . _ rbj@audioimagination.com
"Imagination is more important than knowledge."
.
.
.
> On 05/18/2025 1:51 PM EDT Daniel Kirslis via Election-Methods <election-methods@lists.electorama.com> wrote:
>
>
> Hi all,
>
> Thanks so much for the replies. I’ll respond to everyone in this thread.
>
> Andy - I really appreciate your feedback. Your summary is correct, and your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of thinking about it that I had not considered. It seems like a potentially fruitful lens for understanding it. And, as perhaps you have surmised, I may have been mistaken in the statement about the sincere favorite criteria, but I am working on an analysis of the issue that I will share.
>
> Toby, making a short summary is a great suggestion. The argument in the paper is admittedly a bit convoluted before it presents the actual method. Here is the simplified way that I would explain it:
>
> Each voter ranks their preferences, with ties allowed and unranked candidates treated as last-place preferences. Then, for each candidate, you make a plot, where each axis is the total number of times that they were preferred to each of their opponents. So, if the candidates are A, B, and C, candidate A’s plot would have “number of times preferred to B” on one axis and “number of times preferred to C” on the other axis. Candidate B & C could be plotted similarly in terms of their opponents. The winner is simply the candidate who is plotted the farthest up and to the right, or closest to topmost and rightmost point, which is where a candidate who is the unanimous first-place choice would be plotted. The distance from that point is calculated using the Pythagorean theorem, which is where minimizing the sum of squares that Andy referenced comes in.
>
> The figures in the paper tell the story better than the words, as it is essentially a geometric idea. And, sections 4, 5, and 6 can really be skipped - they are more about justifying the approach than explaining it.
>
> Chris, you asked “Why should we be interested in the "concerns" of Borda (whatever they are)? And so much that we should embrace a method that fails the Condorcet criterion?” Great question. If you look at the Stanford Encyclopedia of Philosophy’s entry on Social Choice Theory, they list Condorcet and Borda as the original pioneers of this thinking (https://plato.stanford.edu/entries/social-choice/). Borda thinks about majoritarianism in terms of votes, while Condorcet thinks about it in terms of voters. Obviously, in FPP elections, these are the same, but the heart of the interest in these questions comes from the tension that arises between them in a ranked-choice setting, where each voter has multiple votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a thinker who studies these issues and has argued most persuasively for Borda’s approach over Condorcet methods. In section 9 of my paper, I explain some of my philosophical objections to the Condorcet winner criterion.
>
> You also asked “Do you propose allowing above-bottom equal ranking or truncation?” Equal ranking is allowed, and unranked candidates are treated as last place.
>
> And, I am afraid I may have actually been mistaken about the sincere favorite property, so will have to disappoint you there.
>
> You asked “Who does your method elect in this example?
>
> 46 A
> 44 B>C
> 10 C”
>
> If I am understanding your notation correctly, A would win in this example. The full ranking would be:
> A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
> B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
> C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
>
> As you can see, when a candidate only appears as a first-place or last-place preference, their K-count is simply equal to the number of voters ranking them first.
>
> Thanks all!
>
>
> On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <elections@jenningsstory.com> wrote:
> > Hi Dan,
> >
> > Great paper. Thank you for posting!
> >
> > It seems like the short version is that the winner is the candidate with the smallest sum of SQUARES of non-victories (defeats plus ties) against their opponents.
> >
> > Taking the square root and dividing can make it meaningful by scaling it to [0,1] or [0,s] (where s is the number of voters), but doesn't change the finish order.
> >
> >
> > It does seem like an interesting attempt to "square the circle" (great pun) and compromise between Borda and Condorcet. I hadn't realized that Borda and Minimax are minimizing the one-norm and infinity-norm in the same geometric space. The two-norm certainly seems like it should be explored.
> >
> > I would love to see the proof of non-favorite-betrayal.
> >
> > Best,
> >
> > ~ Andy
> > On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via Election-Methods <election-methods@lists.electorama.com> wrote:
> >
> > > Hello!
> > >
> > > I am a newcomer to this mailing list, so please forgive me if this message violates any norms or protocols that the members of this list adhere to.
> > >
> > > I have recently developed a novel method for tabulating ranked-choice elections that attempts to reconcile the concerns of Borda and Condorcet. I believe that it maintains the simplicity and mathematical elegance of the Borda count while incorporating Condorcet's concern with pairwise dominance. Intuitively, it can be understood as ordering candidates by how close they come to being unanimously selected when plotted in Cartesian coordinate space. Here is a link to the paper:
> > > https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
> > >
> > > Given its simplicity, I have been very surprised to discover that this method has never been proposed before. I am hoping that some of you all will take a look at the paper and share your comments, questions, and critiques. Ultimately, it is my hope that ranked-choice voting advocates can arrive at a consensus about the best method for RCV and thus strengthen efforts to adopt it and deliver much needed democratic improvements. But even if you don't find the system itself compelling, you may find the method of plotting electoral outcomes elucidated in the paper to be useful for the analysis of other electoral systems.
> > >
> > > Thank you!
> > >
> > > -Dan
> >
> >
> ----
> Election-Methods mailing list - see https://electorama.com/em for list info
CB
Chris Benham
Sun, May 18, 2025 7:58 PM
Daniel,
So according to you, this method is so childishly "simple" that you
can't understand why no-one has thought of it before, but it can't be
explained without reference to geometry, graphs, square roots and "the
Pythagorean theorem".
/Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each
candidate, you make a plot, where each axis is the total number of
times that they were preferred to each of their opponents. So, if the
candidates are A, B, and C, candidate A’s plot would have “number of
times preferred to B” on one axis and “number of times preferred to C”
on the other axis. Candidate B & C could be plotted similarly in terms
of their opponents. The winner is simply the candidate who is plotted
the farthest up and to the right, or closest to topmost and rightmost
point, which is where a candidate who is the unanimous first-place
choice would be plotted. The distance from that point is calculated
using the Pythagorean theorem, which is where minimizing the sum of
squares that Andy referenced comes in./
I think that there are many people in the US (and elsewhere) who have no
background in Maths or Geometry and so don't understand any Math-ese ,
even some who are interested in election methods.
Is this really your best attempt to explain how the method works to them??
Chris
On 19/05/2025 3:21 am, Daniel Kirslis via Election-Methods wrote:
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
Andy - I really appreciate your feedback. Your summary is correct,
and your framing of it as one-norm vs. two-norm vs. infinity-norm is a
way of thinking about it that I had not considered. It seems like a
potentially fruitful lens for understanding it. And, as perhaps you
have surmised, I may have been mistaken in the statement about the
sincere favorite criteria, but I am working on an analysis of the
issue that I will share.
Toby, making a short summary is a great suggestion. The argument in
the paper is admittedly a bit convoluted before it presents the actual
method. Here is the simplified way that I would explain it:
/
Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each
candidate, you make a plot, where each axis is the total number of
times that they were preferred to each of their opponents. So, if the
candidates are A, B, and C, candidate A’s plot would have “number of
times preferred to B” on one axis and “number of times preferred to C”
on the other axis. Candidate B & C could be plotted similarly in terms
of their opponents. The winner is simply the candidate who is plotted
the farthest up and to the right, or closest to topmost and rightmost
point, which is where a candidate who is the unanimous first-place
choice would be plotted. The distance from that point is calculated
using the Pythagorean theorem, which is where minimizing the sum of
squares that Andy referenced comes in./
The figures in the paper tell the story better than the words, as it
is essentially a geometric idea. And, sections 4, 5, and 6 can really
be skipped - they are more about justifying the approach than
explaining it.
