Hallo,
on the other side, the simulations have also shown that
the worst pairwise defeat of the Schulze winner is usually
weaker than the worst defeat of the MAM winner.
Norman Petry writes: "Schulze and Smith//PC are in agreement
on the choice of winner over 90% of the time, regardless of
the size of the Smith set, whereas Tideman's method diverges
in its choices as the size of the Smith set increases."
http://lists.electorama.com/pipermail/election-methods-electorama.com/2000-November/069868.html
https://www.mail-archive.com/election-methods-list@eskimo.com/msg02310.html
https://groups.yahoo.com/neo/groups/election-methods-list/conversations/topics/5948
Jobst Heitzig writes: "Note that Beatpath and Plain Condorcet
are unanimous in all these examples!"
http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-May/078166.html
https://groups.yahoo.com/neo/groups/election-methods-list/conversations/messages/14251
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand." "We do notice that Least Worst Defeat and
Schulze continue to show a very coherent response, agreeing
in nearly ninety-nine percent of all elections through
seven candidates."
Markus Schulze
(Replying farther down)
On Oct 5, 2016 11:13 AM, "Markus Schulze" <
markus.schulze@alumni.tu-berlin.de> wrote:
Hallo,
on the other side, the simulations have also shown that
the worst pairwise defeat of the Schulze winner is usually
weaker than the worst defeat of the MAM winner.
(endquote )
The MAM winner has no defeats that aren't nullified by being the weakest
defeat in a cycle whose other defeats are affirmed.
...and those affirmed stronger defeats are affirmed because that can't be
said of them.
Additionally, I remind you that our topic is MAM vs Schulze. Therefore the
pairwise comparison most relevant here is the pairwise comparison between
MAM & Schulze. ...a comparison which MAM wins several times more often
than Schulze does.
Michael Ossipoff
Norman Petry writes: "Schulze and Smith//PC are in agreement
on the choice of winner over 90% of the time, regardless of
the size of the Smith set, whereas Tideman's method diverges
in its choices as the size of the Smith set increases."
Jobst Heitzig writes: "Note that Beatpath and Plain Condorcet
are unanimous in all these examples!"
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand." "We do notice that Least Worst Defeat and
Schulze continue to show a very coherent response, agreeing
in nearly ninety-nine percent of all elections through
seven candidates."
Marcus,
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand."
In the 3-candidate case, how can "Least Worst Defeat" (aka MinMax ?) and
Schulze ever disagree?
As I understand it, Schulze and MAM and River and Smith//MinMax can
only ever give different winners when
there are more than three candidates in the Smith set.
That chance of that happening in a real public election is close enough
to zero, so therefore "MAM versus Shulze"
strikes me as pointless.
And if it didn't I wouldn't find the argument that one's winner pairwise
beats the other's a small proportion of times more
than vice versa very compelling.
Chris Benham
On 10/6/2016 4:43 AM, Markus Schulze wrote:
Hallo,
on the other side, the simulations have also shown that
the worst pairwise defeat of the Schulze winner is usually
weaker than the worst defeat of the MAM winner.
Norman Petry writes: "Schulze and Smith//PC are in agreement
on the choice of winner over 90% of the time, regardless of
the size of the Smith set, whereas Tideman's method diverges
in its choices as the size of the Smith set increases."
http://lists.electorama.com/pipermail/election-methods-electorama.com/2000-November/069868.html
https://www.mail-archive.com/election-methods-list@eskimo.com/msg02310.html
https://groups.yahoo.com/neo/groups/election-methods-list/conversations/topics/5948
Jobst Heitzig writes: "Note that Beatpath and Plain Condorcet
are unanimous in all these examples!"
http://lists.electorama.com/pipermail/election-methods-electorama.com/2004-May/078166.html
https://groups.yahoo.com/neo/groups/election-methods-list/conversations/messages/14251
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand." "We do notice that Least Worst Defeat and
Schulze continue to show a very coherent response, agreeing
in nearly ninety-nine percent of all elections through
seven candidates."
