Number Votes - 10 April 2016 1. Use Number Votes (1, 2, 3, etc.) for each choice. A Voter MUST put a number vote for ALL choices. 2. Vote YES or NO for each choice. 3. Ballot Form - Numbered Boxes 1 2 3 etc. (i.e. total choices) YES/NO Boxes  Name 4. Do Head to Head combinations math (would require computer voting in any large election). Test Winner(s) (TW) -- Test Loser (TL) -- Test Others (TO) Each TO 2nd or later choice vote goes to a TW or TL. 5. If a TW wins in all combinations, then it wins. 6. If a TW loses in all combinations, then it loses (and repeat step 5). 7. Tiebreaker - If no TW, then add 1st plus 2nd plus etc. choices to get a Droop Quota (majority for 1 seat winner).  If 2 or more get a Droop Quota, then any other non-Droop Quota choices lose (and repeat step 5). 8. OR -- have the lowest YES choice lose (and repeat step 5). ----- Legislative bodies - each final winner would have a voting power equal to the final votes received. For multiple executive/judicial offices (e.g. elect 3 judges) the N highest Number Votes count - for TO transfer purposes. ---- Theory - Condorcet in France in the 1780s (repeat 1780s) noted that a third choice could beat two existing choices head to head -- A beats B C comes along. C beats A and C beats B. --- Divided majority example - 26 AB 25 BA 49 Z The Z voters (i.e. all voters) would be required to make number votes for ALL choices. i.e. example might result in -- 26 ABZ 25 BAZ 26 ZBA 23 ZAB Z is beat by both A and B and thus loses. 51 B beats 49 A. ----- Possible circular tie - 34 ABC 33 BCA 32 CAB 99 Adding 1st plus 2nd votes - 34 + 32 = 66 A 33 + 34 = 67 B 32 + 33 = 65 C  Loses. 66 A beats 33 B. OR use Approval Votes - Lowest would lose. One of the two remaining would win. Note -  Number Votes are *relative* only. Approval Votes are *absolute* only.