Chris, you asked “Why should we be interested in the "concerns" of
Borda (whatever they are)? And so much that we should embrace a method
that fails the Condorcet criterion?” Great question. If you look at
the Stanford Encyclopedia of Philosophy’s entry on Social Choice
Theory, they list Condorcet and Borda as the original pioneers of this
thinking (https://plato.stanford.edu/entries/social-choice/). Borda
thinks about majoritarianism in terms of votes, while Condorcet thinks
about it in terms of voters. Obviously, in FPP elections, these are
the same, but the heart of the interest in these questions comes from
the tension that arises between them in a ranked-choice setting, where
each voter has multiple votes and ‘majoritarianism’ is no longer
simple to define. Don Saari is a thinker who studies these issues and
has argued most persuasively for Borda’s approach over Condorcet
methods. In section 9 of my paper, I explain some of my philosophical
objections to the Condorcet winner criterion.
You also asked “Do you propose allowing above-bottom equal ranking or
truncation?” Equal ranking is allowed, and unranked candidates are
treated as last place.
And, I am afraid I may have actually been mistaken about the sincere
favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this
example. The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or
last-place preference, their K-count is simply equal to the number of
voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections)
elections@jenningsstory.com wrote:
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the
candidate with the smallest sum of SQUARES of non-victories
(defeats plus ties) against their opponents.
Taking the square root and dividing can make it meaningful by
scaling it to [0,1] or [0,s] (where s is the number of voters),
but doesn't change the finish order.
It does seem like an interesting attempt to "square the circle"
(great pun) and compromise between Borda and Condorcet. I hadn't
realized that Borda and Minimax are minimizing the one-norm and
infinity-norm in the same geometric space. The two-norm certainly
seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
Election-Methods <election-methods@lists.electorama.com> wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if
this message violates any norms or protocols that the members of
this list adhere to.
I have recently developed a novel method for tabulating
ranked-choice elections that attempts to reconcile the concerns
of Borda and Condorcet. I believe that it maintains the
simplicity and mathematical elegance of the Borda count while
incorporating Condorcet's concern with pairwise dominance.
Intuitively, it can be understood as ordering candidates by how
close they come to being unanimously selected when plotted in
Cartesian coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that
this method has never been proposed before. I am hoping that some
of you all will take a look at the paper and share your comments,
questions, and critiques. Ultimately, it is my hope that
ranked-choice voting advocates can arrive at a consensus about
the best method for RCV and thus strengthen efforts to adopt it
and deliver much needed democratic improvements. But even if you
don't find the system itself compelling, you may find the method
of plotting electoral outcomes elucidated in the paper to be
useful for the analysis of other electoral systems.
Thank you!
-Dan
Election-Methods mailing list - seehttps://electorama.com/em for list info
Daniel,
So according to you, this method is so childishly "simple" that you
can't understand why no-one has thought of it before, but it can't be
explained without reference to geometry, graphs, square roots and "the
Pythagorean theorem".
> /Each voter ranks their preferences, with ties allowed and unranked
> candidates treated as last-place preferences. Then, for each
> candidate, you make a plot, where each axis is the total number of
> times that they were preferred to each of their opponents. So, if the
> candidates are A, B, and C, candidate A’s plot would have “number of
> times preferred to B” on one axis and “number of times preferred to C”
> on the other axis. Candidate B & C could be plotted similarly in terms
> of their opponents. The winner is simply the candidate who is plotted
> the farthest up and to the right, or closest to topmost and rightmost
> point, which is where a candidate who is the unanimous first-place
> choice would be plotted. The distance from that point is calculated
> using the Pythagorean theorem, which is where minimizing the sum of
> squares that Andy referenced comes in./
I think that there are many people in the US (and elsewhere) who have no
background in Maths or Geometry and so don't understand any Math-ese ,
even some who are interested in election methods.
Is this really your best attempt to explain how the method works to them??
Chris
On 19/05/2025 3:21 am, Daniel Kirslis via Election-Methods wrote:
> Hi all,
>
> Thanks so much for the replies. I’ll respond to everyone in this thread.
>
> *Andy* - I really appreciate your feedback. Your summary is correct,
> and your framing of it as one-norm vs. two-norm vs. infinity-norm is a
> way of thinking about it that I had not considered. It seems like a
> potentially fruitful lens for understanding it. And, as perhaps you
> have surmised, I may have been mistaken in the statement about the
> sincere favorite criteria, but I am working on an analysis of the
> issue that I will share.
>
> *Toby*, making a short summary is a great suggestion. The argument in
> the paper is admittedly a bit convoluted before it presents the actual
> method. Here is the simplified way that I would explain it:
> /
> Each voter ranks their preferences, with ties allowed and unranked
> candidates treated as last-place preferences. Then, for each
> candidate, you make a plot, where each axis is the total number of
> times that they were preferred to each of their opponents. So, if the
> candidates are A, B, and C, candidate A’s plot would have “number of
> times preferred to B” on one axis and “number of times preferred to C”
> on the other axis. Candidate B & C could be plotted similarly in terms
> of their opponents. The winner is simply the candidate who is plotted
> the farthest up and to the right, or closest to topmost and rightmost
> point, which is where a candidate who is the unanimous first-place
> choice would be plotted. The distance from that point is calculated
> using the Pythagorean theorem, which is where minimizing the sum of
> squares that Andy referenced comes in./
>
> The figures in the paper tell the story better than the words, as it
> is essentially a geometric idea. And, sections 4, 5, and 6 can really
> be skipped - they are more about justifying the approach than
> explaining it.
>
> *Chris*, you asked “Why should we be interested in the "concerns" of
> Borda (whatever they are)? And so much that we should embrace a method
> that fails the Condorcet criterion?” Great question. If you look at
> the Stanford Encyclopedia of Philosophy’s entry on Social Choice
> Theory, they list Condorcet and Borda as the original pioneers of this
> thinking (https://plato.stanford.edu/entries/social-choice/). Borda
> thinks about majoritarianism in terms of votes, while Condorcet thinks
> about it in terms of voters. Obviously, in FPP elections, these are
> the same, but the heart of the interest in these questions comes from
> the tension that arises between them in a ranked-choice setting, where
> each voter has multiple votes and ‘majoritarianism’ is no longer
> simple to define. Don Saari is a thinker who studies these issues and
> has argued most persuasively for Borda’s approach over Condorcet
> methods. In section 9 of my paper, I explain some of my philosophical
> objections to the Condorcet winner criterion.
>
> You also asked “Do you propose allowing above-bottom equal ranking or
> truncation?” Equal ranking is allowed, and unranked candidates are
> treated as last place.
>
> And, I am afraid I may have actually been mistaken about the sincere
> favorite property, so will have to disappoint you there.
>
> You asked “Who does your method elect in this example?