Markus Schulze
Election-Methods mailing list - see http://electorama.com/em for list
info
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10/05/16
I agree. I don't find it compelling at all. For any deterministic Condorcet method, I could devise another one where the winner pairwise beats the winner of that one more often than vice versa. Someone could have a method they call BEST METHOD. Then all I have to do is say under my new method, elect the Condorcet winner if there is one. If there isn't, elect a candidate that pairwise beats the winner using BEST METHOD, if there is one (pick at random if there's more than one). Otherwise just pick the same winner as BEST METHOD.
From: C.Benham <cbenham@adam.com.au>
To: election-methods@lists.electorama.com
Sent: Thursday, 6 October 2016, 4:26
Subject: Re: [EM] MAM vs Schulze
Marcus,
That chance of that happening in a real public election is close enough to zero, so therefore "MAM versus Shulze"
strikes me as pointless.
And if it didn't I wouldn't find the argument that one's winner pairwise beats the other's a small proportion of times more
than vice versa very compelling.
Chris Benham
Chris--
Sure, the only reason to use MAM instead of MinMax is for if there's a
larger Smith set.
We could propose MinMax, and assure people that the situations where it
fails MAM's criteria will never happen.
I guess "Don't worry, it will never happen" is what FairVote assured people
in Burlington.
Is that a good idea?
And so, it's on the assumption that there could be a Smith set with more
than 3 candidates, that we speak of how MAM & Schulze differ.
So, if it will be rare for them to differ, does that mean that we should
propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose other
defeats are affirmed.
Though CIVS never has a top cycle for 1st finisher, it often has them
farther down in the finishing order.
I've only looked at the Smith-set of one of those: the poll regarding laws
for bigamy.
It's Smith-set was approaching around 10 when I stopped counting. ( The
cycle was far down in the finishing order).
Maybe short rankings caused that result, or maybe the 1-D spectrum
assumption doesn't hold for low finishing positions.
Michael Ossipoff
Marcus,
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand."
In the 3-candidate case, how can "Least Worst Defeat" (aka MinMax ?) and
Schulze ever disagree?
As I understand it, Schulze and MAM and River and Smith//MinMax can only
ever give different winners when
there are more than three candidates in the Smith set.
That chance of that happening in a real public election is close enough to
zero, so therefore "MAM versus Shulze"
strikes me as pointless.
And if it didn't I wouldn't find the argument that one's winner pairwise
beats the other's a small proportion of times more
than vice versa very compelling.
Chris Benham
On 10/6/2016 4:43 AM, Markus Schulze wrote:
Hallo,
on the other side, the simulations have also shown that
the worst pairwise defeat of the Schulze winner is usually
weaker than the worst defeat of the MAM winner.
Norman Petry writes: "Schulze and Smith//PC are in agreement
on the choice of winner over 90% of the time, regardless of
the size of the Smith set, whereas Tideman's method diverges
in its choices as the size of the Smith set increases."
http://lists.electorama.com/pipermail/election-methods-
electorama.com/2000-November/069868.html
https://www.mail-archive.com/election-methods-list@eskimo.com/msg02310.html
https://groups.yahoo.com/neo/groups/election-methods-list/
conversations/topics/5948
Jobst Heitzig writes: "Note that Beatpath and Plain Condorcet
are unanimous in all these examples!"
http://lists.electorama.com/pipermail/election-methods-
electorama.com/2004-May/078166.html
https://groups.yahoo.com/neo/groups/election-methods-list/
conversations/messages/14251
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand." "We do notice that Least Worst Defeat and
Schulze continue to show a very coherent response, agreeing
in nearly ninety-nine percent of all elections through
seven candidates."
https://services.math.duke.edu/~bray/Courses/49s-GTD/Senior%20Theses/Barry%
20Wright/Barry%20Wright's%20Thesis.pdf
Markus Schulze
Election-Methods mailing list - see http://electorama.com/em for list info
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No, it wasn't the polygamy poll that I looked at. It only has 5
alternatives.
It was one of the others. I don't know which one.
Michael Ossipoff
On Oct 6, 2016 9:33 AM, "Michael Ossipoff" email9648742@gmail.com wrote:
Chris--
Sure, the only reason to use MAM instead of MinMax is for if there's a
larger Smith set.
