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Re: [EM] PAR is awesome part 1/2: FBC?

JQ
Jameson Quinn
Sat, Nov 12, 2016 5:05 PM

2016-11-12 10:45 GMT-05:00 C.Benham cbenham@adam.com.au:

On 11/12/2016 7:53 AM, Jameson Quinn wrote:

2016-11-11 12:50 GMT-05:00 C.Benham cbenham@adam.com.au:

On 11/11/2016 10:14 PM, Jameson Quinn wrote:

I think that simple PAR is close enough to FBC compliance to be an
acceptable proposal.

I'm afraid I can't see any value in "close enough" to FBC compliance.
The point of FBC is to give an absolute guarantee to (possibly uninformed
and not strategically savvy)  greater-evil fearing voters.

Yes. The guarantee you can give is "as long as the world is somewhere in
this restricted domain — that is, essentially, as long as there are no
Condorcet cycles and each voter naturally rejects at least one of the 3
frontrunners — this method meets FBC". This is much broader than any
guarantee you could give for a typical non-FBC method. For instance, with
IRV, the best you could say would be "as long as your favorite is
eliminated early or wins overall, you don't have to betray them", which
unlike PAR's guarantee is not something which could ever be generally true
about all real elections for all factions.

C: I have in mind voters who are inclined to Compromise, and so it's *
absolute guarantee* or it's nothing.  Smith//Approval also has a much
lower Compromise incentive
than does IRV  (which in turn has a much much lower Compromise incentive
then FPP).

It elects the "correct" winner in a chicken dilemma scenario,
naive/honest/strategyless ballots, without a "slippery slope" (though of
course, this is no longer a strong Nash equilibrium).

How do you have a "chicken dilemma scenario" with
"naive/honest/strategyless ballots" ?

35: C >> A=B
33: A>B >> C
32: B >> A=C  (sincere is B>A >> C)

In this CD scenario your method elects B  in violation of the CD
criterion.

You're suggesting that the sincere preferences are

35: C >> A=B
33: A>B >> C
32: B>A >> C

C:  I'm not "suggesting". I'm stating.

If you are 1 of the B>A>>C voters considering whether to strategically
vote B>>A=C, you have no strong motivation to do so, because your vote
alone is not enough to shift the winner to B. This is what I mean by "no
slippery slope".

C: One "vote alone" is very rarely enough to do anything, so I suppose
no-one has a "strong motivation" to vote.

In Smith//approval, one vote alone would shift the above honest election;
so the fact that it does not in PAR is indeed notable.

In particular: in PAR, there is no way for the B voters to strategize such
that they win the above election, while still ensuring that C does not win
no matter what the A voters do. This "safe" strategizing is grease on the
slippery slope.

I believe that in the election you gave, there is no way to tell what the
sincere preferences are.

C: From just the information on the ballots, of course not (like any
election).

Perhaps the B voters are strategically truncating A; perhaps the C voters
are strategically truncating B. So the "correct winner" could be either A
or B, but is almost certainly not C.

C: By "correct winner" I assume you mean the sincere CW. But there is
reason to assume there is one. And if the B voters are actively Burying C,
it could be C.

The "CD criterion" requires the system to elect C, merely to punish the B
voters; I think that's perverse, because, among other things, it means that
a system does badly with center squeeze, allowing the C faction to
strategize and win.

C: No, it merely says "not B".  But CD + Plurality say that it must be C.

Since you are apparently now content to do without FBC  compliance  and
you imply that electing the CW is a good thing,
why don't you advocate a method that meets the Condorcet criterion?

What is wrong with Smith//Approval?  Or Forest's nearly equivalent Max
Covered Approval?

Largely, it's because I think that Condorcet systems are strategically
counterintuitive, and hard to present results in. I think that will lead to
more strategy than a system like PAR. That's because PAR can make
guarantees that Condorcet systems can't.

C: Such as?  What exactly does "strategically counter-intuitive" mean?  An
example?

What I mean is that if you take a non-election-theorist, present an
election scenario to them, explain who won and why, and ask how they would
strategize in the place of voter X, they are more likely to suggest
counterproductive strategies, and less likely to see any strategies that
actually might work, in Condorcet than in Bucklin-like systems.

In a system like MJ or Score, you can give a number to each candidate,
based on their own ratings alone, and the higher number wins. That is an
easy way to get monotonicity, FBC, and IIA.

In Condorcet, no candidate has any number except in relation to all other
candidates. That's good for passing the Condorcet criterion (obviously) but
it breaks FBC and IIA.

C:  Your method and MJ fail IIA.

MJ passes IIA. PAR fails it, as you say, but passes LIIA.

2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au>: > On 11/12/2016 7:53 AM, Jameson Quinn wrote: > > > > 2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au>: > >> On 11/11/2016 10:14 PM, Jameson Quinn wrote: >> >> I think that simple PAR is close enough to FBC compliance to be an >> acceptable proposal. >> >> >> I'm afraid I can't see any value in "close enough" to FBC compliance. >> The point of FBC is to give an absolute guarantee to (possibly uninformed >> and not strategically savvy) greater-evil fearing voters. >> > > Yes. The guarantee you can give is "as long as the world is somewhere in > this restricted domain — that is, essentially, as long as there are no > Condorcet cycles and each voter naturally rejects at least one of the 3 > frontrunners — this method meets FBC". This is much broader than any > guarantee you could give for a typical non-FBC method. For instance, with > IRV, the best you could say would be "as long as your favorite is > eliminated early or wins overall, you don't have to betray them", which > unlike PAR's guarantee is not something which could ever be generally true > about all real elections for all factions. > > C: I have in mind voters who are inclined to Compromise, and so it's * > absolute guarantee* or it's nothing. Smith//Approval also has a much > lower Compromise incentive > than does IRV (which in turn has a much much lower Compromise incentive > then FPP). > > > > >> >> It elects the "correct" winner in a chicken dilemma scenario, >> naive/honest/strategyless ballots, without a "slippery slope" (though of >> course, this is no longer a strong Nash equilibrium). >> >> >> How do you have a "chicken dilemma scenario" with >> "naive/honest/strategyless ballots" ? >> >> 35: C >> A=B >> 33: A>B >> C >> 32: B >> A=C (sincere is B>A >> C) >> >> In this CD scenario your method elects B in violation of the CD >> criterion. >> > > You're suggesting that the sincere preferences are > > 35: C >> A=B > 33: A>B >> C > 32: B>A >> C > > > C: I'm not "suggesting". I'm stating. > > > If you are 1 of the B>A>>C voters considering whether to strategically > vote B>>A=C, you have no strong motivation to do so, because your vote > alone is not enough to shift the winner to B. This is what I mean by "no > slippery slope". > > > C: One "vote alone" is very rarely enough to do anything, so I suppose > no-one has a "strong motivation" to vote. > In Smith//approval, one vote alone would shift the above honest election; so the fact that it does not in PAR is indeed notable. In particular: in PAR, there is no way for the B voters to strategize such that they win the above election, while still ensuring that C does not win no matter what the A voters do. This "safe" strategizing is grease on the slippery slope. > > > I believe that in the election you gave, there is no way to tell what the > sincere preferences are. > > > > C: From just the information on the ballots, of course not (like any > election). > > > Perhaps the B voters are strategically truncating A; perhaps the C voters > are strategically truncating B. So the "correct winner" could be either A > or B, but is almost certainly not C. > > > C: By "correct winner" I assume you mean the sincere CW. But there is > reason to assume there is one. And if the B voters are actively Burying C, > it could be C. > > The "CD criterion" requires the system to elect C, merely to punish the B > voters; I think that's perverse, because, among other things, it means that > a system does badly with center squeeze, allowing the C faction to > strategize and win. > > C: No, it merely says "not B". But CD + Plurality say that it must be C. > > > >> >> Since you are apparently now content to do without FBC compliance and >> you imply that electing the CW is a good thing, >> why don't you advocate a method that meets the Condorcet criterion? >> >> What is wrong with Smith//Approval? Or Forest's nearly equivalent Max >> Covered Approval? >> > > Largely, it's because I think that Condorcet systems are strategically > counterintuitive, and hard to present results in. I think that will lead to > more strategy than a system like PAR. That's because PAR can make > guarantees that Condorcet systems can't. > > C: Such as? What exactly does "strategically counter-intuitive" mean? An > example? > What I mean is that if you take a non-election-theorist, present an election scenario to them, explain who won and why, and ask how they would strategize in the place of voter X, they are more likely to suggest counterproductive strategies, and less likely to see any strategies that actually might work, in Condorcet than in Bucklin-like systems. > > In a system like MJ or Score, you can give a number to each candidate, > based on their own ratings alone, and the higher number wins. That is an > easy way to get monotonicity, FBC, and IIA. > > In Condorcet, no candidate has any number except in relation to all other > candidates. That's good for passing the Condorcet criterion (obviously) but > it breaks FBC and IIA. > > C: Your method and MJ fail IIA. > MJ passes IIA. PAR fails it, as you say, but passes LIIA.
C
C.Benham
Sun, Nov 13, 2016 11:34 AM

On 11/13/2016 3:35 AM, Jameson Quinn wrote:

What I mean is that if you take a non-election-theorist, present an
election scenario to them, explain who won and why, and ask how they
would strategize in the place of voter X, they are more likely to
suggest counterproductive strategies, and less likely to see any
strategies that actually might work, in Condorcet than in Bucklin-like
systems.

The strategy incentives for Condorcet voting methods vary widely. Some
have a random-fill incentive while others have a truncation incentive.
Some have
a stronger or weaker incentive to equal-top rank than others, and some
are more vulnerable to Burial than others.

Smith//Approval has a truncation incentive like Bucklin's, only less
strong. In addition Bucklin has an equal-top rank/rate incentive.  I
don't see the problem.

BTW, why does it matter if "non-election-theorists" when asked suggest
"counter-productive strategies"?  Shouldn't we be encouraging sincere
voting?
If they don't want to do that, why can't they just take the strategy
advice of their favourites?

35: C >> A=B
33: A>B >> C
32: B>A >> C

In Smith//approval, one vote alone would shift the above honest
election; so the fact that it does not in PAR is indeed notable.

I don't see why.  The example I gave just happened to have a close CW.
PAR seems to give an A=B tie unless (as I assume) it breaks tied final
scores in favour of the "leader" (A).

In particular: in PAR, there is no way for the B voters to strategize
such that they win the above election, while still ensuring that C
does not win no matter what the A voters do.

Of course, that is why it's called a "chicken dilemma".  In what method
/can/ "the B voters to strategize such that they win the above election,
while still ensuring that C does not win no matter what the A voters do" ??

MJ passes IIA. PAR fails it, as you say, but passes LIIA.

As do some Condorcet methods. It isn't one of the criteria I care much
about.

