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Re: [EM] Name of this Criterion

MS
Markus Schulze
Sun, Apr 24, 2016 6:41 AM

Hallo,

sorry, but just on the surface this doesn't
seem right.

for instance, a run-of-the-mill no-cycle Condorcet
case (actually it was IRV and the Condorcet winner
did not win) would be the Burlington 2009 election
most of us are familiar with.  in that case M=5.
now if you picked k=3 and chose candidate A to be
Kurt Wright (who was the plurality winner and neither
the IRV winner nor the CW), there is a set of (k-1)
candidates (those would be Smith and Simpson) that
Wright beat consistently.  yet he is not the overall
winner.

you can go to the Warren Smith page or i can scarf
up the numbers from the defeat matrix again.

how am i reading this wrong?

For k=3, this criterion says that, when a candidate
wins every 3-way election, then this candidate should
also be the overall winner.

So to be able to apply this criterion to Kurt Wright,
he would also have to win a 3-way election between
himself and (say) Montroll and Kiss.

Markus Schulze

Hallo, > sorry, but just on the surface this doesn't > seem right. > > for instance, a run-of-the-mill no-cycle Condorcet > case (actually it was IRV and the Condorcet winner > did not win) would be the Burlington 2009 election > most of us are familiar with. in that case M=5. > now if you picked k=3 and chose candidate A to be > Kurt Wright (who was the plurality winner and neither > the IRV winner nor the CW), there is a set of (k-1) > candidates (those would be Smith and Simpson) that > Wright beat consistently. yet he is not the overall > winner. > > you can go to the Warren Smith page or i can scarf > up the numbers from the defeat matrix again. > > how am i reading this wrong? For k=3, this criterion says that, when a candidate wins every 3-way election, then this candidate should also be the overall winner. So to be able to apply this criterion to Kurt Wright, he would also have to win a 3-way election between himself and (say) Montroll and Kiss. Markus Schulze