We could propose MinMax, and assure people that the situations where it
fails MAM's criteria will never happen.
I guess "Don't worry, it will never happen" is what FairVote assured
people in Burlington.
Is that a good idea?
And so, it's on the assumption that there could be a Smith set with more
than 3 candidates, that we speak of how MAM & Schulze differ.
So, if it will be rare for them to differ, does that mean that we should
propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose other
defeats are affirmed.
Though CIVS never has a top cycle for 1st finisher, it often has them
farther down in the finishing order.
I've only looked at the Smith-set of one of those: the poll regarding laws
for bigamy.
It's Smith-set was approaching around 10 when I stopped counting. ( The
cycle was far down in the finishing order).
Maybe short rankings caused that result, or maybe the 1-D spectrum
assumption doesn't hold for low finishing positions.
Michael Ossipoff
Marcus,
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand."
In the 3-candidate case, how can "Least Worst Defeat" (aka MinMax ?) and
Schulze ever disagree?
As I understand it, Schulze and MAM and River and Smith//MinMax can only
ever give different winners when
there are more than three candidates in the Smith set.
That chance of that happening in a real public election is close enough to
zero, so therefore "MAM versus Shulze"
strikes me as pointless.
And if it didn't I wouldn't find the argument that one's winner pairwise
beats the other's a small proportion of times more
than vice versa very compelling.
Chris Benham
On 10/6/2016 4:43 AM, Markus Schulze wrote:
Hallo,
on the other side, the simulations have also shown that
the worst pairwise defeat of the Schulze winner is usually
weaker than the worst defeat of the MAM winner.
Norman Petry writes: "Schulze and Smith//PC are in agreement
on the choice of winner over 90% of the time, regardless of
the size of the Smith set, whereas Tideman's method diverges
in its choices as the size of the Smith set increases."
http://lists.electorama.com/pipermail/election-methods-elect
orama.com/2000-November/069868.html
https://www.mail-archive.com/election-methods-list@eskimo.co
m/msg02310.html
https://groups.yahoo.com/neo/groups/election-methods-list/co
nversations/topics/5948
Jobst Heitzig writes: "Note that Beatpath and Plain Condorcet
are unanimous in all these examples!"
http://lists.electorama.com/pipermail/election-methods-elect
orama.com/2004-May/078166.html
https://groups.yahoo.com/neo/groups/election-methods-list/co
nversations/messages/14251
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand." "We do notice that Least Worst Defeat and
Schulze continue to show a very coherent response, agreeing
in nearly ninety-nine percent of all elections through
seven candidates."
https://services.math.duke.edu/~bray/Courses/49s-GTD/Senior%
20Theses/Barry%20Wright/Barry%20Wright's%20Thesis.pdf
Markus Schulze
Election-Methods mailing list - see http://electorama.com/em for list
info
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It was probably my 23-candidate, 19-party 2016 presidential poll.
By the way, without Bernie, Jill Stein is CWv, beating everyone by a large
factor.
Trump finished at bottom among the original candidates (the two write-ins
were too recent to have a chance to get much support).
Jill beat Donald by a factor of several to one.
The lowest-finishing socialist best Trump by a factor of 2 to 1.
The lowest finishing socialist beat the highest-finishing Republican by a
factor of 1.5 to 1.
Sampling bias? With Jill finishing 1st & Donald finishing last, will you
say that sampling bias justifies saying that Trump might beat Stein in an
honest election with honest media? That would take rather a lot of sampling
bias.
:^)
...because only some have computers? People who have more money are known
to be more conservative.
Yes, some polls show Hillary beating Jill. In my poll, Hillary finished 5th.
Drastic differences like that must result from different electorates.
..the poll being announced to different people.
...to partisan organizations in particular.
My poll was announced only at the polling website (CIVS), and at Democracy
Chronicles.
...not to any partisan organizations.
Michael Ossipoff
On Oct 6, 2016 10:22 AM, "Michael Ossipoff" email9648742@gmail.com wrote:
No, it wasn't the polygamy poll that I looked at. It only has 5
alternatives.
It was one of the others. I don't know which one.