As I understand it, IIA can only be met by methods that fail Majority
(like positional methods that pretend that the voters' ratings are on
some scale independent of the
candidates).  MJ  is a variety of Median Ratings which is normally
claimed to meet Majority.

I would be a bit surprised if IIA can be met by a method (such as MJ and
Bucklin) by a method that fails Irrelevant Ballots Independence.

There is some rubbish about Independence of Irrelevant Alternatives
(IIA) on Electowiki.  I'll address that in a later post.

Chris Benham

On 11/13/2016 3:35 AM, Jameson Quinn wrote:

2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au
mailto:cbenham@adam.com.au>:

 On 11/12/2016 7:53 AM, Jameson Quinn wrote:
 2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au
 <mailto:cbenham@adam.com.au>>:

     On 11/11/2016 10:14 PM, Jameson Quinn wrote:
     I think that simple PAR is close enough to FBC compliance to
     be an acceptable proposal.
     I'm afraid I can't see any value in "close enough" to FBC
     compliance. The point of FBC is to give an absolute guarantee
     to (possibly uninformed
     and not strategically savvy) greater-evil fearing voters.


 Yes. The guarantee you can give is "as long as the world is
 somewhere in this restricted domain — that is, essentially, as
 long as there are no Condorcet cycles and each voter naturally
 rejects at least one of the 3 frontrunners — this method meets
 FBC". This is much broader than any guarantee you could give for
 a typical non-FBC method. For instance, with IRV, the best you
 could say would be "as long as your favorite is eliminated early
 or wins overall, you don't have to betray them", which unlike
 PAR's guarantee is not something which could ever be generally
 true about all real elections for all factions.
 C: I have in mind voters who are inclined to Compromise, and so
 it's /absolute guarantee/ or it's nothing.   Smith//Approval also
 has a much lower Compromise incentive
 than does IRV  (which in turn has a much much lower Compromise
 incentive then FPP).
     It elects the "correct" winner in a chicken dilemma
     scenario, naive/honest/strategyless ballots, without a
     "slippery slope" (though of course, this is no longer a
     strong Nash equilibrium). 
     How do you have a "chicken dilemma scenario" with
     "naive/honest/strategyless ballots" ?

     35: C >> A=B
     33: A>B >> C
     32: B >> A=C  (sincere is B>A >> C)

     In this CD scenario your method elects B  in violation of the
     CD criterion.


 You're suggesting that the sincere preferences are

 35: C >> A=B
 33: A>B >> C
 32: B>A >> C
 C:  I'm not "suggesting". I'm stating.
 If you are 1 of the B>A>>C voters considering whether to
 strategically vote B>>A=C, you have no strong motivation to do
 so, because your vote alone is not enough to shift the winner to
 B. This is what I mean by "no slippery slope".
 C: One "vote alone" is very rarely enough to do anything, so I
 suppose no-one has a "strong motivation" to vote.

In Smith//approval, one vote alone would shift the above honest
election; so the fact that it does not in PAR is indeed notable.

In particular: in PAR, there is no way for the B voters to strategize
such that they win the above election, while still ensuring that C
does not win no matter what the A voters do. This "safe" strategizing
is grease on the slippery slope.

 I believe that in the election you gave, there is no way to tell
 what the sincere preferences are.
 C: From just the information on the ballots, of course not (like
 any election).
 Perhaps the B voters are strategically truncating A; perhaps the
 C voters are strategically truncating B. So the "correct winner"
 could be either A or B, but is almost certainly not C.
 C: By "correct winner" I assume you mean the sincere CW. But there
 is reason to assume there is one. And if the B voters are actively
 Burying C, it could be C.
 The "CD criterion" requires the system to elect C, merely to
 punish the B voters; I think that's perverse, because, among
 other things, it means that a system does badly with center
 squeeze, allowing the C faction to strategize and win.
 C: No, it merely says "not B".  But CD + Plurality say that it
 must be C.
     Since you are apparently now content to do without FBC 
     compliance  and you imply that electing the CW is a good thing,
     why don't you advocate a method that meets the Condorcet
     criterion?

     What is wrong with Smith//Approval?  Or Forest's nearly
     equivalent Max Covered Approval?


 Largely, it's because I think that Condorcet systems are
 strategically counterintuitive, and hard to present results in. I
 think that will lead to more strategy than a system like PAR.
 That's because PAR can make guarantees that Condorcet systems can't.
 C: Such as?  What exactly does "strategically counter-intuitive"
 mean?  An example?

What I mean is that if you take a non-election-theorist, present an
election scenario to them, explain who won and why, and ask how they
would strategize in the place of voter X, they are more likely to
suggest counterproductive strategies, and less likely to see any
strategies that actually might work, in Condorcet than in Bucklin-like
systems.

 In a system like MJ or Score, you can give a number to each
 candidate, based on their own ratings alone, and the higher
 number wins. That is an easy way to get monotonicity, FBC, and IIA.

 In Condorcet, no candidate has any number except in relation to
 all other candidates. That's good for passing the Condorcet
 criterion (obviously) but it breaks FBC and IIA.
 C:  Your method and MJ fail IIA.

MJ passes IIA. PAR fails it, as you say, but passes LIIA.

Prefer Accept Reject (PAR) voting works as follows:

  1. Voters can Prefer, Accept, or Reject each candidate. Blanks
    count as "Reject" if no rival is explicitly rejected; otherwise,
    blank is "Accept".
  2. Candidates with at least 25% Prefer, and no more than 50% reject,
    are "viable"
    . The most-preferred viable candidate (if any) is the
    leader.
  3. Each "prefer" is worth 1 point. For viable candidates, each
    "accept" on a ballot which doesn't prefer the leader is also worth
    1 point. Most points wins.
On 11/13/2016 3:35 AM, Jameson Quinn wrote: > What I mean is that if you take a non-election-theorist, present an > election scenario to them, explain who won and why, and ask how they > would strategize in the place of voter X, they are more likely to > suggest counterproductive strategies, and less likely to see any > strategies that actually might work, in Condorcet than in Bucklin-like > systems. > The strategy incentives for Condorcet voting methods vary widely. Some have a random-fill incentive while others have a truncation incentive. Some have a stronger or weaker incentive to equal-top rank than others, and some are more vulnerable to Burial than others. Smith//Approval has a truncation incentive like Bucklin's, only less strong. In addition Bucklin has an equal-top rank/rate incentive. I don't see the problem. BTW, why does it matter if "non-election-theorists" when asked suggest "counter-productive strategies"? Shouldn't we be encouraging sincere voting? If they don't want to do that, why can't they just take the strategy advice of their favourites? 35: C >> A=B 33: A>B >> C 32: B>A >> C > In Smith//approval, one vote alone would shift the above honest > election; so the fact that it does not in PAR is indeed notable. I don't see why. The example I gave just happened to have a close CW. PAR seems to give an A=B tie unless (as I assume) it breaks tied final scores in favour of the "leader" (A). > In particular: in PAR, there is no way for the B voters to strategize > such that they win the above election, while still ensuring that C > does not win no matter what the A voters do. Of course, that is why it's called a "chicken dilemma". In what method /can/ "the B voters to strategize such that they win the above election, while still ensuring that C does not win no matter what the A voters do" ?? > MJ passes IIA. PAR fails it, as you say, but passes LIIA. As do some Condorcet methods. It isn't one of the criteria I care much about. As I understand it, IIA can only be met by methods that fail Majority (like positional methods that pretend that the voters' ratings are on some scale independent of the candidates). MJ is a variety of Median Ratings which is normally claimed to meet Majority. I would be a bit surprised if IIA can be met by a method (such as MJ and Bucklin) by a method that fails Irrelevant Ballots Independence. There is some rubbish about Independence of Irrelevant Alternatives (IIA) on Electowiki. I'll address that in a later post. Chris Benham On 11/13/2016 3:35 AM, Jameson Quinn wrote: > > > 2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au > <mailto:cbenham@adam.com.au>>: > > On 11/12/2016 7:53 AM, Jameson Quinn wrote: >> >> >> 2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au >> <mailto:cbenham@adam.com.au>>: >> >> On 11/11/2016 10:14 PM, Jameson Quinn wrote: >> >>> I think that simple PAR is close enough to FBC compliance to >>> be an acceptable proposal. >> >> I'm afraid I can't see any value in "close enough" to FBC >> compliance. The point of FBC is to give an absolute guarantee >> to (possibly uninformed >> and not strategically savvy) greater-evil fearing voters. >> >> >> Yes. The guarantee you can give is "as long as the world is >> somewhere in this restricted domain — that is, essentially, as >> long as there are no Condorcet cycles and each voter naturally >> rejects at least one of the 3 frontrunners — this method meets >> FBC". This is much broader than any guarantee you could give for >> a typical non-FBC method. For instance, with IRV, the best you >> could say would be "as long as your favorite is eliminated early >> or wins overall, you don't have to betray them", which unlike >> PAR's guarantee is not something which could ever be generally >> true about all real elections for all factions. >> > C: I have in mind voters who are inclined to Compromise, and so > it's /absolute guarantee/ or it's nothing. Smith//Approval also > has a much lower Compromise incentive > than does IRV (which in turn has a much much lower Compromise > incentive then FPP). > > >> >> >> >>> It elects the "correct" winner in a chicken dilemma >>> scenario, naive/honest/strategyless ballots, without a >>> "slippery slope" (though of course, this is no longer a >>> strong Nash equilibrium). >> >> How do you have a "chicken dilemma scenario" with >> "naive/honest/strategyless ballots" ? >> >> 35: C >> A=B >> 33: A>B >> C >> 32: B >> A=C (sincere is B>A >> C) >> >> In this CD scenario your method elects B in violation of the >> CD criterion. >> >> >> You're suggesting that the sincere preferences are >> >> 35: C >> A=B >> 33: A>B >> C >> 32: B>A >> C >> >> > C: I'm not "suggesting". I'm stating. >> >> If you are 1 of the B>A>>C voters considering whether to >> strategically vote B>>A=C, you have no strong motivation to do >> so, because your vote alone is not enough to shift the winner to >> B. This is what I mean by "no slippery slope". >> >> > C: One "vote alone" is very rarely enough to do anything, so I > suppose no-one has a "strong motivation" to vote. > > > In Smith//approval, one vote alone would shift the above honest > election; so the fact that it does not in PAR is indeed notable. > > In particular: in PAR, there is no way for the B voters to strategize > such that they win the above election, while still ensuring that C > does not win no matter what the A voters do. This "safe" strategizing > is grease on the slippery slope. > > >> >> >> I believe that in the election you gave, there is no way to tell >> what the sincere preferences are. >> >> > > C: From just the information on the ballots, of course not (like > any election). >> >> Perhaps the B voters are strategically truncating A; perhaps the >> C voters are strategically truncating B. So the "correct winner" >> could be either A or B, but is almost certainly not C. > > C: By "correct winner" I assume you mean the sincere CW. But there > is reason to assume there is one. And if the B voters are actively > Burying C, it could be C. > >> The "CD criterion" requires the system to elect C, merely to >> punish the B voters; I think that's perverse, because, among >> other things, it means that a system does badly with center >> squeeze, allowing the C faction to strategize and win. >> > C: No, it merely says "not B". But CD + Plurality say that it > must be C. >> >> >> Since you are apparently now content to do without FBC >> compliance and you imply that electing the CW is a good thing, >> why don't you advocate a method that meets the Condorcet >> criterion? >> >> What is wrong with Smith//Approval? Or Forest's nearly >> equivalent Max Covered Approval? >> >> >> Largely, it's because I think that Condorcet systems are >> strategically counterintuitive, and hard to present results in. I >> think that will lead to more strategy than a system like PAR. >> That's because PAR can make guarantees that Condorcet systems can't. >> > C: Such as? What exactly does "strategically counter-intuitive" > mean? An example? > > > What I mean is that if you take a non-election-theorist, present an > election scenario to them, explain who won and why, and ask how they > would strategize in the place of voter X, they are more likely to > suggest counterproductive strategies, and less likely to see any > strategies that actually might work, in Condorcet than in Bucklin-like > systems. > > >> >> In a system like MJ or Score, you can give a number to each >> candidate, based on their own ratings alone, and the higher >> number wins. That is an easy way to get monotonicity, FBC, and IIA. >> >> In Condorcet, no candidate has any number except in relation to >> all other candidates. That's good for passing the Condorcet >> criterion (obviously) but it breaks FBC and IIA. >> > C: Your method and MJ fail IIA. > > > MJ passes IIA. PAR fails it, as you say, but passes LIIA. > > > Prefer Accept Reject (PAR) voting works as follows: > > 1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks > count as "Reject" if no rival is explicitly rejected; otherwise, > blank is "Accept". > 2. *Candidates with at least 25% Prefer, and no more than 50% reject, > are "viable"*. The most-preferred viable candidate (if any) is the > leader. > 3. Each "prefer" is worth 1 point. For viable candidates, each > "accept" on a ballot which doesn't prefer the leader is also worth > 1 point. *Most points wins.* >
JQ
Jameson Quinn
Sun, Nov 13, 2016 3:18 PM