>
> 46 A
> 44 B>C
> 10 C”
>
> If I am understanding your notation correctly, A would win in this
> example. The full ranking would be:
> A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
> B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
> C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
>
> As you can see, when a candidate only appears as a first-place or
> last-place preference, their K-count is simply equal to the number of
> voters ranking them first.
>
> Thanks all!
>
> On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections)
> <elections@jenningsstory.com> wrote:
>
> Hi Dan,
>
> Great paper. Thank you for posting!
>
> It seems like the short version is that the winner is the
> candidate with the smallest sum of SQUARES of non-victories
> (defeats plus ties) against their opponents.
>
> Taking the square root and dividing can make it meaningful by
> scaling it to [0,1] or [0,s] (where s is the number of voters),
> but doesn't change the finish order.
>
> It does seem like an interesting attempt to "square the circle"
> (great pun) and compromise between Borda and Condorcet. I hadn't
> realized that Borda and Minimax are minimizing the one-norm and
> infinity-norm in the same geometric space. The two-norm certainly
> seems like it should be explored.
>
> I would love to see the proof of non-favorite-betrayal.
>
> Best,
>
> ~ Andy
> On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
> Election-Methods <election-methods@lists.electorama.com> wrote:
>> Hello!
>>
>> I am a newcomer to this mailing list, so please forgive me if
>> this message violates any norms or protocols that the members of
>> this list adhere to.
>>
>> I have recently developed a novel method for tabulating
>> ranked-choice elections that attempts to reconcile the concerns
>> of Borda and Condorcet. I believe that it maintains the
>> simplicity and mathematical elegance of the Borda count while
>> incorporating Condorcet's concern with pairwise dominance.
>> Intuitively, it can be understood as ordering candidates by how
>> close they come to being unanimously selected when plotted in
>> Cartesian coordinate space. Here is a link to the paper:
>> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>>
>> Given its simplicity, I have been very surprised to discover that
>> this method has never been proposed before. I am hoping that some
>> of you all will take a look at the paper and share your comments,
>> questions, and critiques. Ultimately, it is my hope that
>> ranked-choice voting advocates can arrive at a consensus about
>> the best method for RCV and thus strengthen efforts to adopt it
>> and deliver much needed democratic improvements. But even if you
>> don't find the system itself compelling, you may find the method
>> of plotting electoral outcomes elucidated in the paper to be
>> useful for the analysis of other electoral systems.
>>
>> Thank you!
>>
>> -Dan
>
>
> ----
> Election-Methods mailing list - seehttps://electorama.com/em for list info
DK
Daniel Kirslis
Sun, May 18, 2025 11:46 PM
Hi r b-j,
Thank you for this response. I want to address both of your principles.
First, is "one person, one vote". I of course agree completely that each
individual's vote should be treated exactly equally, and the K-count does
this. You say that "for any ranked ballot, this means that if Candidate A
is ranked higher than Candidate B then that is a vote for A... It doesn't
matter how many levels A is ranked higher than B, it counts as exactly one
vote for A." This is precisely how the K-count works - if A is ranked above
B on one ballot, then A advances by one along the 'preferred to B' axis.
The number of rankings between them is immaterial to A's position vis a vis
the B axis. However, if A is ranked above other candidates on that ballot,
A will also advance along those candidates' axes, so it is perhaps not
exactly "one vote". But each voter's vote has the same potential power.
To your second principle. You say "I cannot understand why, if a
Condorcet winner exists, how any other method; Hare, Borda, Bucklin, or
Kirslis is more democratic than Condorcet." Let me give an example to
illustrate, which relates to the principle of majority rule.
Imagine an election with 26 candidates, A, B, C... Z, and 1 million voters.
Let us suppose that candidate A is unanimously preferred to every other
candidate, 1,000,000 to 0, except for candidate Z, to whom she loses by 2
votes, 500,001 to 499,999. Meanwhile, candidate Z beats every other
candidate by the same 2 vote margin, and is thus very narrowly a Condorcet
winner. Does it really reflect the will of the majority better to declare
candidate Z the winner because of his extraordinarily narrow margin over
all of the opposition when candidate A is the unanimous favorite versus
everyone but Candidate Z, to whom she barely loses? Many more preferences
are violated by choosing the Condorcet winner in this case than
choosing candidate A. This is the heart of the issue with the Condorcet
winner criteria - if a Condorcet winner exists, a Condorcet method
must completely
ignore the size of the margins of victory, no matter how large. In my view,
this curtails the meaning of 'majority rule' in a way that feels
undemocratic.
I am not familiar with the Burlington election that you reference, and I
will look into it when I have a chance. I don't know what the K-count would
decide in that case. But I can try to answer in principle your question
"How possibly can Candidate B be elected without counting those 3476
voters' individual votes a little more (like 17% more) than how much the
votes were counted from the 4064 voters preferring Candidate A?" In the
K-count, for Candidate B to be elected in this scenario, there would need
to be a 3rd candidate (or multiple other candidates) to whom B was widely
preferred but A was not. So, B would win because the people who favored A
still preferred B to C, while the people who favored B preferred C to A. If
you only look at the head-to-head votes of A vs. B, this seems
anti-majoritarian, but the point I make in the paper is that you cannot make
valid inferences by decontextualizing the data like that, as doing so can
lead you into the logical contradiction of a Condorcet cycle. It is in the
very nature of multi-option preference aggregation that the data cannot be
decomposed in this way. Another way of thinking about this is - suppose
that while A is preferred to B, B is preferred to C, and C is preferred to
A, so you have a classic Condorcet cycle. Then, someone must be declared
the winner, so in your reasoning, someone's votes will be counted for more
than someone else's. And, when resolving this issue, most Condorcet methods
will look at the margins of victory, even though they are ignored in the
case when a Condorcet winner exists. But if margins matter enough to decide
a winner when no Condorcet winner exists, why is it okay to completely
ignore them when a Condorcet winner does exist?
The K-count is a way of trying to reconcile Condorcet's conception of
majority rule, which looks for majority in terms of each head-to-head
matchup, with Borda's conception of majority rule, which seeks to honor the
maximum number of individual pairwise preferences.
Thanks again for your response, and thank you for looking over the paper. I
appreciate your civil tone and good faith questions, and I hope it is clear
that the discussion here is made with full respect and in a spirit of
friendly intellectual inquiry. And I welcome your response to these
arguments!
I am also considering the questions from other folks and am working on
responses to those as well.
On Sun, May 18, 2025 at 3:30 PM robert bristow-johnson via Election-Methods
election-methods@lists.electorama.com wrote:
Hi Dan,
I made one pass through your paper, but the interaction with Chris and
Andy was helpful. I understand the definition of your K-count measure, but
still don't understand the motivation of it, solely from the POV of
democratic principles, which is where I draw my Condorcetist perspective.
Admittedly, I am a hard-core Condorcet advocate, but I am so because of
some basic principles.