Michael Ossipoff
On Oct 6, 2016 9:33 AM, "Michael Ossipoff" email9648742@gmail.com wrote:
Chris--
Sure, the only reason to use MAM instead of MinMax is for if there's a
larger Smith set.
We could propose MinMax, and assure people that the situations where it
fails MAM's criteria will never happen.
I guess "Don't worry, it will never happen" is what FairVote assured
people in Burlington.
Is that a good idea?
And so, it's on the assumption that there could be a Smith set with more
than 3 candidates, that we speak of how MAM & Schulze differ.
So, if it will be rare for them to differ, does that mean that we should
propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose
other defeats are affirmed.
Though CIVS never has a top cycle for 1st finisher, it often has them
farther down in the finishing order.
I've only looked at the Smith-set of one of those: the poll regarding
laws for bigamy.
It's Smith-set was approaching around 10 when I stopped counting. ( The
cycle was far down in the finishing order).
Maybe short rankings caused that result, or maybe the 1-D spectrum
assumption doesn't hold for low finishing positions.
Michael Ossipoff
Marcus,
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand."
In the 3-candidate case, how can "Least Worst Defeat" (aka MinMax ?) and
Schulze ever disagree?
As I understand it, Schulze and MAM and River and Smith//MinMax can
only ever give different winners when
there are more than three candidates in the Smith set.
That chance of that happening in a real public election is close enough
to zero, so therefore "MAM versus Shulze"
strikes me as pointless.
And if it didn't I wouldn't find the argument that one's winner pairwise
beats the other's a small proportion of times more
than vice versa very compelling.
Chris Benham
On 10/6/2016 4:43 AM, Markus Schulze wrote:
Hallo,
on the other side, the simulations have also shown that
the worst pairwise defeat of the Schulze winner is usually
weaker than the worst defeat of the MAM winner.
Norman Petry writes: "Schulze and Smith//PC are in agreement
on the choice of winner over 90% of the time, regardless of
the size of the Smith set, whereas Tideman's method diverges
in its choices as the size of the Smith set increases."
http://lists.electorama.com/pipermail/election-methods-elect
orama.com/2000-November/069868.html
https://www.mail-archive.com/election-methods-list@eskimo.co
m/msg02310.html
https://groups.yahoo.com/neo/groups/election-methods-list/co
nversations/topics/5948
Jobst Heitzig writes: "Note that Beatpath and Plain Condorcet
are unanimous in all these examples!"
http://lists.electorama.com/pipermail/election-methods-elect
orama.com/2004-May/078166.html
https://groups.yahoo.com/neo/groups/election-methods-list/co
nversations/messages/14251
Barry Wright writes: "[In the 3-candidate case] Least Worst
Defeat and Schulze [are] disagreeing on only three elections
per thousand." "We do notice that Least Worst Defeat and
Schulze continue to show a very coherent response, agreeing
in nearly ninety-nine percent of all elections through
seven candidates."
https://services.math.duke.edu/~bray/Courses/49s-GTD/Senior%
20Theses/Barry%20Wright/Barry%20Wright's%20Thesis.pdf
Markus Schulze
Election-Methods mailing list - see http://electorama.com/em for list
info
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Mike,
As far as I can tell, for all intents and purposes MAM, Schulze, River
and Smith//MinMax (wv) are all just different wordings
of the same method.
If you think that MAM is better than Shulze, then what criterion (that
we might care about) is met by MAM and not Shulze?
Or perhaps you have some example in mind where you think the MAM winner
is much prettier than the Schulze winner?
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose
other defeats are affirmed.
C: Is that definition fully adequate? It doesn't tell you where to start.
So, if it will be rare for them to differ, does that mean that we
should propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
C: Recently you accepted that Winning Votes is at best "maybe a bit
questionable", so why do you think that we should "propose" either?
If you want a Condorcet method that meets Chicken Dilemma then I
prefer both "Benham" and Losing Votes (erw) Sorted Margins Elimination.
If you want a method that (like WV) meets Minimal Defense then I prefer
Forest's "Max Covered Approval" (which would nearly always be equivalent
to Smith//Approval, which I also like.)