2016-11-13 6:34 GMT-05:00 C.Benham cbenham@adam.com.au:

On 11/13/2016 3:35 AM, Jameson Quinn wrote:

What I mean is that if you take a non-election-theorist, present an
election scenario to them, explain who won and why, and ask how they would
strategize in the place of voter X, they are more likely to suggest
counterproductive strategies, and less likely to see any strategies that
actually might work, in Condorcet than in Bucklin-like systems.

The strategy incentives for Condorcet voting methods vary widely.  Some
have a random-fill incentive while others have a truncation incentive. Some
have
a stronger or weaker incentive to equal-top rank than others, and some are
more vulnerable to Burial than others.

Smith//Approval has a truncation incentive like Bucklin's, only less
strong. In addition Bucklin has an equal-top rank/rate incentive.  I don't
see the problem.

BTW, why does it matter if "non-election-theorists" when asked suggest
"counter-productive strategies"?  Shouldn't we be encouraging sincere
voting?
If they don't want to do that, why can't they just take the strategy
advice of their favourites?

My concern here is that people will misuse strategy. I think that FBC and
IIA are good guarantees to be able to give, but also that these guarantees
are related to O(N) summability, which is basically saying "you can think
about what's going on in an election, it fits inside your head." PAR does
not have O(N) summability, but it can be done in 2 steps, each of them O(N)
summable, and each of them considered separately meeting FBC and IIA.

35: C >> A=B
33: A>B >> C
32: B>A >> C

In Smith//approval, one vote alone would shift the above honest election;
so the fact that it does not in PAR is indeed notable.

I don't see why.  The example I gave just happened to have a close CW.
PAR seems to give an A=B tie unless (as I assume) it breaks tied final
scores in favour of the "leader" (A).

In particular: in PAR, there is no way for the B voters to strategize such
that they win the above election, while still ensuring that C does not win
no matter what the A voters do.

Of course, that is why it's called a "chicken dilemma".  In what method
can "the B voters to strategize such that they win the above election,
while still ensuring that C does not win no matter what the A voters do" ??

I think that you still don't understand what I mean by "slippery slope".
(Of course, once you do understand it, you're still free to disagree that
it's important.)

Suppose you have a scenario like the following:
19: A>B
11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a vote
with A top, B second-to-bottom, and all else bottom. In approval, then,
this would be A or AB)
25: (ego faction; true preferences B>A)
45: C

You are in the ego faction, and deciding whether to vote B>A or just B (or
in approval, BA or B). If there is some combination of votes that the ego
faction can give such that B wins in the case where the 11 votes are B>A,
but A wins in the case where the 11 votes are A, then there is a slippery
slope; the ego faction can safely and profitably use a small amount of
offensive strategy, which means that A voters should use slightly more
defensive strategy, and then there's a cycle of escalation until both
factions fall off the cliff and end up electing C.

Is that clear now?

MJ passes IIA. PAR fails it, as you say, but passes LIIA.

As do some Condorcet methods. It isn't one of the criteria I care much
about.

As I understand it, IIA can only be met by methods that fail Majority
(like positional methods that pretend that the voters' ratings are on some
scale independent of the
candidates).  MJ  is a variety of Median Ratings which is normally
claimed to meet Majority.

IIA, when applied to a cardinal or categorical method, assumes that when
you remove a candidate, you simply delete that candidate from all ballots
and leave them otherwise unchanged.

The definition of majority used in the proof that IIA and Majority are
incompatible assumes otherwise. Thus, this proof does not apply to
non-ranked methods. Or perhaps one could say: it shows that a method cannot
pass IIA and ranked-majority. MJ does not pass ranked-majority, but it does
pass majority, so that's fine.

MJ does pass IIA.

I would be a bit surprised if IIA can be met by a method (such as MJ and
Bucklin) by a method that fails Irrelevant Ballots Independence.

There is some rubbish about Independence of Irrelevant Alternatives (IIA)
on Electowiki.  I'll address that in a later post.

Chris Benham

On 11/13/2016 3:35 AM, Jameson Quinn wrote:

2016-11-12 10:45 GMT-05:00 C.Benham cbenham@adam.com.au:

On 11/12/2016 7:53 AM, Jameson Quinn wrote:

2016-11-11 12:50 GMT-05:00 C.Benham cbenham@adam.com.au:

On 11/11/2016 10:14 PM, Jameson Quinn wrote:

I think that simple PAR is close enough to FBC compliance to be an
acceptable proposal.

I'm afraid I can't see any value in "close enough" to FBC compliance.
The point of FBC is to give an absolute guarantee to (possibly uninformed
and not strategically savvy)  greater-evil fearing voters.

Yes. The guarantee you can give is "as long as the world is somewhere in
this restricted domain — that is, essentially, as long as there are no
Condorcet cycles and each voter naturally rejects at least one of the 3
frontrunners — this method meets FBC". This is much broader than any
guarantee you could give for a typical non-FBC method. For instance, with
IRV, the best you could say would be "as long as your favorite is
eliminated early or wins overall, you don't have to betray them", which
unlike PAR's guarantee is not something which could ever be generally true
about all real elections for all factions.

C: I have in mind voters who are inclined to Compromise, and so it's *
absolute guarantee* or it's nothing.  Smith//Approval also has a much
lower Compromise incentive
than does IRV  (which in turn has a much much lower Compromise incentive
then FPP).

It elects the "correct" winner in a chicken dilemma scenario,
naive/honest/strategyless ballots, without a "slippery slope" (though of
course, this is no longer a strong Nash equilibrium).

How do you have a "chicken dilemma scenario" with
"naive/honest/strategyless ballots" ?

35: C >> A=B
33: A>B >> C
32: B >> A=C  (sincere is B>A >> C)

In this CD scenario your method elects B  in violation of the CD
criterion.

You're suggesting that the sincere preferences are

35: C >> A=B
33: A>B >> C
32: B>A >> C

C:  I'm not "suggesting". I'm stating.

If you are 1 of the B>A>>C voters considering whether to strategically
vote B>>A=C, you have no strong motivation to do so, because your vote
alone is not enough to shift the winner to B. This is what I mean by "no
slippery slope".

C: One "vote alone" is very rarely enough to do anything, so I suppose
no-one has a "strong motivation" to vote.

In Smith//approval, one vote alone would shift the above honest election;
so the fact that it does not in PAR is indeed notable.

In particular: in PAR, there is no way for the B voters to strategize such
that they win the above election, while still ensuring that C does not win
no matter what the A voters do. This "safe" strategizing is grease on the
slippery slope.

I believe that in the election you gave, there is no way to tell what the
sincere preferences are.

C: From just the information on the ballots, of course not (like any
election).

Perhaps the B voters are strategically truncating A; perhaps the C voters
are strategically truncating B. So the "correct winner" could be either A
or B, but is almost certainly not C.

C: By "correct winner" I assume you mean the sincere CW. But there is
reason to assume there is one. And if the B voters are actively Burying C,
it could be C.

The "CD criterion" requires the system to elect C, merely to punish the B
voters; I think that's perverse, because, among other things, it means that
a system does badly with center squeeze, allowing the C faction to
strategize and win.

C: No, it merely says "not B".  But CD + Plurality say that it must be C.

Since you are apparently now content to do without FBC  compliance  and
you imply that electing the CW is a good thing,
why don't you advocate a method that meets the Condorcet criterion?

What is wrong with Smith//Approval?  Or Forest's nearly equivalent Max
Covered Approval?

Largely, it's because I think that Condorcet systems are strategically
counterintuitive, and hard to present results in. I think that will lead to
more strategy than a system like PAR. That's because PAR can make
guarantees that Condorcet systems can't.

C: Such as?  What exactly does "strategically counter-intuitive" mean?
An example?

What I mean is that if you take a non-election-theorist, present an
election scenario to them, explain who won and why, and ask how they would
strategize in the place of voter X, they are more likely to suggest
counterproductive strategies, and less likely to see any strategies that
actually might work, in Condorcet than in Bucklin-like systems.

In a system like MJ or Score, you can give a number to each candidate,
based on their own ratings alone, and the higher number wins. That is an
easy way to get monotonicity, FBC, and IIA.

In Condorcet, no candidate has any number except in relation to all other
candidates. That's good for passing the Condorcet criterion (obviously) but
it breaks FBC and IIA.

C:  Your method and MJ fail IIA.

MJ passes IIA. PAR fails it, as you say, but passes LIIA.