I read your section 9 and re-read it, and I still cannot get past how it
justifies any non-Condorcet method (including your K-count) over
Condorcet. The principles of free and fair elections in a democratic
context require, among other things, that our votes are valued equally:
1. "One person, one vote": Every enfranchised voter has an equal
influence on
government in elections because of our inherent equality as citizens
and this is
independent of any utilitarian notion of personal investment in the
outcome. If I
enthusiastically prefer Candidate A and you prefer Candidate B only
tepidly, your
vote for Candidate B counts no less (nor more) than my vote for A. The
effectiveness of one's vote – how much their vote counts – is not
proportional to
their degree of preference but is determined only by their franchise.
A citizen with
franchise has a vote that counts equally as much as any other citizen
with
franchise. For any ranked ballot, this means that if Candidate A is
ranked higher
than Candidate B then that is a vote for A, if only candidates A and B
are
contending (such as in the IRV final round). It doesn't matter how
many levels A
is ranked higher than B, it counts as exactly one vote for A.
If our votes are not valued equally, then I want my vote to count more
than yours. If that is unacceptable (understandably) then we must agree to
count our votes equally. In the U.S., too many people have died over that
inequality. So then, in order for our votes to be valued equally, we must
have Majority Rule in single-winner elections:
2. Majority rule: If more voters mark their ballots preferring
Candidate A over
Candidate B than the number of voters marking their ballots to the
contrary,
then Candidate B is not elected. If Candidate B were to be elected,
that would
mean that the fewer voters preferring Candidate B had cast votes that
had greater
value and counted more than those votes from voters of the larger set
preferring
Candidate A.
Those are two ways of, essentially, expressing the same principle in
single-winner elections. For multi-winner elections, the way to value our
votes equally would be Proportional Representation, but I don't wanna go
there in this discussion. I would like to stay with single-winner
elections.
Now, of course this doesn't deal with the problem of cycles and we can
discuss what the best and most democratic way to deal with cycles is, but I
cannot understand why, if a Condorcet winner exists, how any other
method; Hare, Borda, Bucklin, or Kirslis is more democratic than Condorcet.
If a CW exists and we know (from the Cast Vote Record having ranked
ballot data) that the CW exists and who that CW is, how is electing the
K-count winner, assuming they're different from the CW, more democratic?
Just like with the IRV failures, we will know that a smaller set of
voters have left that election satisfied than that of a larger set of
voters leaving the election dissatisfied. We will know that the votes
coming from that smaller set of voters were more effective in electing
their preferred candidate than the votes coming from the larger set of
voters that not only preferred someone else, but they preferred a
specific candidate over the one who Kirslis elected and marked their
ballots saying so. For the very same reason that IRV failed in Burlington
Vermont in 2009 or in Alaska in August 2022, the elected candidate will
suffer a sense of loss of legitimacy in the election.
In Burlington in 2009, 4064 voters marked their ballots that Candidate A
was a better choice than Candidate B and 3476 voters marked their ballots
to the contrary. (There were 1436 voters that didn't like either A or B
and didn't rank either.) How possibly can Candidate B be elected without
counting those 3476 voters' individual votes a little more (like 17% more)
than how much the votes were counted from the 4064 voters preferring
Candidate A?
Now this is a failure of Hare (IRV) but I can construct the very same
question for an election decided with Kirslis rules that failed to elect
the CW when such exists. How would you answer that question? How do you
justify satisfying a smaller set of voters at the expense of a larger set
of voters that preferred, not just anyone else, but a specific candidate
over the Kirslis winner? I couldn't glean an answer to that from section 9
(or anywhere else) in your paper.
bestest,
--
r b-j . _ . _ . _ . _ rbj@audioimagination.com
"Imagination is more important than knowledge."
.
.
.
On 05/18/2025 1:51 PM EDT Daniel Kirslis via Election-Methods <
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
Andy - I really appreciate your feedback. Your summary is correct, and
your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
thinking about it that I had not considered. It seems like a potentially
fruitful lens for understanding it. And, as perhaps you have surmised, I
may have been mistaken in the statement about the sincere favorite
criteria, but I am working on an analysis of the issue that I will share.
Toby, making a short summary is a great suggestion. The argument in the
paper is admittedly a bit convoluted before it presents the actual method.
Here is the simplified way that I would explain it:
Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each candidate, you
make a plot, where each axis is the total number of times that they were
preferred to each of their opponents. So, if the candidates are A, B, and
C, candidate A’s plot would have “number of times preferred to B” on one
axis and “number of times preferred to C” on the other axis. Candidate B &
C could be plotted similarly in terms of their opponents. The winner is
simply the candidate who is plotted the farthest up and to the right, or
closest to topmost and rightmost point, which is where a candidate who is
the unanimous first-place choice would be plotted. The distance from that
point is calculated using the Pythagorean theorem, which is where
minimizing the sum of squares that Andy referenced comes in.
The figures in the paper tell the story better than the words, as it is
essentially a geometric idea. And, sections 4, 5, and 6 can really be
skipped - they are more about justifying the approach than explaining it.
Chris, you asked “Why should we be interested in the "concerns" of Borda
(whatever they are)? And so much that we should embrace a method that fails
the Condorcet criterion?” Great question. If you look at the Stanford
Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
Condorcet and Borda as the original pioneers of this thinking (
https://plato.stanford.edu/entries/social-choice/). Borda thinks about
majoritarianism in terms of votes, while Condorcet thinks about it in terms
of voters. Obviously, in FPP elections, these are the same, but the heart
of the interest in these questions comes from the tension that arises
between them in a ranked-choice setting, where each voter has multiple
votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
thinker who studies these issues and has argued most persuasively for
Borda’s approach over Condorcet methods. In section 9 of my paper, I
explain some of my philosophical objections to the Condorcet winner
criterion.
You also asked “Do you propose allowing above-bottom equal ranking or
truncation?” Equal ranking is allowed, and unranked candidates are treated
as last place.
And, I am afraid I may have actually been mistaken about the sincere
favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this
example. The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or
last-place preference, their K-count is simply equal to the number of
voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate
with the smallest sum of SQUARES of non-victories (defeats plus ties)
against their opponents.
Taking the square root and dividing can make it meaningful by scaling
it to [0,1] or [0,s] (where s is the number of voters), but doesn't change
the finish order.
It does seem like an interesting attempt to "square the circle" (great
pun) and compromise between Borda and Condorcet. I hadn't realized that
Borda and Minimax are minimizing the one-norm and infinity-norm in the same
geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
Hello!
I am a newcomer to this mailing list, so please forgive me if this
message violates any norms or protocols that the members of this list
adhere to.
I have recently developed a novel method for tabulating
ranked-choice elections that attempts to reconcile the concerns of Borda
and Condorcet. I believe that it maintains the simplicity and mathematical
elegance of the Borda count while incorporating Condorcet's concern with
pairwise dominance. Intuitively, it can be understood as ordering
candidates by how close they come to being unanimously selected when
plotted in Cartesian coordinate space. Here is a link to the paper:
Given its simplicity, I have been very surprised to discover that
this method has never been proposed before. I am hoping that some of you
all will take a look at the paper and share your comments, questions, and
critiques. Ultimately, it is my hope that ranked-choice voting advocates
can arrive at a consensus about the best method for RCV and thus strengthen
efforts to adopt it and deliver much needed democratic improvements. But
even if you don't find the system itself compelling, you may find the
method of plotting electoral outcomes elucidated in the paper to be useful
for the analysis of other electoral systems.