Chris Benham
On 10/7/2016 3:03 AM, Michael Ossipoff wrote:
Chris--
Sure, the only reason to use MAM instead of MinMax is for if there's a
larger Smith set.
We could propose MinMax, and assure people that the situations where
it fails MAM's criteria will never happen.
I guess "Don't worry, it will never happen" is what FairVote assured
people in Burlington.
Is that a good idea?
And so, it's on the assumption that there could be a Smith set with
more than 3 candidates, that we speak of how MAM & Schulze differ.
So, if it will be rare for them to differ, does that mean that we
should propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose
other defeats are affirmed.
Though CIVS never has a top cycle for 1st finisher, it often has them
farther down in the finishing order.
I've only looked at the Smith-set of one of those: the poll regarding
laws for bigamy.
It's Smith-set was approaching around 10 when I stopped counting. (
The cycle was far down in the finishing order).
Maybe short rankings caused that result, or maybe the 1-D spectrum
assumption doesn't hold for low finishing positions.
Michael Ossipoff
On 10/08/2016 03:06 PM, C.Benham wrote:
Mike,
As far as I can tell, for all intents and purposes MAM, Schulze, River
and Smith//MinMax (wv) are all just different wordings
of the same method.
If you think that MAM is better than Shulze, then what criterion (that
we might care about) is met by MAM and not Shulze?
Or perhaps you have some example in mind where you think the MAM winner
is much prettier than the Schulze winner?
I'm not Mike (and I don't see his posts), but I would probably say LIIA
for MAM and IPDA/ISDA for River. Those criteria probably only become
relevant (that is, failed by Schulze) when the Smith set size is large,
however, so whether you consider them important would depend in part on
whether you think large Smith sets may occur in real elections. On the
one hand, they haven't so far; on the other, adoption of a Condorcet
method might lead to a richer political landscape where they could.
MAM and River may also be simpler to explain than Schulze, since a brief
description of beatpaths require recursion, and recursion is a tricky
concept to get if you haven't already been exposed to it.
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose
other defeats are affirmed.
How about, for MAM:
Sort defeats in order from strongest to weakest. Going from strongest to
weakest, affirm a defeat unless it forms a cycle with earlier affirmed
defeats. The candidate who isn't beaten in any affirmed defeat wins.
Schulze:
A has a beatpath to B if A beats B or A beats someone who has a beatpath
to B. The strength of a beatpath is defined by the strength of its
weakest defeat. The candidate who, for every other candidate has a
stronger beatpath to that candidate than that candidate has to him, wins.
Neither definition goes into the subtlety of tiebreakers (random voter
hierarchy for MAM) nor margins vs wv.
If you want a method that (like WV) meets Minimal Defense then I prefer
Forest's "Max Covered Approval" (which would nearly always be equivalent
to Smith//Approval, which I also like.)
If you had to pick a method passing Minimal Defense but not using
Approval information, which would it be? (That is, do you have any
favorites in that category, and if so, which?)
On Oct 8, 2016 6:06 AM, "C.Benham" cbenham@adam.com.au wrote:
Mike,
As far as I can tell, for all intents and purposes MAM, Schulze, River
and Smith//MinMax (wv) are all just different wordings
of the same method.
No. They sometimes choose different winners.
If you think that MAM is better than Shulze, then what criterion (that
we might care about) is met by MAM and not Shulze?
Sometimes they choose the same, sometimes they don't.
When they don't, the MAM winner is publicly preferred to the Schulze winner
several times more often than vice-versa.
(It seems to me that it might have been something like 4 to 1, or 5 to 1.
Steve Eppley would be the one to ask.)
So: Choose in keeping with public preference, or contrary to it. Your choice
MAM's brief, natural & obvious definition is the opposite of the arbitrary
definition of Schulze or CSSD.
MAM's definition clearly is the one that doesn't unnecessarily disregard a
defeat.
It disregards a defeat only it's the weakest in a cycle with defeats for
which there isn't
justification to disregard them.
And, as I said, it's no surprise when unnecessarily disregarding defeats
results in a winner to whom the public prefer the MAM winner.