Prefer Accept Reject (PAR) voting works as follows:

1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks count
as "Reject" if no rival is explicitly rejected; otherwise, blank is
"Accept".
2. *Candidates with at least 25% Prefer, and no more than 50% reject,
are "viable"*. The most-preferred viable candidate (if any) is the
leader.
3. Each "prefer" is worth 1 point. For viable candidates, each
"accept" on a ballot which doesn't prefer the leader is also worth 1 point. *Most
points wins.*
2016-11-13 6:34 GMT-05:00 C.Benham <cbenham@adam.com.au>: > On 11/13/2016 3:35 AM, Jameson Quinn wrote: > > What I mean is that if you take a non-election-theorist, present an > election scenario to them, explain who won and why, and ask how they would > strategize in the place of voter X, they are more likely to suggest > counterproductive strategies, and less likely to see any strategies that > actually might work, in Condorcet than in Bucklin-like systems. > > > The strategy incentives for Condorcet voting methods vary widely. Some > have a random-fill incentive while others have a truncation incentive. Some > have > a stronger or weaker incentive to equal-top rank than others, and some are > more vulnerable to Burial than others. > > Smith//Approval has a truncation incentive like Bucklin's, only less > strong. In addition Bucklin has an equal-top rank/rate incentive. I don't > see the problem. > > BTW, why does it matter if "non-election-theorists" when asked suggest > "counter-productive strategies"? Shouldn't we be encouraging sincere > voting? > If they don't want to do that, why can't they just take the strategy > advice of their favourites? > My concern here is that people will misuse strategy. I think that FBC and IIA are good guarantees to be able to give, but also that these guarantees are related to O(N) summability, which is basically saying "you can think about what's going on in an election, it fits inside your head." PAR does not have O(N) summability, but it can be done in 2 steps, each of them O(N) summable, and each of them considered separately meeting FBC and IIA. > > 35: C >> A=B > 33: A>B >> C > 32: B>A >> C > > In Smith//approval, one vote alone would shift the above honest election; > so the fact that it does not in PAR is indeed notable. > > > I don't see why. The example I gave just happened to have a close CW. > PAR seems to give an A=B tie unless (as I assume) it breaks tied final > scores in favour of the "leader" (A). > > In particular: in PAR, there is no way for the B voters to strategize such > that they win the above election, while still ensuring that C does not win > no matter what the A voters do. > > > Of course, that is why it's called a "chicken dilemma". In what method > *can* "the B voters to strategize such that they win the above election, > while still ensuring that C does not win no matter what the A voters do" ?? > I think that you still don't understand what I mean by "slippery slope". (Of course, once you do understand it, you're still free to disagree that it's important.) Suppose you have a scenario like the following: 19: A>B 11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a vote with A top, B second-to-bottom, and all else bottom. In approval, then, this would be A or AB) 25: (ego faction; true preferences B>A) 45: C You are in the ego faction, and deciding whether to vote B>A or just B (or in approval, BA or B). If there is some combination of votes that the ego faction can give such that B wins in the case where the 11 votes are B>A, but A wins in the case where the 11 votes are A, then there is a slippery slope; the ego faction can safely and profitably use a small amount of offensive strategy, which means that A voters should use slightly more defensive strategy, and then there's a cycle of escalation until both factions fall off the cliff and end up electing C. Is that clear now? > > MJ passes IIA. PAR fails it, as you say, but passes LIIA. > > > As do some Condorcet methods. It isn't one of the criteria I care much > about. > > As I understand it, IIA can only be met by methods that fail Majority > (like positional methods that pretend that the voters' ratings are on some > scale independent of the > candidates). MJ is a variety of Median Ratings which is normally > claimed to meet Majority. > IIA, when applied to a cardinal or categorical method, assumes that when you remove a candidate, you simply delete that candidate from all ballots and leave them otherwise unchanged. The definition of majority used in the proof that IIA and Majority are incompatible assumes otherwise. Thus, this proof does not apply to non-ranked methods. Or perhaps one could say: it shows that a method cannot pass IIA and ranked-majority. MJ does not pass ranked-majority, but it does pass majority, so that's fine. MJ does pass IIA. > > I would be a bit surprised if IIA can be met by a method (such as MJ and > Bucklin) by a method that fails Irrelevant Ballots Independence. > > There is some rubbish about Independence of Irrelevant Alternatives (IIA) > on Electowiki. I'll address that in a later post. > > Chris Benham > > > > On 11/13/2016 3:35 AM, Jameson Quinn wrote: > > > > 2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au>: > >> On 11/12/2016 7:53 AM, Jameson Quinn wrote: >> >> >> >> 2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au>: >> >>> On 11/11/2016 10:14 PM, Jameson Quinn wrote: >>> >>> I think that simple PAR is close enough to FBC compliance to be an >>> acceptable proposal. >>> >>> >>> I'm afraid I can't see any value in "close enough" to FBC compliance. >>> The point of FBC is to give an absolute guarantee to (possibly uninformed >>> and not strategically savvy) greater-evil fearing voters. >>> >> >> Yes. The guarantee you can give is "as long as the world is somewhere in >> this restricted domain — that is, essentially, as long as there are no >> Condorcet cycles and each voter naturally rejects at least one of the 3 >> frontrunners — this method meets FBC". This is much broader than any >> guarantee you could give for a typical non-FBC method. For instance, with >> IRV, the best you could say would be "as long as your favorite is >> eliminated early or wins overall, you don't have to betray them", which >> unlike PAR's guarantee is not something which could ever be generally true >> about all real elections for all factions. >> >> C: I have in mind voters who are inclined to Compromise, and so it's * >> absolute guarantee* or it's nothing. Smith//Approval also has a much >> lower Compromise incentive >> than does IRV (which in turn has a much much lower Compromise incentive >> then FPP). >> >> >> >> >>> >>> It elects the "correct" winner in a chicken dilemma scenario, >>> naive/honest/strategyless ballots, without a "slippery slope" (though of >>> course, this is no longer a strong Nash equilibrium). >>> >>> >>> How do you have a "chicken dilemma scenario" with >>> "naive/honest/strategyless ballots" ? >>> >>> 35: C >> A=B >>> 33: A>B >> C >>> 32: B >> A=C (sincere is B>A >> C) >>> >>> In this CD scenario your method elects B in violation of the CD >>> criterion. >>> >> >> You're suggesting that the sincere preferences are >> >> 35: C >> A=B >> 33: A>B >> C >> 32: B>A >> C >> >> >> C: I'm not "suggesting". I'm stating. >> >> >> If you are 1 of the B>A>>C voters considering whether to strategically >> vote B>>A=C, you have no strong motivation to do so, because your vote >> alone is not enough to shift the winner to B. This is what I mean by "no >> slippery slope". >> >> >> C: One "vote alone" is very rarely enough to do anything, so I suppose >> no-one has a "strong motivation" to vote. >> > > In Smith//approval, one vote alone would shift the above honest election; > so the fact that it does not in PAR is indeed notable. > > In particular: in PAR, there is no way for the B voters to strategize such > that they win the above election, while still ensuring that C does not win > no matter what the A voters do. This "safe" strategizing is grease on the > slippery slope. > > >> >> >> I believe that in the election you gave, there is no way to tell what the >> sincere preferences are. >> >> >> >> C: From just the information on the ballots, of course not (like any >> election). >> >> >> Perhaps the B voters are strategically truncating A; perhaps the C voters >> are strategically truncating B. So the "correct winner" could be either A >> or B, but is almost certainly not C. >> >> >> C: By "correct winner" I assume you mean the sincere CW. But there is >> reason to assume there is one. And if the B voters are actively Burying C, >> it could be C. >> >> The "CD criterion" requires the system to elect C, merely to punish the B >> voters; I think that's perverse, because, among other things, it means that >> a system does badly with center squeeze, allowing the C faction to >> strategize and win. >> >> C: No, it merely says "not B". But CD + Plurality say that it must be C. >> >> >> >>> >>> Since you are apparently now content to do without FBC compliance and >>> you imply that electing the CW is a good thing, >>> why don't you advocate a method that meets the Condorcet criterion? >>> >>> What is wrong with Smith//Approval? Or Forest's nearly equivalent Max >>> Covered Approval? >>> >> >> Largely, it's because I think that Condorcet systems are strategically >> counterintuitive, and hard to present results in. I think that will lead to >> more strategy than a system like PAR. That's because PAR can make >> guarantees that Condorcet systems can't. >> >> C: Such as? What exactly does "strategically counter-intuitive" mean? >> An example? >> > > What I mean is that if you take a non-election-theorist, present an > election scenario to them, explain who won and why, and ask how they would > strategize in the place of voter X, they are more likely to suggest > counterproductive strategies, and less likely to see any strategies that > actually might work, in Condorcet than in Bucklin-like systems. > > >> >> In a system like MJ or Score, you can give a number to each candidate, >> based on their own ratings alone, and the higher number wins. That is an >> easy way to get monotonicity, FBC, and IIA. >> >> In Condorcet, no candidate has any number except in relation to all other >> candidates. That's good for passing the Condorcet criterion (obviously) but >> it breaks FBC and IIA. >> >> C: Your method and MJ fail IIA. >> > > MJ passes IIA. PAR fails it, as you say, but passes LIIA. > > > Prefer Accept Reject (PAR) voting works as follows: > > 1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks count > as "Reject" if no rival is explicitly rejected; otherwise, blank is > "Accept". > 2. *Candidates with at least 25% Prefer, and no more than 50% reject, > are "viable"*. The most-preferred viable candidate (if any) is the > leader. > 3. Each "prefer" is worth 1 point. For viable candidates, each > "accept" on a ballot which doesn't prefer the leader is also worth 1 point. *Most > points wins.* > > >
C
C.Benham
Tue, Nov 15, 2016 5:57 AM

On 11/14/2016 1:48 AM, Jameson Quinn wrote:

I think that you still don't understand what I mean by "slippery
slope". (Of course, once you do understand it, you're still free to
disagree that it's important.)

Suppose you have a scenario like the following:
19: A>B
11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a
vote with A top, B second-to-bottom, and all else bottom. In approval,
then, this would be A or AB)
25: (ego faction; true preferences B>A)
45: C

You are in the ego faction, and deciding whether to vote B>A or just B
(or in approval, BA or B). If there is some combination of votes that
the ego faction can give such that B wins in the case where the 11
votes are B>A, but A wins in the case where the 11 votes are A, then
there is a slippery slope; the ego faction can safely and profitably
use a small amount of offensive strategy, which means that A voters
should use slightly more defensive strategy, and then there's a cycle
of escalation until both factions fall off the cliff and end up
electing C.

Is that clear now?

Jameson,

Maybe not entirely. When you refer to a "small amount" of "offensive" or
"defensive" strategy, presumably you are talking about some members of a
faction
voting one way and the rest another. Is that right?

I can see the problem in Approval, but under Smith//Approval in your
scenario A is simply the CW and the "ego faction" can't do anything to
get a result they prefer.

I'm not sure that this problem is entirely avoided in PAR. Presumably
the C faction gives Rejects to both A and B.  If six or more of the ego
faction give B a Reject
and six or more of the ??? faction give B an Accept then both A and C
will be eliminated leaving B the winner.