Hi r b-j,
Thank you for this response. I want to address both of your principles.
First, is "one person, one vote". I of course agree completely that each
individual's vote should be treated exactly equally, and the K-count does
this. You say that "for any ranked ballot, this means that if Candidate A
is ranked higher than Candidate B then that is a vote for A... It doesn't
matter how many levels A is ranked higher than B, it counts as exactly one
vote for A." This is precisely how the K-count works - if A is ranked above
B on one ballot, then A advances by one along the 'preferred to B' axis.
The number of rankings between them is immaterial to A's position vis a vis
the B axis. However, if A is ranked above other candidates on that ballot,
A will also advance along those candidates' axes, so it is perhaps not
exactly "one vote". But each voter's vote has the same potential power.
To your second principle. You say "I cannot understand why, *if* a
Condorcet winner exists, how *any* other method; Hare, Borda, Bucklin, or
Kirslis is more democratic than Condorcet." Let me give an example to
illustrate, which relates to the principle of majority rule.
Imagine an election with 26 candidates, A, B, C... Z, and 1 million voters.
Let us suppose that candidate A is unanimously preferred to every other
candidate, 1,000,000 to 0, except for candidate Z, to whom she loses by 2
votes, 500,001 to 499,999. Meanwhile, candidate Z beats every other
candidate by the same 2 vote margin, and is thus very narrowly a Condorcet
winner. Does it really reflect the will of the majority better to declare
candidate Z the winner because of his extraordinarily narrow margin over
all of the opposition when candidate A is the unanimous favorite versus
everyone but Candidate Z, to whom she barely loses? Many more preferences
are violated by choosing the Condorcet winner in this case than
choosing candidate A. This is the heart of the issue with the Condorcet
winner criteria - if a Condorcet winner exists, a Condorcet method
*must* completely
ignore the size of the margins of victory, no matter how large. In my view,
this curtails the meaning of 'majority rule' in a way that feels
undemocratic.
I am not familiar with the Burlington election that you reference, and I
will look into it when I have a chance. I don't know what the K-count would
decide in that case. But I can try to answer in principle your question
"How *possibly* can Candidate B be elected without counting those 3476
voters' individual votes a little more (like 17% more) than how much the
votes were counted from the 4064 voters preferring Candidate A?" In the
K-count, for Candidate B to be elected in this scenario, there would need
to be a 3rd candidate (or multiple other candidates) to whom B was widely
preferred but A was not. So, B would win because the people who favored A
still preferred B to C, while the people who favored B preferred C to A. If
you only look at the head-to-head votes of A vs. B, this seems
anti-majoritarian, but the point I make in the paper is that you cannot make
valid inferences by decontextualizing the data like that, as doing so can
lead you into the logical contradiction of a Condorcet cycle. It is in the
very nature of multi-option preference aggregation that the data cannot be
decomposed in this way. Another way of thinking about this is - suppose
that while A is preferred to B, B is preferred to C, and C is preferred to
A, so you have a classic Condorcet cycle. Then, someone must be declared
the winner, so in your reasoning, someone's votes will be counted for more
than someone else's. And, when resolving this issue, most Condorcet methods
will look at the margins of victory, even though they are ignored in the
case when a Condorcet winner exists. But if margins matter enough to decide
a winner when no Condorcet winner exists, why is it okay to completely
ignore them when a Condorcet winner does exist?
The K-count is a way of trying to reconcile Condorcet's conception of
majority rule, which looks for majority in terms of each head-to-head
matchup, with Borda's conception of majority rule, which seeks to honor the
maximum number of individual pairwise preferences.
Thanks again for your response, and thank you for looking over the paper. I
appreciate your civil tone and good faith questions, and I hope it is clear
that the discussion here is made with full respect and in a spirit of
friendly intellectual inquiry. And I welcome your response to these
arguments!
I am also considering the questions from other folks and am working on
responses to those as well.
On Sun, May 18, 2025 at 3:30 PM robert bristow-johnson via Election-Methods
<election-methods@lists.electorama.com> wrote:
>
> Hi Dan,
>
> I made one pass through your paper, but the interaction with Chris and
> Andy was helpful. I understand the definition of your K-count measure, but
> still don't understand the motivation of it, solely from the POV of
> democratic principles, which is where I draw my Condorcetist perspective.
> Admittedly, I am a hard-core Condorcet advocate, but I am so because of
> some basic principles.
>
> I read your section 9 and re-read it, and I still cannot get past how it
> justifies *any* non-Condorcet method (including your K-count) over
> Condorcet. The principles of free and fair elections in a democratic
> context require, among other things, that our votes are valued equally:
>
> 1. "One person, one vote": Every enfranchised voter has an equal
> influence on
> government in elections because of our inherent equality as citizens
> and this is
> independent of any utilitarian notion of personal investment in the
> outcome. If I
> enthusiastically prefer Candidate A and you prefer Candidate B only
> tepidly, your
> vote for Candidate B counts no less (nor more) than my vote for A. The
> effectiveness of one's vote – how much their vote counts – is not
> proportional to
> their degree of preference but is determined only by their franchise.
> A citizen with
> franchise has a vote that counts equally as much as any other citizen
> with
> franchise. For any ranked ballot, this means that if Candidate A is
> ranked higher
> than Candidate B then that is a vote for A, if only candidates A and B
> are
> contending (such as in the IRV final round). It doesn't matter how
> many levels A
> is ranked higher than B, it counts as exactly one vote for A.
>
> If our votes are not valued equally, then I want my vote to count more
> than yours. If that is unacceptable (understandably) then we must agree to
> count our votes equally. In the U.S., too many people have died over that
> inequality. So then, in order for our votes to be valued equally, we must
> have Majority Rule in single-winner elections:
>
> 2. Majority rule: If more voters mark their ballots preferring
> Candidate A over
> Candidate B than the number of voters marking their ballots to the
> contrary,
> then Candidate B is not elected. If Candidate B were to be elected,
> that would
> mean that the fewer voters preferring Candidate B had cast votes that
> had greater
> value and counted more than those votes from voters of the larger set
> preferring
> Candidate A.
>
> Those are two ways of, essentially, expressing the same principle in
> single-winner elections. For multi-winner elections, the way to value our
> votes equally would be Proportional Representation, but I don't wanna go
> there in this discussion. I would like to stay with single-winner
> elections.
>
> Now, of course this doesn't deal with the problem of cycles and we can
> discuss what the best and most democratic way to deal with cycles is, but I
> cannot understand why, *if* a Condorcet winner exists, how *any* other
> method; Hare, Borda, Bucklin, or Kirslis is more democratic than Condorcet.
>
> If a CW exists and we *know* (from the Cast Vote Record having ranked
> ballot data) that the CW exists and who that CW is, how is electing the
> K-count winner, assuming they're different from the CW, more democratic?
> Just like with the IRV failures, we will *know* that a smaller set of
> voters have left that election satisfied than that of a larger set of
> voters leaving the election dissatisfied. We will know that the votes
> coming from that smaller set of voters were more effective in electing
> their preferred candidate than the votes coming from the larger set of
> voters that not only preferred someone else, but they preferred a
> *specific* candidate over the one who Kirslis elected and marked their
> ballots saying so. For the very same reason that IRV failed in Burlington
> Vermont in 2009 or in Alaska in August 2022, the elected candidate will
> suffer a sense of loss of legitimacy in the election.