Or perhaps you have some example in mind where you think the MAM winner
is much prettier than the Schulze winner?
Publicly-preferred is prettier.
Minimally disregarding defeats only with obviousl, strong justification,
never unnecessarily disregarding a defeat--That's prettier.
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose
other defeats are affirmed.
C: Is that definition fully adequate?
Yes.
You wrote:
It doesn't tell you where to start.
It isn't a procedural definition or a count-instruction. It's a brief
recursive definition.
Given a set of rankings, it fully and definitely specifies a set of
affirmed defeats, & a set of not-affirmed defeats.
...and fully specifies the winner.
For a procedure:
Write down the strongest defeat.
Below it, write down the next strongest defeat.
Below that, write down the next strongest defeat, if it doesn't cycle with
defeats already written down.
Repeat the paragraph before this one, until all the defeats have been
considered as described in that paragraph.
A candidate wins if s/he has no written-down defeats.
(end of count instruction)
So, if it will be rare for them to differ, does that mean that we should
propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
C: Recently you accepted that Winning Votes is at best "maybe a bit
questionable", so why do you think that we should "propose" either?
(endquote)
I said they might be iffy or questionable. I didn't say they're ruled out.
For that questionable-ness, you get a chance for much better strategy.
...at the cost of the possibility of the strategic mess of the
perpetual-burial fiasco.
I'd say that MAM, Smith//MMPO, & plain MMPO are worth a try.
They should be included in a proposal that lists a number of suggested
methods.
In particular, for an unlimited-rankings method, Plain MMPO offers the
most, for current conditions.
If you want a Condorcet method that meets Chicken Dilemma then I prefer
both "Benham" and Losing Votes (erw) Sorted Margins Elimination.
(endquote)
They're far too vulnerable to truncation & burial.
In WV & MMPO, truncation just doesn't work. The CWs still wins.
The strategy situation of the methods you listed isn't as good as Bucklin.
Surely the purpose of a pairwise-count method is to improve on Bucklin.
In Bucklin & Approval, the CWs's preferrers can protect hir win by plumping.
In Benham, Woodall, & Margins-Sorted LV Elimination, the best they can do
is:
Say it's Worst (W), Middle (M), & Favorite (F).
M is the middle CWs.
The M voters could estimate or look up the expected sizes of the W & F
factions. ...& rank one over the other probabilistically, so that each
one's probability of pair-beating the other is 50%.
...so that burial has a 50% chance of backfiring.
In Bucklin, WV or MMPO, they need merely to plump.
Or the F voters could rank M alone in 1st place. That would work in IRV too
(nothing else would).
As I said, surely the purpose of a pairwise-count method is to improve on
Bucklin.
If you want a method that (like WV) meets Minimal Defense then I prefer
Forest's "Max Covered Approval" (which would nearly always be equivalent
to Smith//Approval, which I also like.)
Smith//Approval shares the great vulnerability to truncation & burial.
Michael Ossipoff
Chris Benham
On 10/7/2016 3:03 AM, Michael Ossipoff wrote:
Chris--
Sure, the only reason to use MAM instead of MinMax is for if there's a
larger Smith set.
We could propose MinMax, and assure people that the situations where it
fails MAM's criteria will never happen.
I guess "Don't worry, it will never happen" is what FairVote assured
people in Burlington.
Is that a good idea?
And so, it's on the assumption that there could be a Smith set with more
than 3 candidates, that we speak of how MAM & Schulze differ.
So, if it will be rare for them to differ, does that mean that we should
propose the more complicatedly-worded, elaborately- worded one?
...the less obviously, naturally and clearly motivated & justified one?
MAM's brief definition just says:
A defeat is affirmed if it isn't the weakest defeat in a cycle whose
other defeats are affirmed.
Though CIVS never has a top cycle for 1st finisher, it often has them
farther down in the finishing order.
I've only looked at the Smith-set of one of those: the poll regarding
laws for bigamy.
It's Smith-set was approaching around 10 when I stopped counting. ( The
cycle was far down in the finishing order).
Maybe short rankings caused that result, or maybe the 1-D spectrum
assumption doesn't hold for low finishing positions.
Michael Ossipoff