Chris Benham

On 11/14/2016 1:48 AM, Jameson Quinn wrote:

2016-11-13 6:34 GMT-05:00 C.Benham <cbenham@adam.com.au
mailto:cbenham@adam.com.au>:

 On 11/13/2016 3:35 AM, Jameson Quinn wrote:
 What I mean is that if you take a non-election-theorist, present
 an election scenario to them, explain who won and why, and ask
 how they would strategize in the place of voter X, they are more
 likely to suggest counterproductive strategies, and less likely
 to see any strategies that actually might work, in Condorcet than
 in Bucklin-like systems.
 The strategy incentives for Condorcet voting methods vary widely. 
 Some have a random-fill incentive while others have a truncation
 incentive. Some have
 a stronger or weaker incentive to equal-top rank than others, and
 some are more vulnerable to Burial than others.

 Smith//Approval has a truncation incentive like Bucklin's, only
 less strong. In addition Bucklin has an equal-top rank/rate
 incentive.  I don't see the problem.

 BTW, why does it matter if "non-election-theorists" when asked
 suggest "counter-productive strategies"? Shouldn't we be
 encouraging sincere voting?
 If they don't want to do that, why can't they just take the
 strategy advice of their favourites?

My concern here is that people will misuse strategy. I think that FBC
and IIA are good guarantees to be able to give, but also that these
guarantees are related to O(N) summability, which is basically saying
"you can think about what's going on in an election, it fits inside
your head." PAR does not have O(N) summability, but it can be done in
2 steps, each of them O(N) summable, and each of them considered
separately meeting FBC and IIA.

 35: C >> A=B
 33: A>B >> C
 32: B>A >> C
 In Smith//approval, one vote alone would shift the above honest
 election; so the fact that it does not in PAR is indeed notable.
 I don't see why.  The example I gave just happened to have a close
 CW.  PAR seems to give an A=B tie unless (as I assume) it breaks
 tied final
 scores in favour of the "leader" (A).
 In particular: in PAR, there is no way for the B voters to
 strategize such that they win the above election, while still
 ensuring that C does not win no matter what the A voters do.
 Of course, that is why it's called a "chicken dilemma".  In what
 method /can/ "the B voters to strategize such that they win the
 above election, while still ensuring that C does not win no matter
 what the A voters do" ??

I think that you still don't understand what I mean by "slippery
slope". (Of course, once you do understand it, you're still free to
disagree that it's important.)

Suppose you have a scenario like the following:
19: A>B
11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a
vote with A top, B second-to-bottom, and all else bottom. In approval,
then, this would be A or AB)
25: (ego faction; true preferences B>A)
45: C

You are in the ego faction, and deciding whether to vote B>A or just B
(or in approval, BA or B). If there is some combination of votes that
the ego faction can give such that B wins in the case where the 11
votes are B>A, but A wins in the case where the 11 votes are A, then
there is a slippery slope; the ego faction can safely and profitably
use a small amount of offensive strategy, which means that A voters
should use slightly more defensive strategy, and then there's a cycle
of escalation until both factions fall off the cliff and end up
electing C.

Is that clear now?

 MJ passes IIA. PAR fails it, as you say, but passes LIIA.
 As do some Condorcet methods. It isn't one of the criteria I care
 much about.

 As I understand it, IIA can only be met by methods that fail
 Majority (like positional methods that pretend that the voters'
 ratings are on some scale independent of the
 candidates).   MJ  is a variety of Median Ratings which is
 normally claimed to meet Majority.

IIA, when applied to a cardinal or categorical method, assumes that
when you remove a candidate, you simply delete that candidate from all
ballots and leave them otherwise unchanged.

The definition of majority used in the proof that IIA and Majority are
incompatible assumes otherwise. Thus, this proof does not apply to
non-ranked methods. Or perhaps one could say: it shows that a method
cannot pass IIA and ranked-majority. MJ does not pass ranked-majority,
but it does pass majority, so that's fine.

MJ does pass IIA.

 I would be a bit surprised if IIA can be met by a method (such as
 MJ and Bucklin) by a method that fails Irrelevant Ballots
 Independence.

 There is some rubbish about Independence of Irrelevant
 Alternatives (IIA) on Electowiki.  I'll address that in a later post.

 Chris Benham



 On 11/13/2016 3:35 AM, Jameson Quinn wrote:
 2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au
 <mailto:cbenham@adam.com.au>>:

     On 11/12/2016 7:53 AM, Jameson Quinn wrote:
     2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au
     <mailto:cbenham@adam.com.au>>:

         On 11/11/2016 10:14 PM, Jameson Quinn wrote:
         I think that simple PAR is close enough to FBC
         compliance to be an acceptable proposal.
         I'm afraid I can't see any value in "close enough" to
         FBC compliance.  The point of FBC is to give an absolute
         guarantee to (possibly uninformed
         and not strategically savvy)  greater-evil fearing voters.


     Yes. The guarantee you can give is "as long as the world is
     somewhere in this restricted domain — that is, essentially,
     as long as there are no Condorcet cycles and each voter
     naturally rejects at least one of the 3 frontrunners — this
     method meets FBC". This is much broader than any guarantee
     you could give for a typical non-FBC method. For instance,
     with IRV, the best you could say would be "as long as your
     favorite is eliminated early or wins overall, you don't have
     to betray them", which unlike PAR's guarantee is not
     something which could ever be generally true about all real
     elections for all factions.
     C: I have in mind voters who are inclined to Compromise, and
     so it's /absolute guarantee/ or it's nothing.  
     Smith//Approval also has a much lower Compromise incentive
     than does IRV  (which in turn has a much much lower
     Compromise incentive then FPP).
         It elects the "correct" winner in a chicken dilemma
         scenario, naive/honest/strategyless ballots, without a
         "slippery slope" (though of course, this is no longer a
         strong Nash equilibrium). 
         How do you have a "chicken dilemma scenario" with
         "naive/honest/strategyless ballots" ?

         35: C >> A=B
         33: A>B >> C
         32: B >> A=C (sincere is B>A >> C)

         In this CD scenario your method elects B  in violation
         of the CD criterion.


     You're suggesting that the sincere preferences are

     35: C >> A=B
     33: A>B >> C
     32: B>A >> C
     C:  I'm not "suggesting". I'm stating.
     If you are 1 of the B>A>>C voters considering whether to
     strategically vote B>>A=C, you have no strong motivation to
     do so, because your vote alone is not enough to shift the
     winner to B. This is what I mean by "no slippery slope".
     C: One "vote alone" is very rarely enough to do anything, so
     I suppose no-one has a "strong motivation" to vote.


 In Smith//approval, one vote alone would shift the above honest
 election; so the fact that it does not in PAR is indeed notable.

 In particular: in PAR, there is no way for the B voters to
 strategize such that they win the above election, while still
 ensuring that C does not win no matter what the A voters do. This
 "safe" strategizing is grease on the slippery slope.
     I believe that in the election you gave, there is no way to
     tell what the sincere preferences are.
     C: From just the information on the ballots, of course not
     (like any election).
     Perhaps the B voters are strategically truncating A; perhaps
     the C voters are strategically truncating B. So the "correct
     winner" could be either A or B, but is almost certainly not C.
     C: By "correct winner" I assume you mean the sincere CW. But
     there is reason to assume there is one. And if the B voters
     are actively Burying C, it could be C.
     The "CD criterion" requires the system to elect C, merely to
     punish the B voters; I think that's perverse, because, among
     other things, it means that a system does badly with center
     squeeze, allowing the C faction to strategize and win.
     C: No, it merely says "not B". But CD + Plurality say that it
     must be C.
         Since you are apparently now content to do without FBC 
         compliance and you imply that electing the CW is a good
         thing,
         why don't you advocate a method that meets the Condorcet
         criterion?

         What is wrong with Smith//Approval?  Or Forest's nearly
         equivalent Max Covered Approval?


     Largely, it's because I think that Condorcet systems are
     strategically counterintuitive, and hard to present results
     in. I think that will lead to more strategy than a system
     like PAR. That's because PAR can make guarantees that
     Condorcet systems can't.
     C: Such as?  What exactly does "strategically
     counter-intuitive" mean? An example?


 What I mean is that if you take a non-election-theorist, present
 an election scenario to them, explain who won and why, and ask
 how they would strategize in the place of voter X, they are more
 likely to suggest counterproductive strategies, and less likely
 to see any strategies that actually might work, in Condorcet than
 in Bucklin-like systems.
     In a system like MJ or Score, you can give a number to each
     candidate, based on their own ratings alone, and the higher
     number wins. That is an easy way to get monotonicity, FBC,
     and IIA.

     In Condorcet, no candidate has any number except in relation
     to all other candidates. That's good for passing the
     Condorcet criterion (obviously) but it breaks FBC and IIA.
     C:  Your method and MJ fail IIA.


 MJ passes IIA. PAR fails it, as you say, but passes LIIA.


 Prefer Accept Reject (PAR) voting works as follows:

  1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks
     count as "Reject" if no rival is explicitly rejected;
     otherwise, blank is "Accept".
  2. *Candidates with at least 25% Prefer, and no more than 50%
     reject, are "viable"*. The most-preferred viable candidate
     (if any) is the leader.
  3. Each "prefer" is worth 1 point. For viable candidates, each
     "accept" on a ballot which doesn't prefer the leader is also
     worth 1 point. *Most points wins.*
On 11/14/2016 1:48 AM, Jameson Quinn wrote: > I think that you still don't understand what I mean by "slippery > slope". (Of course, once you do understand it, you're still free to > disagree that it's important.) > > Suppose you have a scenario like the following: > 19: A>B > 11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a > vote with A top, B second-to-bottom, and all else bottom. In approval, > then, this would be A or AB) > 25: (ego faction; true preferences B>A) > 45: C > > You are in the ego faction, and deciding whether to vote B>A or just B > (or in approval, BA or B). If there is some combination of votes that > the ego faction can give such that B wins in the case where the 11 > votes are B>A, but A wins in the case where the 11 votes are A, then > there is a slippery slope; the ego faction can safely and profitably > use a small amount of offensive strategy, which means that A voters > should use slightly more defensive strategy, and then there's a cycle > of escalation until both factions fall off the cliff and end up > electing C. > > Is that clear now? Jameson, Maybe not entirely. When you refer to a "small amount" of "offensive" or "defensive" strategy, presumably you are talking about some members of a faction voting one way and the rest another. Is that right? I can see the problem in Approval, but under Smith//Approval in your scenario A is simply the CW and the "ego faction" can't do anything to get a result they prefer. I'm not sure that this problem is entirely avoided in PAR. Presumably the C faction gives Rejects to both A and B. If six or more of the ego faction give B a Reject and six or more of the ??? faction give B an Accept then both A and C will be eliminated leaving B the winner. Chris Benham On 11/14/2016 1:48 AM, Jameson Quinn wrote: > > > 2016-11-13 6:34 GMT-05:00 C.Benham <cbenham@adam.com.au > <mailto:cbenham@adam.com.au>>: > > On 11/13/2016 3:35 AM, Jameson Quinn wrote: > >> What I mean is that if you take a non-election-theorist, present >> an election scenario to them, explain who won and why, and ask >> how they would strategize in the place of voter X, they are more >> likely to suggest counterproductive strategies, and less likely >> to see any strategies that actually might work, in Condorcet than >> in Bucklin-like systems. >> > > The strategy incentives for Condorcet voting methods vary widely. > Some have a random-fill incentive while others have a truncation > incentive. Some have > a stronger or weaker incentive to equal-top rank than others, and > some are more vulnerable to Burial than others. > > Smith//Approval has a truncation incentive like Bucklin's, only > less strong. In addition Bucklin has an equal-top rank/rate > incentive. I don't see the problem. > > BTW, why does it matter if "non-election-theorists" when asked > suggest "counter-productive strategies"? Shouldn't we be > encouraging sincere voting? > If they don't want to do that, why can't they just take the > strategy advice of their favourites? > > > My concern here is that people will misuse strategy. I think that FBC > and IIA are good guarantees to be able to give, but also that these > guarantees are related to O(N) summability, which is basically saying > "you can think about what's going on in an election, it fits inside > your head." PAR does not have O(N) summability, but it can be done in > 2 steps, each of them O(N) summable, and each of them considered > separately meeting FBC and IIA. > > > > 35: C >> A=B > 33: A>B >> C > 32: B>A >> C > >> In Smith//approval, one vote alone would shift the above honest >> election; so the fact that it does not in PAR is indeed notable. > > I don't see why. The example I gave just happened to have a close > CW. PAR seems to give an A=B tie unless (as I assume) it breaks > tied final > scores in favour of the "leader" (A). > >> In particular: in PAR, there is no way for the B voters to >> strategize such that they win the above election, while still >> ensuring that C does not win no matter what the A voters do. > > Of course, that is why it's called a "chicken dilemma". In what > method /can/ "the B voters to strategize such that they win the > above election, while still ensuring that C does not win no matter > what the A voters do" ?? > > > I think that you still don't understand what I mean by "slippery > slope". (Of course, once you do understand it, you're still free to > disagree that it's important.) > > Suppose you have a scenario like the following: > 19: A>B > 11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a > vote with A top, B second-to-bottom, and all else bottom. In approval, > then, this would be A or AB) > 25: (ego faction; true preferences B>A) > 45: C > > You are in the ego faction, and deciding whether to vote B>A or just B > (or in approval, BA or B). If there is some combination of votes that > the ego faction can give such that B wins in the case where the 11 > votes are B>A, but A wins in the case where the 11 votes are A, then > there is a slippery slope; the ego faction can safely and profitably > use a small amount of offensive strategy, which means that A voters > should use slightly more defensive strategy, and then there's a cycle > of escalation until both factions fall off the cliff and end up > electing C. > > Is that clear now? > > >> MJ passes IIA. PAR fails it, as you say, but passes LIIA. > > As do some Condorcet methods. It isn't one of the criteria I care > much about. > > As I understand it, IIA can only be met by methods that fail > Majority (like positional methods that pretend that the voters' > ratings are on some scale independent of the > candidates). MJ is a variety of Median Ratings which is > normally claimed to meet Majority. > > > IIA, when applied to a cardinal or categorical method, assumes that > when you remove a candidate, you simply delete that candidate from all > ballots and leave them otherwise unchanged. > > The definition of majority used in the proof that IIA and Majority are > incompatible assumes otherwise. Thus, this proof does not apply to > non-ranked methods. Or perhaps one could say: it shows that a method > cannot pass IIA and ranked-majority. MJ does not pass ranked-majority, > but it does pass majority, so that's fine. > > MJ does pass IIA. > > > I would be a bit surprised if IIA can be met by a method (such as > MJ and Bucklin) by a method that fails Irrelevant Ballots > Independence. > > There is some rubbish about Independence of Irrelevant > Alternatives (IIA) on Electowiki. I'll address that in a later post. > > Chris Benham > > > > On 11/13/2016 3:35 AM, Jameson Quinn wrote: >> >> >> 2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au >> <mailto:cbenham@adam.com.au>>: >> >> On 11/12/2016 7:53 AM, Jameson Quinn wrote: >>> >>> >>> 2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au >>> <mailto:cbenham@adam.com.au>>: >>> >>> On 11/11/2016 10:14 PM, Jameson Quinn wrote: >>> >>>> I think that simple PAR is close enough to FBC >>>> compliance to be an acceptable proposal. >>> >>> I'm afraid I can't see any value in "close enough" to >>> FBC compliance. The point of FBC is to give an absolute >>> guarantee to (possibly uninformed >>> and not strategically savvy) greater-evil fearing voters. >>> >>> >>> Yes. The guarantee you can give is "as long as the world is >>> somewhere in this restricted domain — that is, essentially, >>> as long as there are no Condorcet cycles and each voter >>> naturally rejects at least one of the 3 frontrunners — this >>> method meets FBC". This is much broader than any guarantee >>> you could give for a typical non-FBC method. For instance, >>> with IRV, the best you could say would be "as long as your >>> favorite is eliminated early or wins overall, you don't have >>> to betray them", which unlike PAR's guarantee is not >>> something which could ever be generally true about all real >>> elections for all factions. >>> >> C: I have in mind voters who are inclined to Compromise, and >> so it's /absolute guarantee/ or it's nothing. >> Smith//Approval also has a much lower Compromise incentive >> than does IRV (which in turn has a much much lower >> Compromise incentive then FPP). >> >> >>> >>> >>> >>>> It elects the "correct" winner in a chicken dilemma >>>> scenario, naive/honest/strategyless ballots, without a >>>> "slippery slope" (though of course, this is no longer a >>>> strong Nash equilibrium). >>> >>> How do you have a "chicken dilemma scenario" with >>> "naive/honest/strategyless ballots" ? >>> >>> 35: C >> A=B >>> 33: A>B >> C >>> 32: B >> A=C (sincere is B>A >> C) >>> >>> In this CD scenario your method elects B in violation >>> of the CD criterion. >>> >>> >>> You're suggesting that the sincere preferences are >>> >>> 35: C >> A=B >>> 33: A>B >> C >>> 32: B>A >> C >>> >>> >> C: I'm not "suggesting". I'm stating. >>> >>> If you are 1 of the B>A>>C voters considering whether to >>> strategically vote B>>A=C, you have no strong motivation to >>> do so, because your vote alone is not enough to shift the >>> winner to B. This is what I mean by "no slippery slope". >>> >>> >> C: One "vote alone" is very rarely enough to do anything, so >> I suppose no-one has a "strong motivation" to vote. >> >> >> In Smith//approval, one vote alone would shift the above honest >> election; so the fact that it does not in PAR is indeed notable. >> >> In particular: in PAR, there is no way for the B voters to >> strategize such that they win the above election, while still >> ensuring that C does not win no matter what the A voters do. This >> "safe" strategizing is grease on the slippery slope. >> >> >>> >>> >>> I believe that in the election you gave, there is no way to >>> tell what the sincere preferences are. >>> >>> >> >> C: From just the information on the ballots, of course not >> (like any election). >>> >>> Perhaps the B voters are strategically truncating A; perhaps >>> the C voters are strategically truncating B. So the "correct >>> winner" could be either A or B, but is almost certainly not C. >> >> C: By "correct winner" I assume you mean the sincere CW. But >> there is reason to assume there is one. And if the B voters >> are actively Burying C, it could be C. >> >>> The "CD criterion" requires the system to elect C, merely to >>> punish the B voters; I think that's perverse, because, among >>> other things, it means that a system does badly with center >>> squeeze, allowing the C faction to strategize and win. >>> >> C: No, it merely says "not B". But CD + Plurality say that it >> must be C. >>> >>> >>> Since you are apparently now content to do without FBC >>> compliance and you imply that electing the CW is a good >>> thing, >>> why don't you advocate a method that meets the Condorcet >>> criterion? >>> >>> What is wrong with Smith//Approval? Or Forest's nearly >>> equivalent Max Covered Approval? >>> >>> >>> Largely, it's because I think that Condorcet systems are >>> strategically counterintuitive, and hard to present results >>> in. I think that will lead to more strategy than a system >>> like PAR. That's because PAR can make guarantees that >>> Condorcet systems can't. >>> >> C: Such as? What exactly does "strategically >> counter-intuitive" mean? An example? >> >> >> What I mean is that if you take a non-election-theorist, present >> an election scenario to them, explain who won and why, and ask >> how they would strategize in the place of voter X, they are more >> likely to suggest counterproductive strategies, and less likely >> to see any strategies that actually might work, in Condorcet than >> in Bucklin-like systems. >> >> >>> >>> In a system like MJ or Score, you can give a number to each >>> candidate, based on their own ratings alone, and the higher >>> number wins. That is an easy way to get monotonicity, FBC, >>> and IIA. >>> >>> In Condorcet, no candidate has any number except in relation >>> to all other candidates. That's good for passing the >>> Condorcet criterion (obviously) but it breaks FBC and IIA. >>> >> C: Your method and MJ fail IIA. >> >> >> MJ passes IIA. PAR fails it, as you say, but passes LIIA. >> >> >> Prefer Accept Reject (PAR) voting works as follows: >> >> 1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks >> count as "Reject" if no rival is explicitly rejected; >> otherwise, blank is "Accept". >> 2. *Candidates with at least 25% Prefer, and no more than 50% >> reject, are "viable"*. The most-preferred viable candidate >> (if any) is the leader. >> 3. Each "prefer" is worth 1 point. For viable candidates, each >> "accept" on a ballot which doesn't prefer the leader is also >> worth 1 point. *Most points wins.* >> > > >
C
C.Benham
Thu, Nov 17, 2016 7:25 AM

On 11/14/2016 1:48 AM, Jameson Quinn wrote:

Suppose you have a scenario like the following:
19: A>B
11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a
vote with A top, B second-to-bottom, and all else bottom. In approval,
then, this would be A or AB)
25: (ego faction; true preferences B>A)
45: C

You are in the ego faction, and deciding whether to vote B>A or just B
(or in approval, BA or B). If there is some combination of votes that
the ego faction can give such that B wins in the case where the 11
votes are B>A, but A wins in the case where the 11 votes are A, then
there is a slippery slope; the ego faction can safely and profitably
use a small amount of offensive strategy, which means that A voters
should use slightly more defensive strategy, and then there's a cycle
of escalation until both factions fall off the cliff and end up
electing C.

Is that clear now?