>
> In Burlington in 2009, 4064 voters marked their ballots that Candidate A
> was a better choice than Candidate B and 3476 voters marked their ballots
> to the contrary. (There were 1436 voters that didn't like either A or B
> and didn't rank either.) How *possibly* can Candidate B be elected without
> counting those 3476 voters' individual votes a little more (like 17% more)
> than how much the votes were counted from the 4064 voters preferring
> Candidate A?
>
> Now this is a failure of Hare (IRV) but I can construct the very same
> question for an election decided with Kirslis rules that failed to elect
> the CW when such exists. How would you answer that question? How do you
> justify satisfying a smaller set of voters at the expense of a larger set
> of voters that preferred, not just anyone else, but a specific candidate
> over the Kirslis winner? I couldn't glean an answer to that from section 9
> (or anywhere else) in your paper.
>
> bestest,
>
> --
>
> r b-j . _ . _ . _ . _ rbj@audioimagination.com
>
> "Imagination is more important than knowledge."
>
> .
> .
> .
>
> > On 05/18/2025 1:51 PM EDT Daniel Kirslis via Election-Methods <
> election-methods@lists.electorama.com> wrote:
> >
> >
> > Hi all,
> >
> > Thanks so much for the replies. I’ll respond to everyone in this thread.
> >
> > Andy - I really appreciate your feedback. Your summary is correct, and
> your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
> thinking about it that I had not considered. It seems like a potentially
> fruitful lens for understanding it. And, as perhaps you have surmised, I
> may have been mistaken in the statement about the sincere favorite
> criteria, but I am working on an analysis of the issue that I will share.
> >
> > Toby, making a short summary is a great suggestion. The argument in the
> paper is admittedly a bit convoluted before it presents the actual method.
> Here is the simplified way that I would explain it:
> >
> > Each voter ranks their preferences, with ties allowed and unranked
> candidates treated as last-place preferences. Then, for each candidate, you
> make a plot, where each axis is the total number of times that they were
> preferred to each of their opponents. So, if the candidates are A, B, and
> C, candidate A’s plot would have “number of times preferred to B” on one
> axis and “number of times preferred to C” on the other axis. Candidate B &
> C could be plotted similarly in terms of their opponents. The winner is
> simply the candidate who is plotted the farthest up and to the right, or
> closest to topmost and rightmost point, which is where a candidate who is
> the unanimous first-place choice would be plotted. The distance from that
> point is calculated using the Pythagorean theorem, which is where
> minimizing the sum of squares that Andy referenced comes in.
> >
> > The figures in the paper tell the story better than the words, as it is
> essentially a geometric idea. And, sections 4, 5, and 6 can really be
> skipped - they are more about justifying the approach than explaining it.
> >
> > Chris, you asked “Why should we be interested in the "concerns" of Borda
> (whatever they are)? And so much that we should embrace a method that fails
> the Condorcet criterion?” Great question. If you look at the Stanford
> Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
> Condorcet and Borda as the original pioneers of this thinking (
> https://plato.stanford.edu/entries/social-choice/). Borda thinks about
> majoritarianism in terms of votes, while Condorcet thinks about it in terms
> of voters. Obviously, in FPP elections, these are the same, but the heart
> of the interest in these questions comes from the tension that arises
> between them in a ranked-choice setting, where each voter has multiple
> votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
> thinker who studies these issues and has argued most persuasively for
> Borda’s approach over Condorcet methods. In section 9 of my paper, I
> explain some of my philosophical objections to the Condorcet winner
> criterion.
> >
> > You also asked “Do you propose allowing above-bottom equal ranking or
> truncation?” Equal ranking is allowed, and unranked candidates are treated
> as last place.
> >
> > And, I am afraid I may have actually been mistaken about the sincere
> favorite property, so will have to disappoint you there.
> >
> > You asked “Who does your method elect in this example?
> >
> > 46 A
> > 44 B>C
> > 10 C”
> >
> > If I am understanding your notation correctly, A would win in this
> example. The full ranking would be:
> > A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
> > B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
> > C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
> >
> > As you can see, when a candidate only appears as a first-place or
> last-place preference, their K-count is simply equal to the number of
> voters ranking them first.
> >
> > Thanks all!
> >
> >
> > On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
> elections@jenningsstory.com> wrote:
> > > Hi Dan,
> > >
> > > Great paper. Thank you for posting!
> > >
> > > It seems like the short version is that the winner is the candidate
> with the smallest sum of SQUARES of non-victories (defeats plus ties)
> against their opponents.
> > >
> > > Taking the square root and dividing can make it meaningful by scaling
> it to [0,1] or [0,s] (where s is the number of voters), but doesn't change
> the finish order.
> > >
> > >
> > > It does seem like an interesting attempt to "square the circle" (great
> pun) and compromise between Borda and Condorcet. I hadn't realized that
> Borda and Minimax are minimizing the one-norm and infinity-norm in the same
> geometric space. The two-norm certainly seems like it should be explored.
> > >
> > > I would love to see the proof of non-favorite-betrayal.
> > >
> > > Best,
> > >
> > > ~ Andy
> > > On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
> Election-Methods <election-methods@lists.electorama.com> wrote:
> > >
> > > > Hello!
> > > >
> > > > I am a newcomer to this mailing list, so please forgive me if this
> message violates any norms or protocols that the members of this list
> adhere to.
> > > >
> > > > I have recently developed a novel method for tabulating
> ranked-choice elections that attempts to reconcile the concerns of Borda
> and Condorcet. I believe that it maintains the simplicity and mathematical
> elegance of the Borda count while incorporating Condorcet's concern with
> pairwise dominance. Intuitively, it can be understood as ordering
> candidates by how close they come to being unanimously selected when
> plotted in Cartesian coordinate space. Here is a link to the paper:
> > > >
> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
> > > >
> > > > Given its simplicity, I have been very surprised to discover that
> this method has never been proposed before. I am hoping that some of you
> all will take a look at the paper and share your comments, questions, and
> critiques. Ultimately, it is my hope that ranked-choice voting advocates
> can arrive at a consensus about the best method for RCV and thus strengthen
> efforts to adopt it and deliver much needed democratic improvements. But
> even if you don't find the system itself compelling, you may find the
> method of plotting electoral outcomes elucidated in the paper to be useful
> for the analysis of other electoral systems.
> > > >
> > > > Thank you!
> > > >
> > > > -Dan
> > >
> > >
> > ----
> > Election-Methods mailing list - see https://electorama.com/em for list
> info
> ----
> Election-Methods mailing list - see https://electorama.com/em for list
> info
>
DK
Daniel Kirslis
Sun, May 18, 2025 11:58 PM
Hi Chris,
I certainly did not mean to cause any offence with that comment. I
understand that the paper itself is not at all simple or accessible, and my
attempt at summarizing it on a busy Sunday afternoon is perhaps not a
paragon of clarity. However, though my explanations are not the best, I do
hold onto the belief that the idea itself, when understood geometrically,
is simple. You choose the candidate whose vote totals are the closest to
unanimous selection when plotted on a graph. I do think that most voters
are familiar with 2-dimensional graphs, from which the core idea can be
understood. I don't think that at its core this method is any more
complicated for the average voter to understand than many of the other
ranked choice electoral methods, some of which can become quite intricate.