Jameson,

Much more than it was, thanks.  In the example you give, if the ???
cohort vote A>> B=C then under PAR if the "ego" faction gives Rejects to
A then C will win
and if they give Accepts or Prefers to A then A will win.

But is there a precisely worded criterion about this "slippery slope"
problem?  Is there anything non-arbitrary about the numbers you chose
for your example?

In your example there doesn't seem to be any problem if the method meets
Condorcet  or is IRV.

MJ passes IIA.

I suppose if a losing "irrelevant" candidate is removed and the number
of ballots remain unchanged and no voters react by changing any of their
ratings
of any of the remaining candidates, then I suppose it might (in a
useless and abstract way).

The claim I've seen made that it also meets some version of Majority
involves a bit of goal-post shifting.

Chris Benham

On 11/14/2016 1:48 AM, Jameson Quinn wrote:

2016-11-13 6:34 GMT-05:00 C.Benham <cbenham@adam.com.au
mailto:cbenham@adam.com.au>:

 On 11/13/2016 3:35 AM, Jameson Quinn wrote:
 What I mean is that if you take a non-election-theorist, present
 an election scenario to them, explain who won and why, and ask
 how they would strategize in the place of voter X, they are more
 likely to suggest counterproductive strategies, and less likely
 to see any strategies that actually might work, in Condorcet than
 in Bucklin-like systems.
 The strategy incentives for Condorcet voting methods vary widely. 
 Some have a random-fill incentive while others have a truncation
 incentive. Some have
 a stronger or weaker incentive to equal-top rank than others, and
 some are more vulnerable to Burial than others.

 Smith//Approval has a truncation incentive like Bucklin's, only
 less strong. In addition Bucklin has an equal-top rank/rate
 incentive.  I don't see the problem.

 BTW, why does it matter if "non-election-theorists" when asked
 suggest "counter-productive strategies"? Shouldn't we be
 encouraging sincere voting?
 If they don't want to do that, why can't they just take the
 strategy advice of their favourites?

My concern here is that people will misuse strategy. I think that FBC
and IIA are good guarantees to be able to give, but also that these
guarantees are related to O(N) summability, which is basically saying
"you can think about what's going on in an election, it fits inside
your head." PAR does not have O(N) summability, but it can be done in
2 steps, each of them O(N) summable, and each of them considered
separately meeting FBC and IIA.

 35: C >> A=B
 33: A>B >> C
 32: B>A >> C
 In Smith//approval, one vote alone would shift the above honest
 election; so the fact that it does not in PAR is indeed notable.
 I don't see why.  The example I gave just happened to have a close
 CW.  PAR seems to give an A=B tie unless (as I assume) it breaks
 tied final
 scores in favour of the "leader" (A).
 In particular: in PAR, there is no way for the B voters to
 strategize such that they win the above election, while still
 ensuring that C does not win no matter what the A voters do.
 Of course, that is why it's called a "chicken dilemma".  In what
 method /can/ "the B voters to strategize such that they win the
 above election, while still ensuring that C does not win no matter
 what the A voters do" ??

I think that you still don't understand what I mean by "slippery
slope". (Of course, once you do understand it, you're still free to
disagree that it's important.)

Suppose you have a scenario like the following:
19: A>B
11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a
vote with A top, B second-to-bottom, and all else bottom. In approval,
then, this would be A or AB)
25: (ego faction; true preferences B>A)
45: C

You are in the ego faction, and deciding whether to vote B>A or just B
(or in approval, BA or B). If there is some combination of votes that
the ego faction can give such that B wins in the case where the 11
votes are B>A, but A wins in the case where the 11 votes are A, then
there is a slippery slope; the ego faction can safely and profitably
use a small amount of offensive strategy, which means that A voters
should use slightly more defensive strategy, and then there's a cycle
of escalation until both factions fall off the cliff and end up
electing C.

Is that clear now?

 MJ passes IIA. PAR fails it, as you say, but passes LIIA.
 As do some Condorcet methods. It isn't one of the criteria I care
 much about.

 As I understand it, IIA can only be met by methods that fail
 Majority (like positional methods that pretend that the voters'
 ratings are on some scale independent of the
 candidates).   MJ  is a variety of Median Ratings which is
 normally claimed to meet Majority.

IIA, when applied to a cardinal or categorical method, assumes that
when you remove a candidate, you simply delete that candidate from all
ballots and leave them otherwise unchanged.

The definition of majority used in the proof that IIA and Majority are
incompatible assumes otherwise. Thus, this proof does not apply to
non-ranked methods. Or perhaps one could say: it shows that a method
cannot pass IIA and ranked-majority. MJ does not pass ranked-majority,
but it does pass majority, so that's fine.

MJ does pass IIA.

 I would be a bit surprised if IIA can be met by a method (such as
 MJ and Bucklin) by a method that fails Irrelevant Ballots
 Independence.

 There is some rubbish about Independence of Irrelevant
 Alternatives (IIA) on Electowiki.  I'll address that in a later post.

 Chris Benham



 On 11/13/2016 3:35 AM, Jameson Quinn wrote:
 2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au
 <mailto:cbenham@adam.com.au>>:

     On 11/12/2016 7:53 AM, Jameson Quinn wrote:
     2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au
     <mailto:cbenham@adam.com.au>>:

         On 11/11/2016 10:14 PM, Jameson Quinn wrote:
         I think that simple PAR is close enough to FBC
         compliance to be an acceptable proposal.
         I'm afraid I can't see any value in "close enough" to
         FBC compliance.  The point of FBC is to give an absolute
         guarantee to (possibly uninformed
         and not strategically savvy)  greater-evil fearing voters.


     Yes. The guarantee you can give is "as long as the world is
     somewhere in this restricted domain — that is, essentially,
     as long as there are no Condorcet cycles and each voter
     naturally rejects at least one of the 3 frontrunners — this
     method meets FBC". This is much broader than any guarantee
     you could give for a typical non-FBC method. For instance,
     with IRV, the best you could say would be "as long as your
     favorite is eliminated early or wins overall, you don't have
     to betray them", which unlike PAR's guarantee is not
     something which could ever be generally true about all real
     elections for all factions.
     C: I have in mind voters who are inclined to Compromise, and
     so it's /absolute guarantee/ or it's nothing.  
     Smith//Approval also has a much lower Compromise incentive
     than does IRV  (which in turn has a much much lower
     Compromise incentive then FPP).
         It elects the "correct" winner in a chicken dilemma
         scenario, naive/honest/strategyless ballots, without a
         "slippery slope" (though of course, this is no longer a
         strong Nash equilibrium). 
         How do you have a "chicken dilemma scenario" with
         "naive/honest/strategyless ballots" ?

         35: C >> A=B
         33: A>B >> C
         32: B >> A=C (sincere is B>A >> C)

         In this CD scenario your method elects B  in violation
         of the CD criterion.


     You're suggesting that the sincere preferences are

     35: C >> A=B
     33: A>B >> C
     32: B>A >> C
     C:  I'm not "suggesting". I'm stating.
     If you are 1 of the B>A>>C voters considering whether to
     strategically vote B>>A=C, you have no strong motivation to
     do so, because your vote alone is not enough to shift the
     winner to B. This is what I mean by "no slippery slope".
     C: One "vote alone" is very rarely enough to do anything, so
     I suppose no-one has a "strong motivation" to vote.


 In Smith//approval, one vote alone would shift the above honest
 election; so the fact that it does not in PAR is indeed notable.

 In particular: in PAR, there is no way for the B voters to
 strategize such that they win the above election, while still
 ensuring that C does not win no matter what the A voters do. This
 "safe" strategizing is grease on the slippery slope.
     I believe that in the election you gave, there is no way to
     tell what the sincere preferences are.
     C: From just the information on the ballots, of course not
     (like any election).
     Perhaps the B voters are strategically truncating A; perhaps
     the C voters are strategically truncating B. So the "correct
     winner" could be either A or B, but is almost certainly not C.
     C: By "correct winner" I assume you mean the sincere CW. But
     there is reason to assume there is one. And if the B voters
     are actively Burying C, it could be C.
     The "CD criterion" requires the system to elect C, merely to
     punish the B voters; I think that's perverse, because, among
     other things, it means that a system does badly with center
     squeeze, allowing the C faction to strategize and win.
     C: No, it merely says "not B". But CD + Plurality say that it
     must be C.
         Since you are apparently now content to do without FBC 
         compliance and you imply that electing the CW is a good
         thing,
         why don't you advocate a method that meets the Condorcet
         criterion?

         What is wrong with Smith//Approval?  Or Forest's nearly
         equivalent Max Covered Approval?


     Largely, it's because I think that Condorcet systems are
     strategically counterintuitive, and hard to present results
     in. I think that will lead to more strategy than a system
     like PAR. That's because PAR can make guarantees that
     Condorcet systems can't.
     C: Such as?  What exactly does "strategically
     counter-intuitive" mean? An example?


 What I mean is that if you take a non-election-theorist, present
 an election scenario to them, explain who won and why, and ask
 how they would strategize in the place of voter X, they are more
 likely to suggest counterproductive strategies, and less likely
 to see any strategies that actually might work, in Condorcet than
 in Bucklin-like systems.
     In a system like MJ or Score, you can give a number to each
     candidate, based on their own ratings alone, and the higher
     number wins. That is an easy way to get monotonicity, FBC,
     and IIA.

     In Condorcet, no candidate has any number except in relation
     to all other candidates. That's good for passing the
     Condorcet criterion (obviously) but it breaks FBC and IIA.
     C:  Your method and MJ fail IIA.


 MJ passes IIA. PAR fails it, as you say, but passes LIIA.