Again, I acknowledge that my paper and explanations are not easy to
understand, but I think that is a failure of my communication skills, not
of the method itself. I'll keep working on expressing the idea more simply.
-Dan
On Sun, May 18, 2025 at 3:58 PM Chris Benham via Election-Methods <
election-methods@lists.electorama.com> wrote:
Daniel,
So according to you, this method is so childishly "simple" that you can't
understand why no-one has thought of it before, but it can't be explained
without reference to geometry, graphs, square roots and "the Pythagorean
theorem".
Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each candidate, you
make a plot, where each axis is the total number of times that they were
preferred to each of their opponents. So, if the candidates are A, B, and
C, candidate A’s plot would have “number of times preferred to B” on one
axis and “number of times preferred to C” on the other axis. Candidate B &
C could be plotted similarly in terms of their opponents. The winner is
simply the candidate who is plotted the farthest up and to the right, or
closest to topmost and rightmost point, which is where a candidate who is
the unanimous first-place choice would be plotted. The distance from that
point is calculated using the Pythagorean theorem, which is where
minimizing the sum of squares that Andy referenced comes in.
I think that there are many people in the US (and elsewhere) who have no
background in Maths or Geometry and so don't understand any Math-ese , even
some who are interested in election methods.
Is this really your best attempt to explain how the method works to them??
Chris
On 19/05/2025 3:21 am, Daniel Kirslis via Election-Methods wrote:
Hi all,
Thanks so much for the replies. I’ll respond to everyone in this thread.
Andy - I really appreciate your feedback. Your summary is correct, and
your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
thinking about it that I had not considered. It seems like a potentially
fruitful lens for understanding it. And, as perhaps you have surmised, I
may have been mistaken in the statement about the sincere favorite
criteria, but I am working on an analysis of the issue that I will share.
Toby, making a short summary is a great suggestion. The argument in the
paper is admittedly a bit convoluted before it presents the actual method.
Here is the simplified way that I would explain it:
- Each voter ranks their preferences, with ties allowed and unranked
candidates treated as last-place preferences. Then, for each candidate, you
make a plot, where each axis is the total number of times that they were
preferred to each of their opponents. So, if the candidates are A, B, and
C, candidate A’s plot would have “number of times preferred to B” on one
axis and “number of times preferred to C” on the other axis. Candidate B &
C could be plotted similarly in terms of their opponents. The winner is
simply the candidate who is plotted the farthest up and to the right, or
closest to topmost and rightmost point, which is where a candidate who is
the unanimous first-place choice would be plotted. The distance from that
point is calculated using the Pythagorean theorem, which is where
minimizing the sum of squares that Andy referenced comes in.*
The figures in the paper tell the story better than the words, as it is
essentially a geometric idea. And, sections 4, 5, and 6 can really be
skipped - they are more about justifying the approach than explaining it.
Chris, you asked “Why should we be interested in the "concerns" of
Borda (whatever they are)? And so much that we should embrace a method that
fails the Condorcet criterion?” Great question. If you look at the Stanford
Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
Condorcet and Borda as the original pioneers of this thinking (
https://plato.stanford.edu/entries/social-choice/). Borda thinks about
majoritarianism in terms of votes, while Condorcet thinks about it in terms
of voters. Obviously, in FPP elections, these are the same, but the heart
of the interest in these questions comes from the tension that arises
between them in a ranked-choice setting, where each voter has multiple
votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
thinker who studies these issues and has argued most persuasively for
Borda’s approach over Condorcet methods. In section 9 of my paper, I
explain some of my philosophical objections to the Condorcet winner
criterion.
You also asked “Do you propose allowing above-bottom equal ranking or
truncation?” Equal ranking is allowed, and unranked candidates are treated
as last place.
And, I am afraid I may have actually been mistaken about the sincere
favorite property, so will have to disappoint you there.
You asked “Who does your method elect in this example?
46 A
44 B>C
10 C”
If I am understanding your notation correctly, A would win in this
example. The full ranking would be:
A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
As you can see, when a candidate only appears as a first-place or
last-place preference, their K-count is simply equal to the number of
voters ranking them first.
Thanks all!
On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
elections@jenningsstory.com> wrote:
Hi Dan,
Great paper. Thank you for posting!
It seems like the short version is that the winner is the candidate with
the smallest sum of SQUARES of non-victories (defeats plus ties) against
their opponents.
Taking the square root and dividing can make it meaningful by scaling it
to [0,1] or [0,s] (where s is the number of voters), but doesn't change the
finish order.
It does seem like an interesting attempt to "square the circle" (great
pun) and compromise between Borda and Condorcet. I hadn't realized that
Borda and Minimax are minimizing the one-norm and infinity-norm in the same
geometric space. The two-norm certainly seems like it should be explored.
I would love to see the proof of non-favorite-betrayal.
Best,
~ Andy
On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
Election-Methods election-methods@lists.electorama.com wrote:
Hello!
I am a newcomer to this mailing list, so please forgive me if this
message violates any norms or protocols that the members of this list
adhere to.
I have recently developed a novel method for tabulating ranked-choice
elections that attempts to reconcile the concerns of Borda and Condorcet. I
believe that it maintains the simplicity and mathematical elegance of the
Borda count while incorporating Condorcet's concern with pairwise
dominance. Intuitively, it can be understood as ordering candidates by how
close they come to being unanimously selected when plotted in Cartesian
coordinate space. Here is a link to the paper:
https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
Given its simplicity, I have been very surprised to discover that this
method has never been proposed before. I am hoping that some of you all
will take a look at the paper and share your comments, questions, and
critiques. Ultimately, it is my hope that ranked-choice voting advocates
can arrive at a consensus about the best method for RCV and thus strengthen
efforts to adopt it and deliver much needed democratic improvements. But
even if you don't find the system itself compelling, you may find the
method of plotting electoral outcomes elucidated in the paper to be useful
for the analysis of other electoral systems.
Thank you!
-Dan
Hi Chris,
I certainly did not mean to cause any offence with that comment. I
understand that the paper itself is not at all simple or accessible, and my
attempt at summarizing it on a busy Sunday afternoon is perhaps not a
paragon of clarity. However, though my explanations are not the best, I do
hold onto the belief that the idea itself, when understood geometrically,
is simple. You choose the candidate whose vote totals are the closest to
unanimous selection when plotted on a graph. I do think that most voters
are familiar with 2-dimensional graphs, from which the core idea can be
understood. I don't think that at its core this method is any more
complicated for the average voter to understand than many of the other
ranked choice electoral methods, some of which can become quite intricate.
Again, I acknowledge that my paper and explanations are not easy to
understand, but I think that is a failure of my communication skills, not
of the method itself. I'll keep working on expressing the idea more simply.
-Dan
On Sun, May 18, 2025 at 3:58 PM Chris Benham via Election-Methods <
election-methods@lists.electorama.com> wrote:
> Daniel,
>
> So according to you, this method is so childishly "simple" that you can't
> understand why no-one has thought of it before, but it can't be explained
> without reference to geometry, graphs, square roots and "the Pythagorean
> theorem".
>
> *Each voter ranks their preferences, with ties allowed and unranked
> candidates treated as last-place preferences. Then, for each candidate, you
> make a plot, where each axis is the total number of times that they were
> preferred to each of their opponents. So, if the candidates are A, B, and
> C, candidate A’s plot would have “number of times preferred to B” on one
> axis and “number of times preferred to C” on the other axis. Candidate B &
> C could be plotted similarly in terms of their opponents. The winner is
> simply the candidate who is plotted the farthest up and to the right, or
> closest to topmost and rightmost point, which is where a candidate who is
> the unanimous first-place choice would be plotted. The distance from that
> point is calculated using the Pythagorean theorem, which is where
> minimizing the sum of squares that Andy referenced comes in.*
>
>
> I think that there are many people in the US (and elsewhere) who have no
> background in Maths or Geometry and so don't understand any Math-ese , even
> some who are interested in election methods.
>
> Is this really your best attempt to explain how the method works to them??
>
> Chris
>
> On 19/05/2025 3:21 am, Daniel Kirslis via Election-Methods wrote:
>
> Hi all,
>
> Thanks so much for the replies. I’ll respond to everyone in this thread.
>
> *Andy* - I really appreciate your feedback. Your summary is correct, and
> your framing of it as one-norm vs. two-norm vs. infinity-norm is a way of
> thinking about it that I had not considered. It seems like a potentially
> fruitful lens for understanding it. And, as perhaps you have surmised, I
> may have been mistaken in the statement about the sincere favorite
> criteria, but I am working on an analysis of the issue that I will share.
>
> *Toby*, making a short summary is a great suggestion. The argument in the
> paper is admittedly a bit convoluted before it presents the actual method.
> Here is the simplified way that I would explain it:
>
> * Each voter ranks their preferences, with ties allowed and unranked
> candidates treated as last-place preferences. Then, for each candidate, you
> make a plot, where each axis is the total number of times that they were
> preferred to each of their opponents. So, if the candidates are A, B, and
> C, candidate A’s plot would have “number of times preferred to B” on one
> axis and “number of times preferred to C” on the other axis. Candidate B &
> C could be plotted similarly in terms of their opponents. The winner is
> simply the candidate who is plotted the farthest up and to the right, or
> closest to topmost and rightmost point, which is where a candidate who is
> the unanimous first-place choice would be plotted. The distance from that
> point is calculated using the Pythagorean theorem, which is where
> minimizing the sum of squares that Andy referenced comes in.*
>
> The figures in the paper tell the story better than the words, as it is
> essentially a geometric idea. And, sections 4, 5, and 6 can really be
> skipped - they are more about justifying the approach than explaining it.
>
> *Chris*, you asked “Why should we be interested in the "concerns" of
> Borda (whatever they are)? And so much that we should embrace a method that
> fails the Condorcet criterion?” Great question. If you look at the Stanford
> Encyclopedia of Philosophy’s entry on Social Choice Theory, they list
> Condorcet and Borda as the original pioneers of this thinking (
> https://plato.stanford.edu/entries/social-choice/). Borda thinks about
> majoritarianism in terms of votes, while Condorcet thinks about it in terms
> of voters. Obviously, in FPP elections, these are the same, but the heart
> of the interest in these questions comes from the tension that arises
> between them in a ranked-choice setting, where each voter has multiple
> votes and ‘majoritarianism’ is no longer simple to define. Don Saari is a
> thinker who studies these issues and has argued most persuasively for
> Borda’s approach over Condorcet methods. In section 9 of my paper, I
> explain some of my philosophical objections to the Condorcet winner
> criterion.
>
> You also asked “Do you propose allowing above-bottom equal ranking or
> truncation?” Equal ranking is allowed, and unranked candidates are treated
> as last place.
>
> And, I am afraid I may have actually been mistaken about the sincere
> favorite property, so will have to disappoint you there.
>
> You asked “Who does your method elect in this example?
>
> 46 A
> 44 B>C
> 10 C”
>
> If I am understanding your notation correctly, A would win in this
> example. The full ranking would be:
> A's K-count = 46 = 100-SQRT((100-46)^2+(100-46)^2)/(SQRT(2))
> B's K-count = 44 = 100-SQRT((100-44)^2+(100-44)^2)/(SQRT(2))
> C's K-count = 28.53 = 100-SQRT((100-54)^2+(100-10)^2)/(SQRT(2))
>
> As you can see, when a candidate only appears as a first-place or
> last-place preference, their K-count is simply equal to the number of
> voters ranking them first.
>
> Thanks all!
>
> On Sun, May 18, 2025 at 12:10 PM Andrew B Jennings (elections) <
> elections@jenningsstory.com> wrote:
>
>> Hi Dan,
>>
>> Great paper. Thank you for posting!
>>
>> It seems like the short version is that the winner is the candidate with
>> the smallest sum of SQUARES of non-victories (defeats plus ties) against
>> their opponents.
>>
>> Taking the square root and dividing can make it meaningful by scaling it
>> to [0,1] or [0,s] (where s is the number of voters), but doesn't change the
>> finish order.
>>
>> It does seem like an interesting attempt to "square the circle" (great
>> pun) and compromise between Borda and Condorcet. I hadn't realized that
>> Borda and Minimax are minimizing the one-norm and infinity-norm in the same
>> geometric space. The two-norm certainly seems like it should be explored.
>>
>> I would love to see the proof of non-favorite-betrayal.
>>
>> Best,
>>
>> ~ Andy
>> On Thursday, May 15th, 2025 at 4:25 PM, Daniel Kirslis via
>> Election-Methods <election-methods@lists.electorama.com> wrote:
>>
>> Hello!
>>
>> I am a newcomer to this mailing list, so please forgive me if this
>> message violates any norms or protocols that the members of this list
>> adhere to.
>>
>> I have recently developed a novel method for tabulating ranked-choice
>> elections that attempts to reconcile the concerns of Borda and Condorcet. I
>> believe that it maintains the simplicity and mathematical elegance of the
>> Borda count while incorporating Condorcet's concern with pairwise
>> dominance. Intuitively, it can be understood as ordering candidates by how
>> close they come to being unanimously selected when plotted in Cartesian
>> coordinate space. Here is a link to the paper:
>>
>> https://drive.google.com/file/d/152eNheS2qkLHJbDvG4EwW3jdO4I_NwcX/view?usp=sharing
>>
>> Given its simplicity, I have been very surprised to discover that this
>> method has never been proposed before. I am hoping that some of you all
>> will take a look at the paper and share your comments, questions, and
>> critiques. Ultimately, it is my hope that ranked-choice voting advocates
>> can arrive at a consensus about the best method for RCV and thus strengthen
>> efforts to adopt it and deliver much needed democratic improvements. But
>> even if you don't find the system itself compelling, you may find the
>> method of plotting electoral outcomes elucidated in the paper to be useful
>> for the analysis of other electoral systems.
>>
>> Thank you!
>>
>> -Dan
>>
>>
>>
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