 Prefer Accept Reject (PAR) voting works as follows:

  1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks
     count as "Reject" if no rival is explicitly rejected;
     otherwise, blank is "Accept".
  2. *Candidates with at least 25% Prefer, and no more than 50%
     reject, are "viable"*. The most-preferred viable candidate
     (if any) is the leader.
  3. Each "prefer" is worth 1 point. For viable candidates, each
     "accept" on a ballot which doesn't prefer the leader is also
     worth 1 point. *Most points wins.*
On 11/14/2016 1:48 AM, Jameson Quinn wrote: > Suppose you have a scenario like the following: > 19: A>B > 11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a > vote with A top, B second-to-bottom, and all else bottom. In approval, > then, this would be A or AB) > 25: (ego faction; true preferences B>A) > 45: C > > You are in the ego faction, and deciding whether to vote B>A or just B > (or in approval, BA or B). If there is some combination of votes that > the ego faction can give such that B wins in the case where the 11 > votes are B>A, but A wins in the case where the 11 votes are A, then > there is a slippery slope; the ego faction can safely and profitably > use a small amount of offensive strategy, which means that A voters > should use slightly more defensive strategy, and then there's a cycle > of escalation until both factions fall off the cliff and end up > electing C. > > Is that clear now? Jameson, Much more than it was, thanks. In the example you give, if the ??? cohort vote A>> B=C then under PAR if the "ego" faction gives Rejects to A then C will win and if they give Accepts or Prefers to A then A will win. But is there a precisely worded criterion about this "slippery slope" problem? Is there anything non-arbitrary about the numbers you chose for your example? In your example there doesn't seem to be any problem if the method meets Condorcet or is IRV. > MJ passes IIA. I suppose if a losing "irrelevant" candidate is removed and the number of ballots remain unchanged and no voters react by changing any of their ratings of any of the remaining candidates, then I suppose it might (in a useless and abstract way). The claim I've seen made that it also meets some version of Majority involves a bit of goal-post shifting. Chris Benham On 11/14/2016 1:48 AM, Jameson Quinn wrote: > > > 2016-11-13 6:34 GMT-05:00 C.Benham <cbenham@adam.com.au > <mailto:cbenham@adam.com.au>>: > > On 11/13/2016 3:35 AM, Jameson Quinn wrote: > >> What I mean is that if you take a non-election-theorist, present >> an election scenario to them, explain who won and why, and ask >> how they would strategize in the place of voter X, they are more >> likely to suggest counterproductive strategies, and less likely >> to see any strategies that actually might work, in Condorcet than >> in Bucklin-like systems. >> > > The strategy incentives for Condorcet voting methods vary widely. > Some have a random-fill incentive while others have a truncation > incentive. Some have > a stronger or weaker incentive to equal-top rank than others, and > some are more vulnerable to Burial than others. > > Smith//Approval has a truncation incentive like Bucklin's, only > less strong. In addition Bucklin has an equal-top rank/rate > incentive. I don't see the problem. > > BTW, why does it matter if "non-election-theorists" when asked > suggest "counter-productive strategies"? Shouldn't we be > encouraging sincere voting? > If they don't want to do that, why can't they just take the > strategy advice of their favourites? > > > My concern here is that people will misuse strategy. I think that FBC > and IIA are good guarantees to be able to give, but also that these > guarantees are related to O(N) summability, which is basically saying > "you can think about what's going on in an election, it fits inside > your head." PAR does not have O(N) summability, but it can be done in > 2 steps, each of them O(N) summable, and each of them considered > separately meeting FBC and IIA. > > > > 35: C >> A=B > 33: A>B >> C > 32: B>A >> C > >> In Smith//approval, one vote alone would shift the above honest >> election; so the fact that it does not in PAR is indeed notable. > > I don't see why. The example I gave just happened to have a close > CW. PAR seems to give an A=B tie unless (as I assume) it breaks > tied final > scores in favour of the "leader" (A). > >> In particular: in PAR, there is no way for the B voters to >> strategize such that they win the above election, while still >> ensuring that C does not win no matter what the A voters do. > > Of course, that is why it's called a "chicken dilemma". In what > method /can/ "the B voters to strategize such that they win the > above election, while still ensuring that C does not win no matter > what the A voters do" ?? > > > I think that you still don't understand what I mean by "slippery > slope". (Of course, once you do understand it, you're still free to > disagree that it's important.) > > Suppose you have a scenario like the following: > 19: A>B > 11: ??? A or A>B ??? (more generally: either a bullet vote for A, or a > vote with A top, B second-to-bottom, and all else bottom. In approval, > then, this would be A or AB) > 25: (ego faction; true preferences B>A) > 45: C > > You are in the ego faction, and deciding whether to vote B>A or just B > (or in approval, BA or B). If there is some combination of votes that > the ego faction can give such that B wins in the case where the 11 > votes are B>A, but A wins in the case where the 11 votes are A, then > there is a slippery slope; the ego faction can safely and profitably > use a small amount of offensive strategy, which means that A voters > should use slightly more defensive strategy, and then there's a cycle > of escalation until both factions fall off the cliff and end up > electing C. > > Is that clear now? > > >> MJ passes IIA. PAR fails it, as you say, but passes LIIA. > > As do some Condorcet methods. It isn't one of the criteria I care > much about. > > As I understand it, IIA can only be met by methods that fail > Majority (like positional methods that pretend that the voters' > ratings are on some scale independent of the > candidates). MJ is a variety of Median Ratings which is > normally claimed to meet Majority. > > > IIA, when applied to a cardinal or categorical method, assumes that > when you remove a candidate, you simply delete that candidate from all > ballots and leave them otherwise unchanged. > > The definition of majority used in the proof that IIA and Majority are > incompatible assumes otherwise. Thus, this proof does not apply to > non-ranked methods. Or perhaps one could say: it shows that a method > cannot pass IIA and ranked-majority. MJ does not pass ranked-majority, > but it does pass majority, so that's fine. > > MJ does pass IIA. > > > I would be a bit surprised if IIA can be met by a method (such as > MJ and Bucklin) by a method that fails Irrelevant Ballots > Independence. > > There is some rubbish about Independence of Irrelevant > Alternatives (IIA) on Electowiki. I'll address that in a later post. > > Chris Benham > > > > On 11/13/2016 3:35 AM, Jameson Quinn wrote: >> >> >> 2016-11-12 10:45 GMT-05:00 C.Benham <cbenham@adam.com.au >> <mailto:cbenham@adam.com.au>>: >> >> On 11/12/2016 7:53 AM, Jameson Quinn wrote: >>> >>> >>> 2016-11-11 12:50 GMT-05:00 C.Benham <cbenham@adam.com.au >>> <mailto:cbenham@adam.com.au>>: >>> >>> On 11/11/2016 10:14 PM, Jameson Quinn wrote: >>> >>>> I think that simple PAR is close enough to FBC >>>> compliance to be an acceptable proposal. >>> >>> I'm afraid I can't see any value in "close enough" to >>> FBC compliance. The point of FBC is to give an absolute >>> guarantee to (possibly uninformed >>> and not strategically savvy) greater-evil fearing voters. >>> >>> >>> Yes. The guarantee you can give is "as long as the world is >>> somewhere in this restricted domain — that is, essentially, >>> as long as there are no Condorcet cycles and each voter >>> naturally rejects at least one of the 3 frontrunners — this >>> method meets FBC". This is much broader than any guarantee >>> you could give for a typical non-FBC method. For instance, >>> with IRV, the best you could say would be "as long as your >>> favorite is eliminated early or wins overall, you don't have >>> to betray them", which unlike PAR's guarantee is not >>> something which could ever be generally true about all real >>> elections for all factions. >>> >> C: I have in mind voters who are inclined to Compromise, and >> so it's /absolute guarantee/ or it's nothing. >> Smith//Approval also has a much lower Compromise incentive >> than does IRV (which in turn has a much much lower >> Compromise incentive then FPP). >> >> >>> >>> >>> >>>> It elects the "correct" winner in a chicken dilemma >>>> scenario, naive/honest/strategyless ballots, without a >>>> "slippery slope" (though of course, this is no longer a >>>> strong Nash equilibrium). >>> >>> How do you have a "chicken dilemma scenario" with >>> "naive/honest/strategyless ballots" ? >>> >>> 35: C >> A=B >>> 33: A>B >> C >>> 32: B >> A=C (sincere is B>A >> C) >>> >>> In this CD scenario your method elects B in violation >>> of the CD criterion. >>> >>> >>> You're suggesting that the sincere preferences are >>> >>> 35: C >> A=B >>> 33: A>B >> C >>> 32: B>A >> C >>> >>> >> C: I'm not "suggesting". I'm stating. >>> >>> If you are 1 of the B>A>>C voters considering whether to >>> strategically vote B>>A=C, you have no strong motivation to >>> do so, because your vote alone is not enough to shift the >>> winner to B. This is what I mean by "no slippery slope". >>> >>> >> C: One "vote alone" is very rarely enough to do anything, so >> I suppose no-one has a "strong motivation" to vote. >> >> >> In Smith//approval, one vote alone would shift the above honest >> election; so the fact that it does not in PAR is indeed notable. >> >> In particular: in PAR, there is no way for the B voters to >> strategize such that they win the above election, while still >> ensuring that C does not win no matter what the A voters do. This >> "safe" strategizing is grease on the slippery slope. >> >> >>> >>> >>> I believe that in the election you gave, there is no way to >>> tell what the sincere preferences are. >>> >>> >> >> C: From just the information on the ballots, of course not >> (like any election). >>> >>> Perhaps the B voters are strategically truncating A; perhaps >>> the C voters are strategically truncating B. So the "correct >>> winner" could be either A or B, but is almost certainly not C. >> >> C: By "correct winner" I assume you mean the sincere CW. But >> there is reason to assume there is one. And if the B voters >> are actively Burying C, it could be C. >> >>> The "CD criterion" requires the system to elect C, merely to >>> punish the B voters; I think that's perverse, because, among >>> other things, it means that a system does badly with center >>> squeeze, allowing the C faction to strategize and win. >>> >> C: No, it merely says "not B". But CD + Plurality say that it >> must be C. >>> >>> >>> Since you are apparently now content to do without FBC >>> compliance and you imply that electing the CW is a good >>> thing, >>> why don't you advocate a method that meets the Condorcet >>> criterion? >>> >>> What is wrong with Smith//Approval? Or Forest's nearly >>> equivalent Max Covered Approval? >>> >>> >>> Largely, it's because I think that Condorcet systems are >>> strategically counterintuitive, and hard to present results >>> in. I think that will lead to more strategy than a system >>> like PAR. That's because PAR can make guarantees that >>> Condorcet systems can't. >>> >> C: Such as? What exactly does "strategically >> counter-intuitive" mean? An example? >> >> >> What I mean is that if you take a non-election-theorist, present >> an election scenario to them, explain who won and why, and ask >> how they would strategize in the place of voter X, they are more >> likely to suggest counterproductive strategies, and less likely >> to see any strategies that actually might work, in Condorcet than >> in Bucklin-like systems. >> >> >>> >>> In a system like MJ or Score, you can give a number to each >>> candidate, based on their own ratings alone, and the higher >>> number wins. That is an easy way to get monotonicity, FBC, >>> and IIA. >>> >>> In Condorcet, no candidate has any number except in relation >>> to all other candidates. That's good for passing the >>> Condorcet criterion (obviously) but it breaks FBC and IIA. >>> >> C: Your method and MJ fail IIA. >> >> >> MJ passes IIA. PAR fails it, as you say, but passes LIIA. >> >> >> Prefer Accept Reject (PAR) voting works as follows: >> >> 1. *Voters can Prefer, Accept, or Reject each candidate.* Blanks >> count as "Reject" if no rival is explicitly rejected; >> otherwise, blank is "Accept". >> 2. *Candidates with at least 25% Prefer, and no more than 50% >> reject, are "viable"*. The most-preferred viable candidate >> (if any) is the leader. >> 3. Each "prefer" is worth 1 point. For viable candidates, each >> "accept" on a ballot which doesn't prefer the leader is also >> worth 1 point. *Most points wins.* >> > >